Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 7, Problem 101A

(a)

Interpretation Introduction

Interpretation: The given measurement is to be rounded to the number of significant figures indicated in each parenthesis.

Concept Introduction : The number of digits that contributes to the degree of accuracy of the measurement is known as significant figures. It shows the precision of the measurement.

(a)

Expert Solution
Check Mark

Answer to Problem 101A

The round-off measurement is 55.6 g.

Explanation of Solution

The given measurement is 56.55 g. It should be rounded off into 3 significant figures. Therefore, it is rounded off as 56.6 g (After the decimal, the digit at the tenth place is greater than 5 so 1 is added to the 5 and it becomes 6 at one’s place).

(b)

Interpretation Introduction

Interpretation: The given measurement is to be rounded to the number of significant figures indicated in each parenthesis.

Concept Introduction : The number of digits that contributes to the degree of accuracy of the measurement is known as significant figures. It shows the precision of the measurement.

(b)

Expert Solution
Check Mark

Answer to Problem 101A

The round-off measurement is 4.8×10−3 m .

Explanation of Solution

The given measurement is 0.004849 m. It should be rounded off into 2 significant figures. The decimal is shifted toward the right and the power of 10 is equal to the number of decimal shifted places (negative).

Therefore, it is rounded off as 4.8×10−3 m .

(c)

Interpretation Introduction

Interpretation: The given measurement is to be rounded to the number of significant figures indicated in each parenthesis.

Concept Introduction : The number of digits that contributes to the degree of accuracy of the measurement is known as significant figures. It shows the precision of the measurement.

(c)

Expert Solution
Check Mark

Answer to Problem 101A

The rounded-off measurement is 1.81 L.

Explanation of Solution

The given measurement is 1.8072 L. It should be rounded off into 3 significant figures. After the decimal, the digit at the hundredth place is greater than 5 so 1 is added to the 0 and it becomes 1 at tenth place).

Therefore, it is rounded off as 1.81 L.

(d)

Interpretation Introduction

Interpretation: The given measurement is to be rounded to the number of significant figures indicated in each parenthesis.

Concept Introduction : The number of digits that contributes to the degree of accuracy of the measurement is known as significant figures. It shows the precision of the measurement.

(d)

Expert Solution
Check Mark

Answer to Problem 101A

The rounded-off measurement is 4.0×103 mg .

Explanation of Solution

The given measurement is 4.007×103 mg . It should be rounded off into 3 significant figures. Therefore, it is rounded off as 4.0×103 mg .

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Chapter 7, Problem 100A
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Chapter 7, Problem 102A

Chapter 7 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 7.1 - Prob. 1LCCh. 7.1 - Prob. 2LCCh. 7.1 - Prob. 3LCCh. 7.1 - Prob. 4LCCh. 7.1 - Prob. 5LCCh. 7.1 - Prob. 6LCCh. 7.1 - Prob. 7LCCh. 7.1 - Prob. 8LCCh. 7.1 - Prob. 9LCCh. 7.2 - Prob. 10SP
Ch. 7.2 - Prob. 11SPCh. 7.2 - Prob. 12LCCh. 7.2 - Prob. 13LCCh. 7.2 - Prob. 14LCCh. 7.2 - Prob. 15LCCh. 7.2 - Prob. 16LCCh. 7.2 - Prob. 17LCCh. 7.2 - Prob. 18LCCh. 7.2 - Prob. 19LCCh. 7.3 - Prob. 20LCCh. 7.3 - Prob. 21LCCh. 7.3 - Prob. 22LCCh. 7.3 - Prob. 23LCCh. 7.3 - Prob. 24LCCh. 7.3 - Prob. 25LCCh. 7.3 - Prob. 26LCCh. 7 - Prob. 27ACh. 7 - Prob. 28ACh. 7 - Prob. 29ACh. 7 - Prob. 30ACh. 7 - Prob. 31ACh. 7 - Prob. 32ACh. 7 - Prob. 33ACh. 7 - Prob. 34ACh. 7 - Prob. 35ACh. 7 - Prob. 36ACh. 7 - Prob. 37ACh. 7 - Prob. 38ACh. 7 - Prob. 39ACh. 7 - Prob. 40ACh. 7 - Prob. 41ACh. 7 - Prob. 42ACh. 7 - Prob. 43ACh. 7 - Prob. 44ACh. 7 - Prob. 45ACh. 7 - Prob. 46ACh. 7 - Prob. 47ACh. 7 - Prob. 48ACh. 7 - Prob. 49ACh. 7 - Prob. 50ACh. 7 - Prob. 51ACh. 7 - Prob. 52ACh. 7 - Prob. 53ACh. 7 - Prob. 54ACh. 7 - Prob. 55ACh. 7 - Prob. 56ACh. 7 - Prob. 57ACh. 7 - Prob. 58ACh. 7 - Prob. 59ACh. 7 - Prob. 60ACh. 7 - Prob. 61ACh. 7 - Prob. 62ACh. 7 - Prob. 63ACh. 7 - Prob. 64ACh. 7 - Prob. 65ACh. 7 - Prob. 66ACh. 7 - Prob. 67ACh. 7 - Prob. 68ACh. 7 - Prob. 69ACh. 7 - Prob. 70ACh. 7 - Prob. 71ACh. 7 - Prob. 72ACh. 7 - Prob. 73ACh. 7 - Prob. 74ACh. 7 - Prob. 75ACh. 7 - Prob. 76ACh. 7 - Prob. 77ACh. 7 - Prob. 78ACh. 7 - Prob. 79ACh. 7 - Prob. 80ACh. 7 - Prob. 81ACh. 7 - Prob. 82ACh. 7 - Prob. 83ACh. 7 - Prob. 84ACh. 7 - Prob. 85ACh. 7 - Prob. 86ACh. 7 - Prob. 87ACh. 7 - Prob. 88ACh. 7 - Prob. 89ACh. 7 - Prob. 90ACh. 7 - Prob. 91ACh. 7 - Prob. 92ACh. 7 - Prob. 93ACh. 7 - Prob. 94ACh. 7 - Prob. 95ACh. 7 - Prob. 96ACh. 7 - Prob. 97ACh. 7 - Prob. 98ACh. 7 - Prob. 99ACh. 7 - Prob. 100ACh. 7 - Prob. 101ACh. 7 - Prob. 102ACh. 7 - Prob. 103ACh. 7 - Prob. 104ACh. 7 - Prob. 105ACh. 7 - Prob. 106ACh. 7 - Prob. 107ACh. 7 - Prob. 108ACh. 7 - Prob. 109ACh. 7 - Prob. 110ACh. 7 - Prob. 111ACh. 7 - Prob. 112ACh. 7 - Prob. 113ACh. 7 - Prob. 114ACh. 7 - Prob. 1STPCh. 7 - Prob. 2STPCh. 7 - Prob. 3STPCh. 7 - Prob. 4STPCh. 7 - Prob. 5STPCh. 7 - Prob. 6STPCh. 7 - Prob. 7STPCh. 7 - Prob. 8STPCh. 7 - Prob. 9STPCh. 7 - Prob. 10STPCh. 7 - Prob. 11STPCh. 7 - Prob. 12STP
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