Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 24, Problem 130A

(a)

Interpretation Introduction

Interpretation: To write the IUPAC name for the given compound.

Concept Introduction: In order to give names to organic compounds, IUPAC nomenclature is used.

(a)

Expert Solution
Check Mark

Answer to Problem 130A

The IUPAC name for the given compound is cyclopentane.

Explanation of Solution

The given compound is cyclic and consists of five carbon atoms that are bonded with two hydrogen atoms.

In IUPAC nomenclature for naming cyclic compounds depends on the longest chain of carbons that are connected via single bonds. The prefix to be used while writing cyclic compounds is “cyclo” followed by the name of the continuous chain of carbon atoms.

The given compound is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 24, Problem 130A , additional homework tip  1

So, the given compound has a continuous cyclic ring containing five carbon atoms (i.e., pentane). Thus, the IUPAC name for the compound is cyclopentane.

(b)

Interpretation Introduction

Interpretation: To write the IUPAC name for the given compound.

Concept Introduction: In order to give names to organic compounds, IUPAC nomenclature is used.

(b)

Expert Solution
Check Mark

Answer to Problem 130A

The IUPAC name for the given compound is 2-methyl-2-propanol.

Explanation of Solution

The rules for writing IUPAC names for the organic compounds are as follows:

  1. The root word indicates the longest continuous chain in the compound which is also known as the parent chain.
  2. Then suffixes and prefixes must be written as per the substituents, side chains, or functional groups.

The given compound is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 24, Problem 130A , additional homework tip  2

So, for the given compound, the longest possible chain is three carbon atom chain (i.e., propane), there is a substituent that is present at the second carbon which also contains an alcohol functional group ( for alcohols, the suffix to be used is “ol”).

Therefore, the IUPAC name for the given compound is 2-methyl-2-propanol.

(c)

Interpretation Introduction

Interpretation: To write the IUPAC name for the given compound.

Concept Introduction: In order to give names to organic compounds, IUPAC nomenclature is used.

(c)

Expert Solution
Check Mark

Answer to Problem 130A

The IUPAC name for the given compound is 3-pentanone.

Explanation of Solution

The rules for writing IUPAC names for the organic compounds are as follows:

  1. The root word indicates the longest continuous chain in the compound which is also known as the parent chain.
  2. Then suffixes and prefixes must be written as per the substituents, side chains, or functional groups.

The given compound is represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 24, Problem 130A , additional homework tip  3

So, for the given compound the longest possible continuous carbon chain is five carbon atoms (i.e., pentane) and it has a ketone functional group that is present on the third carbon. For ketones, the suffix to be used is “one”.

Therefore, the IUPAC name for the given compound is 3-pentanone.

Chapter 24 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 24.2 - Prob. 11LCCh. 24.2 - Prob. 12LCCh. 24.2 - Prob. 13LCCh. 24.2 - Prob. 14LCCh. 24.2 - Prob. 15LCCh. 24.3 - Prob. 16LCCh. 24.3 - Prob. 17LCCh. 24.3 - Prob. 18LCCh. 24.3 - Prob. 19LCCh. 24.3 - Prob. 20LCCh. 24.3 - Prob. 21LCCh. 24.4 - Prob. 22LCCh. 24.4 - Prob. 23LCCh. 24.4 - Prob. 24LCCh. 24.4 - Prob. 25LCCh. 24.4 - Prob. 26LCCh. 24.4 - Prob. 27LCCh. 24.4 - Prob. 28LCCh. 24.5 - Prob. 29LCCh. 24.5 - Prob. 30LCCh. 24.5 - Prob. 31LCCh. 24.5 - Prob. 32LCCh. 24.5 - Prob. 33LCCh. 24.6 - Prob. 35LCCh. 24.6 - Prob. 36LCCh. 24.6 - Prob. 37LCCh. 24.6 - Prob. 38LCCh. 24.6 - Prob. 39LCCh. 24.6 - Prob. 40LCCh. 24 - Prob. 41ACh. 24 - Prob. 42ACh. 24 - Prob. 43ACh. 24 - Prob. 44ACh. 24 - Prob. 45ACh. 24 - Prob. 46ACh. 24 - Prob. 47ACh. 24 - Prob. 48ACh. 24 - Prob. 49ACh. 24 - Prob. 50ACh. 24 - Prob. 51ACh. 24 - Prob. 52ACh. 24 - Prob. 53ACh. 24 - Prob. 54ACh. 24 - Prob. 55ACh. 24 - Prob. 56ACh. 24 - Prob. 57ACh. 24 - Prob. 58ACh. 24 - Prob. 59ACh. 24 - Prob. 60ACh. 24 - Prob. 61ACh. 24 - Prob. 62ACh. 24 - Prob. 63ACh. 24 - Prob. 64ACh. 24 - Prob. 65ACh. 24 - Prob. 66ACh. 24 - Prob. 67ACh. 24 - Prob. 68ACh. 24 - Prob. 69ACh. 24 - Prob. 70ACh. 24 - Prob. 71ACh. 24 - Prob. 72ACh. 24 - Prob. 73ACh. 24 - Prob. 74ACh. 24 - Prob. 75ACh. 24 - Prob. 76ACh. 24 - Prob. 77ACh. 24 - Prob. 78ACh. 24 - Prob. 79ACh. 24 - Prob. 80ACh. 24 - Prob. 81ACh. 24 - Prob. 82ACh. 24 - Prob. 83ACh. 24 - Prob. 84ACh. 24 - Prob. 85ACh. 24 - Prob. 86ACh. 24 - Prob. 87ACh. 24 - Prob. 88ACh. 24 - Prob. 89ACh. 24 - Prob. 90ACh. 24 - Prob. 91ACh. 24 - Prob. 92ACh. 24 - Prob. 93ACh. 24 - Prob. 94ACh. 24 - Prob. 95ACh. 24 - Prob. 96ACh. 24 - Prob. 97ACh. 24 - Prob. 98ACh. 24 - Prob. 99ACh. 24 - Prob. 100ACh. 24 - Prob. 101ACh. 24 - Prob. 102ACh. 24 - Prob. 103ACh. 24 - Prob. 104ACh. 24 - Prob. 105ACh. 24 - Prob. 106ACh. 24 - Prob. 107ACh. 24 - Prob. 108ACh. 24 - Prob. 109ACh. 24 - Prob. 110ACh. 24 - Prob. 111ACh. 24 - Prob. 112ACh. 24 - Prob. 113ACh. 24 - Prob. 115ACh. 24 - Prob. 116ACh. 24 - Prob. 117ACh. 24 - Prob. 118ACh. 24 - Prob. 119ACh. 24 - Prob. 120ACh. 24 - Prob. 121ACh. 24 - Prob. 122ACh. 24 - Prob. 123ACh. 24 - Prob. 124ACh. 24 - Prob. 125ACh. 24 - Prob. 126ACh. 24 - Prob. 127ACh. 24 - Prob. 128ACh. 24 - Prob. 129ACh. 24 - Prob. 130ACh. 24 - Prob. 131ACh. 24 - Prob. 132ACh. 24 - Prob. 133ACh. 24 - Prob. 1STPCh. 24 - Prob. 2STPCh. 24 - Prob. 3STPCh. 24 - Prob. 4STPCh. 24 - Prob. 5STPCh. 24 - Prob. 6STPCh. 24 - Prob. 7STPCh. 24 - Prob. 8STPCh. 24 - Prob. 9STPCh. 24 - Prob. 10STPCh. 24 - Prob. 11STPCh. 24 - Prob. 12STPCh. 24 - Prob. 13STPCh. 24 - Prob. 14STP
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