Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 7, Problem 53A

(a)

Interpretation Introduction

Interpretation: The electron dot structure for the C element needs to be determined.

Concept Introduction: Electron dot structures of an atom of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, the symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.

For example, the number of valance electrons in a bromine atom is 7; thus, its electron dot structure is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  1

(a)

Expert Solution
Check Mark

Explanation of Solution

The given element is C. It belongs to group 14. The atomic number of carbon atoms is 6. The electronic configuration can be represented as follows:

  1s22s22p2

Here, the number of valence electrons will be 4. Thus, the electron dot structure can be written as follows:

(b)

Interpretation Introduction

Interpretation: The electron dot structure for Be element needs to be determined.

Concept Introduction: Electron dot structures of an atom of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, the symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.

For example, the number of valance electrons in a bromine atom is 7; thus, its electron dot structure is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  2

(b)

Expert Solution
Check Mark

Explanation of Solution

The given element is Be. It belongs to group 2. The atomic number of Be atom is 4. The electronic configuration can be represented as follows:

  1s22s2

Here, the number of valence electrons will be 2. Thus, the electron dot structure can be written as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  3

(c)

Interpretation Introduction

Interpretation: The electron dot structure for O element needs to be determined.

Concept Introduction: Electron dot structures of an atom of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, the symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.

For example, the number of valance electrons in a bromine atom is 7; thus, its electron dot structure is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  4

(c)

Expert Solution
Check Mark

Explanation of Solution

The given element is O. It belongs to group 16. The atomic number of oxygen atom is 8. The electronic configuration can be represented as follows:

  1s22s22p4

Here, the number of valence electrons will be 6. Thus, the electron dot structure can be written as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  5

(d)

Interpretation Introduction

Interpretation: The electron dot structure for the F element needs to be determined.

Concept Introduction: Electron dot structures of an atom of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, the symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.

For example, the number of valance electrons in a bromine atom is 7; thus, its electron dot structure is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  6

(d)

Expert Solution
Check Mark

Explanation of Solution

The given element is F. It belongs to group 17. The atomic number of F atom is 9. The electronic configuration can be represented as follows:

  1s22s22p5

Here, the number of valence electrons will be 7. Thus, the electron dot structure can be written as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  7

(e)

Interpretation Introduction

Interpretation: The electron dot structure for Na element needs to be determined.

Concept Introduction: Electron dot structures of an atom of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, the symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.

For example, the number of valance electrons in a bromine atom is 7; thus, its electron dot structure is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  8

(e)

Expert Solution
Check Mark

Explanation of Solution

The given element is Na. It belongs to group 1. The atomic number of sodium atom is 11. The electronic configuration can be represented as follows:

  1s22s22p63s1

Here, the number of valence electrons will be 1. Thus, the electron dot structure can be written as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  9

(f)

Interpretation Introduction

Interpretation: The electron dot structure for P element needs to be determined.

Concept Introduction: Electron dot structures of an atom of an element represent the number of electron/s present in its valance electron shell. In the electron dot structure, the symbol of an atom of an element is written and the number of valance electrons is arranged in pairs represented as dots around the symbol.

For example, the number of valance electrons in a bromine atom is 7; thus, its electron dot structure is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  10

(f)

Expert Solution
Check Mark

Explanation of Solution

The given element is P. It belongs to group 15. The atomic number of phosphorus atom is 15. The electronic configuration can be represented as follows:

  1s22s22p63s23p3

Here, the number of valence electrons will be 5. Thus, the electron dot structure can be written as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 7, Problem 53A , additional homework tip  11

Chapter 7 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 7.2 - Prob. 11SPCh. 7.2 - Prob. 12LCCh. 7.2 - Prob. 13LCCh. 7.2 - Prob. 14LCCh. 7.2 - Prob. 15LCCh. 7.2 - Prob. 16LCCh. 7.2 - Prob. 17LCCh. 7.2 - Prob. 18LCCh. 7.2 - Prob. 19LCCh. 7.3 - Prob. 20LCCh. 7.3 - Prob. 21LCCh. 7.3 - Prob. 22LCCh. 7.3 - Prob. 23LCCh. 7.3 - Prob. 24LCCh. 7.3 - Prob. 25LCCh. 7.3 - Prob. 26LCCh. 7 - Prob. 27ACh. 7 - Prob. 28ACh. 7 - Prob. 29ACh. 7 - Prob. 30ACh. 7 - Prob. 31ACh. 7 - Prob. 32ACh. 7 - Prob. 33ACh. 7 - Prob. 34ACh. 7 - Prob. 35ACh. 7 - Prob. 36ACh. 7 - Prob. 37ACh. 7 - Prob. 38ACh. 7 - Prob. 39ACh. 7 - Prob. 40ACh. 7 - Prob. 41ACh. 7 - Prob. 42ACh. 7 - Prob. 43ACh. 7 - Prob. 44ACh. 7 - Prob. 45ACh. 7 - Prob. 46ACh. 7 - Prob. 47ACh. 7 - Prob. 48ACh. 7 - Prob. 49ACh. 7 - Prob. 50ACh. 7 - Prob. 51ACh. 7 - Prob. 52ACh. 7 - Prob. 53ACh. 7 - Prob. 54ACh. 7 - Prob. 55ACh. 7 - Prob. 56ACh. 7 - Prob. 57ACh. 7 - Prob. 58ACh. 7 - Prob. 59ACh. 7 - Prob. 60ACh. 7 - Prob. 61ACh. 7 - Prob. 62ACh. 7 - Prob. 63ACh. 7 - Prob. 64ACh. 7 - Prob. 65ACh. 7 - Prob. 66ACh. 7 - Prob. 67ACh. 7 - Prob. 68ACh. 7 - Prob. 69ACh. 7 - Prob. 70ACh. 7 - Prob. 71ACh. 7 - Prob. 72ACh. 7 - Prob. 73ACh. 7 - Prob. 74ACh. 7 - Prob. 75ACh. 7 - Prob. 76ACh. 7 - Prob. 77ACh. 7 - Prob. 78ACh. 7 - Prob. 79ACh. 7 - Prob. 80ACh. 7 - Prob. 81ACh. 7 - Prob. 82ACh. 7 - Prob. 83ACh. 7 - Prob. 84ACh. 7 - Prob. 85ACh. 7 - Prob. 86ACh. 7 - Prob. 87ACh. 7 - Prob. 88ACh. 7 - Prob. 89ACh. 7 - Prob. 90ACh. 7 - Prob. 91ACh. 7 - Prob. 92ACh. 7 - Prob. 93ACh. 7 - Prob. 94ACh. 7 - Prob. 95ACh. 7 - Prob. 96ACh. 7 - Prob. 97ACh. 7 - Prob. 98ACh. 7 - Prob. 99ACh. 7 - Prob. 100ACh. 7 - Prob. 101ACh. 7 - Prob. 102ACh. 7 - Prob. 103ACh. 7 - Prob. 104ACh. 7 - Prob. 105ACh. 7 - Prob. 106ACh. 7 - Prob. 107ACh. 7 - Prob. 108ACh. 7 - Prob. 109ACh. 7 - Prob. 110ACh. 7 - Prob. 111ACh. 7 - Prob. 112ACh. 7 - Prob. 113ACh. 7 - Prob. 114ACh. 7 - Prob. 1STPCh. 7 - Prob. 2STPCh. 7 - Prob. 3STPCh. 7 - Prob. 4STPCh. 7 - Prob. 5STPCh. 7 - Prob. 6STPCh. 7 - Prob. 7STPCh. 7 - Prob. 8STPCh. 7 - Prob. 9STPCh. 7 - Prob. 10STPCh. 7 - Prob. 11STPCh. 7 - Prob. 12STP
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