Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 4, Problem 8CONQ
The blood serum from one individual (let’s call this person individual 1) is known to agglutinate the red blood cells from a second individual (individual 2). List the pairwise combinations of possible genotypes that individuals 1 and 2 could have. If individual 1 is the parent of individual 2, what are his or her possible genotypes?
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The blood serum from one individual (let’s call this person individual 1) is known to agglutinate the red blood cells from a secondindividual (individual 2). List the pairwise combinations of possible genotypes that individuals 1 and 2 could have. If individual 1is the parent of individual 2, what are his or her possiblegenotypes?
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Explain with diagrams.
Chapter 4 Solutions
Genetics: Analysis and Principles
Ch. 4.1 - 1. Which of the following statements is true?
a....Ch. 4.2 - 1. Which of the following is not an example of a...Ch. 4.2 - Prob. 2COMQCh. 4.2 - 3. Polydactyly is a condition in which a person...Ch. 4.3 - The outcome of an individuals traits is controlled...Ch. 4.4 - Prob. 1COMQCh. 4.4 - Prob. 2COMQCh. 4.5 - Prob. 1COMQCh. 4.5 - Hemophilia is a blood-clotting disorder in humans...Ch. 4.6 - Prob. 1COMQ
Ch. 4.7 - 1. The Manx phenotype in cats is caused by a...Ch. 4.8 - Which of the following is a possible explanation...Ch. 4.9 - 1. Two different strains of sweet peas are...Ch. 4.9 - If the F1 offspring from question 1 are allowed to...Ch. 4 - 1. Describe the differences among dominance,...Ch. 4 - Discuss the differences among sex-influenced,...Ch. 4 - 3. What is meant by a gene interaction? How can a...Ch. 4 - Lets suppose a recessive allele encodes a...Ch. 4 - 5. A nectarine is a peach without the fuzz. The...Ch. 4 - 6. An allele in Drosophila produces a star-eye...Ch. 4 - A seed dealer wants to sell four-oclock seeds that...Ch. 4 - 8. The blood serum from one individual (let’s call...Ch. 4 - 9. Which blood type phenotypes (A, B, AB, and/or...Ch. 4 - A woman with type B blood has a child with type O...Ch. 4 - A type A woman is the daughter of a type O father...Ch. 4 - In Shorthorn cattle, coat color is controlled by a...Ch. 4 - In chickens, the Leghorn variety has white...Ch. 4 - Propose the most likely mode of inheritance...Ch. 4 - 15. A human disease known as vitamin D-resistant...Ch. 4 - 16. Hemophilia is an X-linked recessive trait in...Ch. 4 - 17. Incontinentia pigmenti, a rare, X-linked...Ch. 4 - 18. Scurs in cattle is a sex-influenced trait. A...Ch. 4 - In rabbits, the color of body fat is controlled by...Ch. 4 - Prob. 20CONQCh. 4 - 21. The trait of feathering in fowls is a...Ch. 4 - Based on the pedigree shown here for a trait...Ch. 4 - 23. The pedigree shown here involves a trait...Ch. 4 - Lets suppose you have pedigree data from thousands...Ch. 4 - Prob. 25CONQCh. 4 - 26. In humans, a very rare dominant allele that...Ch. 4 - 27. A sex-influenced trait in humans affects the...Ch. 4 - Three coat-color patterns that occur in some...Ch. 4 - Prob. 1EQCh. 4 - 2. In chickens, some varieties have feathered...Ch. 4 - 3. In sheep, the formation of horns is a...Ch. 4 - Prob. 4EQCh. 4 - In the clover butterfly, males are always yellow,...Ch. 4 - The Mic2 gene in humans is present on both the X...Ch. 4 - 7. Duroc Jersey pigs are typically red, but a...Ch. 4 - 8. As shown in Figure 4.17, coat color in rodents...Ch. 4 - 9. Summer squash exist in long, spherical, or disk...Ch. 4 - In a species of plant, two genes control flower...Ch. 4 - 11. Red eyes is the wild-type phenotype in...Ch. 4 - 12. As mentioned in Experimental Question E11, red...Ch. 4 - Lets suppose you were looking through a vial of...Ch. 4 - 14. When examining a human pedigree, what features...Ch. 4 - Lets suppose a gene exists as a functional...Ch. 4 - In oats, the color of the chaff is determined by a...
