(a)
Interpretation:
The products for the given reactions should be determined.
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds that results in bond formation.
Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
The curved arrows are generally used to indicate the flow of electrons present in the reaction.
Addition Reaction: It is defined as chemical reaction in which two given molecules combines and forms product. The types of addition reactions are electrophilic addition, nucleophilic addition, free radical additions and cycloadditions. Generally, compounds with carbon-hetero atom bonds favors addition reaction.
In addition reaction of
Oxidation Reaction: It involves loss of electrons, addition of oxygen atoms or removal of hydrogen atoms.
Oxidizing Reagents: The chemical agents used to add oxygen or remove hydrogen to other compound which finally reduced on oxidizing the other compound.
Carbocation: It is carbon ion that bears a positive charge on it.
Carbocation stability order:
(b)
Interpretation:
From the given two reactions the one with higher free energy activation should be determined.
Concept introduction:
Carbocation: it is carbon ion that bears a positive charge on it.
Carbocation stability order:
Free energy activation is the energy difference between the transition state and the ground state of the reactants present in a reaction.
Transition State: The state which defines the highest potential energy with respect to reaction co-ordinate between reactant and product. It is usually denoted by using the symbol ‘≠’.
(c)
Interpretation:
The reactivity for given set of compounds towards
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
In E-Z designations, the groups attached to vinylic positions are checked by their priority on the basis of higher molecular weight. If the higher priority groups are on the same sides, then the configuration is designated as Z. If the higher priority groups are on the opposite sides, then the configuration is designated as E.
Carbocation: it is carbon ion that bears a positive charge on it.
Carbocation stability order:
Want to see the full answer?
Check out a sample textbook solutionChapter 6 Solutions
Essential Organic Chemistry, Global Edition
- Draw the structures of the products obtained from the reaction of each enantiomer of cis-1-chloro-2-isopropylcyclopentane with sodium methoxide in methanol. b. Are all the products optically active? c. How would the products differ if the starting material were the trans isomer? Are these products optically active? d. Will the cis enantiomers or the trans enantiomers form substitution products more rapidly? e. Will the cis enantiomers or the trans enantiomers form elimination products more rapidly?arrow_forwardWhich stereoisomer would be produced from the reaction of trans-2-butene with OsO4 followed by H2O2? A. 2S,3S- diol and 2R, 3R-diol B. 2S,3R-diol and 2R,3S-diol C. 2S,3S-diol only D. 2R, 3R-diol only E. 2S,3R-diol onlyarrow_forwardCyclohexene (an alkene) is mixed with potassium permanagnate solution (KMnO4). What do you expect to observe? A. The mixture will turn purple as the permanganate is reduced by the alkene. B. The purple colour will disappear as the permanganate is reduced by the alkene. C. Nothing. Permanganate does not react with alkenes. D. The purple colour will disappear as the permanganate is oxidised by the alkene.arrow_forward
- Draw the products obtained from the reaction of one equivalent of HBr with one equivalent of 1,3,5-hexatriene. a. Which product(s) will predominate if the reaction is under kinetic control? b. Which product(s) will predominate if the reaction is under thermodynamic control?arrow_forwardSelect the best reagent expected to convert 3-heptyne to cis-3-heptene. A. NaNH2, NH3 B. Na, NH3 C. H2, Lindlar’s catalyst D. Both A and C E. Both B and Carrow_forward7. Ozonolysis of compound A yields pentane-2,4-dione. What is the structure of compound A? a OH OH H Compound A C10H16 H₂SO4 1.03 2) (CH3)2S Draw the structures of the two possible cyclization products. pentane-2,4-dionearrow_forward
- Draw the products of the following reactions. If the products can exist as stereoisomers show what stereoisomers are formed. a. cis-2-pentene + Br2/CH2Cl2 b. trans-2-pentene + Br2/CH2Cl2 c. 1- butene + HCl d. methylcyclohexene + HBr e. trans-3-hexene + Br2/CH2Cl2 f. cis-3-hexene + Br2/CH2Cl2 g. 3,3-dimethyl-1-pentene + HBr h. cis-2-butene + HBr i. (Z)-2,3-dichloro-2-butene + H2, Pd/C j. (E)-2,3-dichloro-2-butene + H2, Pd/C k. (Z)-3,4-dimethyl-3-hexene + H2, Pd/C l. (E)-3,4-dimethyl-3-hexene + H2, Pd/Carrow_forwarda. How many alkenes could you treat with H2, Pd/C to prepare methylcyclopentane? b. Which of the alkenes is the most stable? c. Which of the alkenes has the smallest heat of hydrogenation?arrow_forwardSubstitution and Elimination (Please draw the structures involved in the reactions) A. Which will react more rapidly via SN1? 1-bromo-2,2-dimethylpropane or 2-bromo-2- methylbutane? Explain. B. Which will react faster via SN2? 1-chlorocyclohexane or 1-chloro-1-methylcyclohexane? Explain.arrow_forward
- 4. Draw the structure of the four allylic halides formed when 3-methylcyclohexene undergoes allylic halogenation with NBS + hv. CH3 Allylic Brominationarrow_forwardDraw the organic products formed when cyclopentene is treated with each reagent. With some reagents, no reaction occurs. a.H2 + Pd-C b.H2 + Lindlar catalyst c.Na, NH3 d.CH3CO3H e.[1] CH3CO3H; [2] H2O, HO− f.[1]OsO4 + NMO; [2] NaHSO3, H2O g.KMnO4, H2O, HO− h.[1] LiAlH4; [2] H2O i. [1] O3; [2] CH3SCH3 j.(CH3)3COOH, Ti[OCH(CH3)2]4, (−)-DET k.mCPBA l.Product in (k); then [1] LiAlH4; [2] H2Oarrow_forwardDraw the major organic product formed by reaction of 2-hexyne with the following reagent: H₂O in H₂SO4 / HgSO4. • Consider E/Z stereochemistry of alkenes. • In cases where there is more than one answer, just draw one. • If no reaction occurs, draw the organic starting material.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY