Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 24.2, Problem 10LC
Interpretation Introduction

Interpretation: The formation of cyclic forms by combining the two simple sugars is to be explained.

Concept introduction: Carbohydrates are sugar molecules. Carbohydrates are carbon, hydrogen, and oxygen-based monomers of ketones and aldehydes, including many hydroxyl groups.

Expert Solution & Answer
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Answer to Problem 10LC

By joining one sugar's hydrogen atom to another sugar's hydroxyl group, the condensation reaction combines the cyclic forms of two sugar units.

Explanation of Solution

A condensation process can bind the cyclic forms of two sugars together. By attaching one sugar's hydrogen atom to another's hydroxyl group, condensation reactions can combine the two sugar units to form a cyclic structure. The combination of a glucose molecule and a fructose molecule produces a sucrose molecule.

Conclusion

By joining one sugar's hydrogen atom to another sugar's hydroxyl group, the condensation reaction combines the cyclic forms of two sugar units.

Chapter 24 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 24.2 - Prob. 11LCCh. 24.2 - Prob. 12LCCh. 24.2 - Prob. 13LCCh. 24.2 - Prob. 14LCCh. 24.2 - Prob. 15LCCh. 24.3 - Prob. 16LCCh. 24.3 - Prob. 17LCCh. 24.3 - Prob. 18LCCh. 24.3 - Prob. 19LCCh. 24.3 - Prob. 20LCCh. 24.3 - Prob. 21LCCh. 24.4 - Prob. 22LCCh. 24.4 - Prob. 23LCCh. 24.4 - Prob. 24LCCh. 24.4 - Prob. 25LCCh. 24.4 - Prob. 26LCCh. 24.4 - Prob. 27LCCh. 24.4 - Prob. 28LCCh. 24.5 - Prob. 29LCCh. 24.5 - Prob. 30LCCh. 24.5 - Prob. 31LCCh. 24.5 - Prob. 32LCCh. 24.5 - Prob. 33LCCh. 24.6 - Prob. 35LCCh. 24.6 - Prob. 36LCCh. 24.6 - Prob. 37LCCh. 24.6 - Prob. 38LCCh. 24.6 - Prob. 39LCCh. 24.6 - Prob. 40LCCh. 24 - Prob. 41ACh. 24 - Prob. 42ACh. 24 - Prob. 43ACh. 24 - Prob. 44ACh. 24 - Prob. 45ACh. 24 - Prob. 46ACh. 24 - Prob. 47ACh. 24 - Prob. 48ACh. 24 - Prob. 49ACh. 24 - Prob. 50ACh. 24 - Prob. 51ACh. 24 - Prob. 52ACh. 24 - Prob. 53ACh. 24 - Prob. 54ACh. 24 - Prob. 55ACh. 24 - Prob. 56ACh. 24 - Prob. 57ACh. 24 - Prob. 58ACh. 24 - Prob. 59ACh. 24 - Prob. 60ACh. 24 - Prob. 61ACh. 24 - Prob. 62ACh. 24 - Prob. 63ACh. 24 - Prob. 64ACh. 24 - Prob. 65ACh. 24 - Prob. 66ACh. 24 - Prob. 67ACh. 24 - Prob. 68ACh. 24 - Prob. 69ACh. 24 - Prob. 70ACh. 24 - Prob. 71ACh. 24 - Prob. 72ACh. 24 - Prob. 73ACh. 24 - Prob. 74ACh. 24 - Prob. 75ACh. 24 - Prob. 76ACh. 24 - Prob. 77ACh. 24 - Prob. 78ACh. 24 - Prob. 79ACh. 24 - Prob. 80ACh. 24 - Prob. 81ACh. 24 - Prob. 82ACh. 24 - Prob. 83ACh. 24 - Prob. 84ACh. 24 - Prob. 85ACh. 24 - Prob. 86ACh. 24 - Prob. 87ACh. 24 - Prob. 88ACh. 24 - Prob. 89ACh. 24 - Prob. 90ACh. 24 - Prob. 91ACh. 24 - Prob. 92ACh. 24 - Prob. 93ACh. 24 - Prob. 94ACh. 24 - Prob. 95ACh. 24 - Prob. 96ACh. 24 - Prob. 97ACh. 24 - Prob. 98ACh. 24 - Prob. 99ACh. 24 - Prob. 100ACh. 24 - Prob. 101ACh. 24 - Prob. 102ACh. 24 - Prob. 103ACh. 24 - Prob. 104ACh. 24 - Prob. 105ACh. 24 - Prob. 106ACh. 24 - Prob. 107ACh. 24 - Prob. 108ACh. 24 - Prob. 109ACh. 24 - Prob. 110ACh. 24 - Prob. 111ACh. 24 - Prob. 112ACh. 24 - Prob. 113ACh. 24 - Prob. 115ACh. 24 - Prob. 116ACh. 24 - Prob. 117ACh. 24 - Prob. 118ACh. 24 - Prob. 119ACh. 24 - Prob. 120ACh. 24 - Prob. 121ACh. 24 - Prob. 122ACh. 24 - Prob. 123ACh. 24 - Prob. 124ACh. 24 - Prob. 125ACh. 24 - Prob. 126ACh. 24 - Prob. 127ACh. 24 - Prob. 128ACh. 24 - Prob. 129ACh. 24 - Prob. 130ACh. 24 - Prob. 131ACh. 24 - Prob. 132ACh. 24 - Prob. 133ACh. 24 - Prob. 1STPCh. 24 - Prob. 2STPCh. 24 - Prob. 3STPCh. 24 - Prob. 4STPCh. 24 - Prob. 5STPCh. 24 - Prob. 6STPCh. 24 - Prob. 7STPCh. 24 - Prob. 8STPCh. 24 - Prob. 9STPCh. 24 - Prob. 10STPCh. 24 - Prob. 11STPCh. 24 - Prob. 12STPCh. 24 - Prob. 13STPCh. 24 - Prob. 14STP
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