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- In humans, the allele for normal blood clotting (H) is dominant to the allele for hemophilia. This is a sex-linked trait found on the X chromosome. A woman with normal blood clotting has four children: a normal son, a hemophiliac son, and two normal daughters. The father has normal blood clotting. What is the probable genotype for each member of the family?arrow_forwardGene “A” and gene “B” are not linked. Each has two alleles. The A allele is dominant over the a allele and the B allele is dominant over the b allele. Answer the following questions about a dihybrid (two-trait) cross. A) List all of the possible gametes (eggs) that could be produced by an individual with the genotype: aabb B) List all of the possible gametes (sperm) that could be produced by an individual with the genotype: AaBB C) Fill out a Punnett square for the dihybrid cross cross between the two individuals listed above (aabb x AaBB). What percent of the offspring from this cross would have the dominant phenotype for both traits?arrow_forwardThe genotype of EB27 and EB67 are unknown. Based on pedigree, what are the most likely genotype of each individual?arrow_forward
- Joanne has AB blood and Henry has AB blood. They have one child with A blood, one child with AB blood, and another child that has O Bombay phenotype blood. Please explain what is happening here. What is the chance that Joanne and Henry will have a child with B blood type? What is the name of the phenomenon that is responsible for the Bombay phenotype?arrow_forwardA light-haired man has blood type O, his wife has dark hair and blood type AB, but her father had light hair. Assume dark hair (H) is dominant to light (h). What is the probability they will have a child with dark hair and blood type A? What is the probability they will have a child with light hair and blood type B? What is the total number of phenotypes their children could show?arrow_forwardJulie (a female) has hemophilia. Based on this information, what can we say about the genotypes of her parents? If Julie has children with a normal male, what is the chance that her sons have hemophilia? What is the chance that her daughters have hemophilia? A condition called Alport syndrome is caused by a dominant X linked allele. Males who have this condition usually have kidney failure, while females who are heterozygous for the condition have blood in the urine, but usually do not have kidney failure. A male has this condition and has children with an unaffected female What percent of his daughters will show any of the symptoms? What percent of his sons will show any of the symptoms?arrow_forward
- The pedigree below shows the phenotypes of the ABO blood groups and Rhesus factors [positive (+) and negative (-)] for several members of a family. I (B+ AB- 1 2 3 4 II O- A+ В- B- AB+ A+ 1 2 4 5 6 a. What are the ABO blood group genotypes of individuals I-1 and I-2? b. Which child/ren of individual I-4 can donate blood to him? c. Which individual in the pedigree can donate blood to all the other individuals in the pedigree?arrow_forwardIn humans, the allele for normal blood clotting, H, is dominant to the allele for hemophilia, h. This is a sex-linked trait found on the X chromosome. A woman with normal blood clotting has four children: a normal son, a hemophiliac son, and two normal daughters. The father has normal blood clotting. What is the genotype for each member of the family?arrow_forwardA couple who are a carrier of sickle-cell disease with blood type A for the female and type B for the male (assume heterozygosity for blood types). What is the probability that they will have a son with blood type B and is sickle- cell? Please show the solution.arrow_forward
- Several genes in humans in addition to the ABO gene(I) give rise to recognizable antigens on the surface ofred blood cells. The MN and Rh genes are two examples. The Rh locus can contain either a positive or anegative allele, with positive being dominant to negative. M and N are codominant alleles of the MN gene.The following chart shows several mothers and theirchildren. For each mother-child pair, choose the fatherof the child from among the males in the right column, assuming one child per male.Mother Child Malesa. O M Rh(pos) B MN Rh(neg) O M Rh(neg)b. B MN Rh(neg) O N Rh(neg) A M Rh(pos)c. O M Rh(pos) A M Rh(neg) O MN Rh(pos)d. AB N Rh(neg) B MN Rh(neg) B MN Rh(pos)arrow_forwardTwo people are planning to have children together. Each person is heterozygous for the gene “A”. Using this letter, first list all the possible gametes that the two people can produce. Next, write all the possible genotypes and phenotypes for their offspring, using the correct genetic terminology (e.g., “genotype is homozygous dominant” “phenotype is dominant”). HINT: Use the gametes to construct a Punnett square and predict the possible offspring (you do not need to include the Punnett square in your answer).arrow_forwardAlbinism in humans is inherited as a simple recessive trait.Determine the genotypes of the parents and offspring for the following families. When two alternative genotypes are possible,list both.(a) Two parents without albinism have five children, four withoutalbinism and one with albinism.(b) A male without albinism and a female with albinism havesix children, all without albinism.arrow_forward
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