Gene “A” and gene “B” are not linked. Each has two alleles. The A allele is dominant over the a allele and the B allele is dominant over the b allele. Answer the following questions about a dihybrid (two-trait) cross. A) List all of the possible gametes (eggs) that could be produced by an individual with the genotype: aabb B) List all of the possible gametes (sperm) that could be produced by an individual with the genotype: AaBB C) Fill out a Punnett square for the dihybrid cross cross between the two individuals listed above (aabb x AaBB). What percent of the offspring from this cross would have the dominant phenotype for both traits?

Gene “A” and gene “B” are not linked. Each has two alleles. The A allele is dominant over the a allele and the B allele is dominant over the b allele. Answer the following questions about a dihybrid (two-trait) cross. A) List all of the possible gametes (eggs) that could be produced by an individual with the genotype: aabb B) List all of the possible gametes (sperm) that could be produced by an individual with the genotype: AaBB C) Fill out a Punnett square for the dihybrid cross cross between the two individuals listed above (aabb x AaBB). What percent of the offspring from this cross would have the dominant phenotype for both traits?

Name: Gene “A” and gene “B” are not linked. Each has two alleles. The A alle
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Description: Gene “A” and gene “B” are not linked. Each has two alleles. The A allele is dominant over the a allele and the B allele is dominant over the b allele. Answer the following questions about a dihybrid (two-trait) cross.A) List all of the possible gamet

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter6: Cytogenetics: Karyotypes And Chromosome Aberrations

Section: Chapter Questions

Problem 2QP: Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the...

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B. The two rabbits with these corresponding genotypes were mated; CCch X CCh . Do the cross and answer the following questions. How many phenotypes will there be for the offspring? How about the genotypes? What is the percentage of agouti offspring to come out? What is/are the other phenotype/s of the offspring besides agouti?
Cross C: Homozygote wild type flies (+/+) were crossed with white eye flies. The table shows the results for the F1 and F2 generations. White eye females Wild type females White eye males Wild type males 50 F1 phenotypes (observed) F2 phenotypes (observed) F2 - expected phenotypes 50 60 60 60 60 What does the F1 tell you about the trait? Is the gene on an autosome or sex chromosome? What was the genotypes of each parent, male and female? What are the genotypes of the F1 flies? The F1 were crossed with each other and the phenotypes found in F2 are shown in the table above. Are these results consistent with the F1 and your theory of inheritance of this gene? Do a X2 test to see if the observed numbers are consistent with your theory.
Two people are planning to have children together. Each person is heterozygous for the gene “A”. Using this letter, first list all the possible gametes that the two people can produce. Next, write all the possible genotypes and phenotypes for their offspring, using the correct genetic terminology (e.g., “genotype is homozygous dominant” “phenotype is dominant”). HINT: Use the gametes to construct a Punnett square and predict the possible offspring (you do not need to include the Punnett square in your answer).
Two people are planning to have children together. Each person is heterozygous for the gene “G”. Using this letter, first list all the possible gametes that the two people can produce. Next, write all the possible genotypes and phenotypes for their offspring, using the correct genetic terminology (e.g., “genotype is homozygous dominant” “phenotype is dominant”). HINT: Use the gametes to construct a Punnett square and predict the possible offspring (you do not need to include the Punnett square in your answer
In guinea pigs, the black coat (B) is dominant over the white coat (b), and straight hair (H) is dominant over curly hair (h). Using a Punnett square, complete the cross between a heterozygous black, curly-haired individual and a homozygous straight-haired, white individual. State the parent genotypes and gametes, and the F1 phenotypes and genotypes.
In mice, the presence of AA alleles give rise to the agouti fur color, AAY gives rise to a yellow fur color, and AYAY is lethal, causing mice to die before birth. The B allele results in pigment formation and is dominant over the b allele. The bb genotype results in no pigment formation and gives an albino fur color irrespectively of the presence of the AA or AAY alleles. In the following cross between a yellow and agouti mice, what would be the expected proportion of agouti fur mice among the live offspring? AAY Bb X AA Bb 1/2 1/4 3/8 1/3 3/4
Draw a Punnett square for the dihybrid cross. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage.
The eye ring color in wood ducks is under the control of a single, sex linked gene. The dominant allele (R) produces a white eye ring and the recessive allele (r) produces a green eye ring. Provide the results to the following crosses (note birds have ZZ:ZW sex determination). a) Provide the phenotypes and phenotypic ratios of a cross between a female with a white eye ring and a male with a green eye ring. b) Determine the phenotypes and phenotypic ratios for a cross involving an F1 female and an F1 male from the above cross.
In beetles, an X-linked gene determines body size, with normal size (M)completely dominant to miniature body size (m). Body color is determined by an autosomal gene with two alleles, where B is incompletely dominant to b such that BB beetles are black, Bb beetles are brown and bb beetles are yellow. Male beetles are heterogametic (XY). The following cross is performed: brown, miniature sized body female X brown, normal sized body male Based on this information, which of the following statements is FALSE? Select 3 correct answer(s) Question 3 options: A) 1/8 of the female progeny will have yellow miniature bodies. B) All of the male progeny will have miniature bodies. C) 1/4 of the total progeny will be black. D) 1/4 of the male progeny will have yellow miniature bodies. E) All of the female progeny will have miniature bodies.…
Hemophilia is a sex-linked trait where XH gives normal blood clotting and is dominant to the hemophilia allele X h Identify the genotypes of… 1) a woman with normal blood clotting whose father had hemophilia 2) a normal man whose father had hemophilia. What is the probability that a mating between these two individuals will produce a child, regardless of sex, that has hemophilia?
In humans, the genes for red-green color blindness (R = normal, r = color blind) and hemophilia A (H = normal, h = hemophilia) are both X-linked and only 3 map units apart. Suppose a woman has four sons, and two are color blind but have normal blood clotting and two have hemophilia but normal color vision. What is the probable genotype of the woman? HR/hr Hr/hr hr/hR Hr/hR HR/Hr
The father of two children is type O+, and the mother is type A+. The children are O- and A+. Given this information, what are the genotypes of the father vs. the mother at both the “I” and “Rh” alleles? Explain your rationale.