Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 7, Problem 34A

(a)

Interpretation Introduction

Interpretation: The number of electrons gained by nitrogen atom to get a stable electron configuration needs to be determined.

Concept Introduction: A stable electron configuration has a complete octet. To achieve a stable electron configuration, an atom of an element can gain or lose electron/s. The number of electrons lost or gained by an atom is the charge on that atom.

(a)

Expert Solution
Check Mark

Answer to Problem 34A

The number of electrons gained by a nitrogen atom is 3.

Explanation of Solution

The atomic number of nitrogen element is 7. The electronic configuration of N is as follows:

  N(7)=1s22s22p3

Thus, it has 5 valance electrons. To achieve a stable electron configuration or to complete an octet, nitrogen can gain 3 electrons.

Thus, the number of electrons gained by a nitrogen atom is 3.

(b)

Interpretation Introduction

Interpretation: The number of electrons gained by sulphur atoms to get a stable electron configuration needs to be determined.

Concept Introduction: A stable electron configuration has a complete octet. To achieve a stable electron configuration, an atom of an element can gain or lose electron/s. The number of electrons lost or gained by an atom is the charge on that atom.

(b)

Expert Solution
Check Mark

Answer to Problem 34A

The number of electrons gained by a sulphur atom is 2.

Explanation of Solution

The atomic number of sulphur element is 16. The electronic configuration of S is as follows:

  S(16)=1s22s22p63s23p4

Thus, it has 6 valance electrons. To achieve a stable electron configuration or to complete an octet, sulphur can gain 2 electrons.

Thus, the number of electrons gained by a sulphur atom is 2.

(c)

Interpretation Introduction

Interpretation: The number of electrons gained by chlorine atom to get a stable electron configuration needs to be determined.

Concept Introduction: A stable electron configuration has a complete octet. To achieve a stable electron configuration, an atom of an element can gain or lose electron/s. The number of electrons lost or gained by an atom is the charge on that atom.

(c)

Expert Solution
Check Mark

Answer to Problem 34A

The number of electrons gained by a chlorine atom is 1.

Explanation of Solution

The atomic number of the chlorine element is 17. The electronic configuration of Cl is as follows:

  Cl(17)=1s22s22p63s23p5

Thus, it has 7 valance electrons. To achieve a stable electron configuration or to complete an octet, chlorine can gain 1 electron.

Thus, the number of electrons gained by a chlorine atom is 1.

(d)

Interpretation Introduction

Interpretation: The number of electrons gained by phosphorus atom to get a stable electron configuration needs to be determined.

Concept Introduction: A stable electron configuration has a complete octet. To achieve a stable electron configuration, an atom of an element can gain or lose electron/s. The number of electrons lost or gained by an atom is the charge on that atom.

(d)

Expert Solution
Check Mark

Answer to Problem 34A

The number of electrons gained by a phosphorus atom is 3.

Explanation of Solution

The atomic number of phosphorus element is 15. The electronic configuration of P is as follows:

  P(15)=1s22s22p63s23p3

Thus, it has 5 valance electrons. To achieve a stable electron configuration or to complete an octet, phosphorus can gain 3 electrons.

Thus, the number of electrons gained by a phosphorus atom is 3.

Chapter 7 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 7.2 - Prob. 11SPCh. 7.2 - Prob. 12LCCh. 7.2 - Prob. 13LCCh. 7.2 - Prob. 14LCCh. 7.2 - Prob. 15LCCh. 7.2 - Prob. 16LCCh. 7.2 - Prob. 17LCCh. 7.2 - Prob. 18LCCh. 7.2 - Prob. 19LCCh. 7.3 - Prob. 20LCCh. 7.3 - Prob. 21LCCh. 7.3 - Prob. 22LCCh. 7.3 - Prob. 23LCCh. 7.3 - Prob. 24LCCh. 7.3 - Prob. 25LCCh. 7.3 - Prob. 26LCCh. 7 - Prob. 27ACh. 7 - Prob. 28ACh. 7 - Prob. 29ACh. 7 - Prob. 30ACh. 7 - Prob. 31ACh. 7 - Prob. 32ACh. 7 - Prob. 33ACh. 7 - Prob. 34ACh. 7 - Prob. 35ACh. 7 - Prob. 36ACh. 7 - Prob. 37ACh. 7 - Prob. 38ACh. 7 - Prob. 39ACh. 7 - Prob. 40ACh. 7 - Prob. 41ACh. 7 - Prob. 42ACh. 7 - Prob. 43ACh. 7 - Prob. 44ACh. 7 - Prob. 45ACh. 7 - Prob. 46ACh. 7 - Prob. 47ACh. 7 - Prob. 48ACh. 7 - Prob. 49ACh. 7 - Prob. 50ACh. 7 - Prob. 51ACh. 7 - Prob. 52ACh. 7 - Prob. 53ACh. 7 - Prob. 54ACh. 7 - Prob. 55ACh. 7 - Prob. 56ACh. 7 - Prob. 57ACh. 7 - Prob. 58ACh. 7 - Prob. 59ACh. 7 - Prob. 60ACh. 7 - Prob. 61ACh. 7 - Prob. 62ACh. 7 - Prob. 63ACh. 7 - Prob. 64ACh. 7 - Prob. 65ACh. 7 - Prob. 66ACh. 7 - Prob. 67ACh. 7 - Prob. 68ACh. 7 - Prob. 69ACh. 7 - Prob. 70ACh. 7 - Prob. 71ACh. 7 - Prob. 72ACh. 7 - Prob. 73ACh. 7 - Prob. 74ACh. 7 - Prob. 75ACh. 7 - Prob. 76ACh. 7 - Prob. 77ACh. 7 - Prob. 78ACh. 7 - Prob. 79ACh. 7 - Prob. 80ACh. 7 - Prob. 81ACh. 7 - Prob. 82ACh. 7 - Prob. 83ACh. 7 - Prob. 84ACh. 7 - Prob. 85ACh. 7 - Prob. 86ACh. 7 - Prob. 87ACh. 7 - Prob. 88ACh. 7 - Prob. 89ACh. 7 - Prob. 90ACh. 7 - Prob. 91ACh. 7 - Prob. 92ACh. 7 - Prob. 93ACh. 7 - Prob. 94ACh. 7 - Prob. 95ACh. 7 - Prob. 96ACh. 7 - Prob. 97ACh. 7 - Prob. 98ACh. 7 - Prob. 99ACh. 7 - Prob. 100ACh. 7 - Prob. 101ACh. 7 - Prob. 102ACh. 7 - Prob. 103ACh. 7 - Prob. 104ACh. 7 - Prob. 105ACh. 7 - Prob. 106ACh. 7 - Prob. 107ACh. 7 - Prob. 108ACh. 7 - Prob. 109ACh. 7 - Prob. 110ACh. 7 - Prob. 111ACh. 7 - Prob. 112ACh. 7 - Prob. 113ACh. 7 - Prob. 114ACh. 7 - Prob. 1STPCh. 7 - Prob. 2STPCh. 7 - Prob. 3STPCh. 7 - Prob. 4STPCh. 7 - Prob. 5STPCh. 7 - Prob. 6STPCh. 7 - Prob. 7STPCh. 7 - Prob. 8STPCh. 7 - Prob. 9STPCh. 7 - Prob. 10STPCh. 7 - Prob. 11STPCh. 7 - Prob. 12STP
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