Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 21.4, Problem 1CS
Summary Introduction
To explain:
The way in which the proteins encoded by different members of the globin gene family vary in their affinity for oxygen.
Introduction:
Oxygen is the most essential requirement for humans and animals. A gene named as globin gene is responsible for the production of proteins that have an affinity towards oxygen. These proteins are responsible for the transportation of oxygen across different body parts. The best-known example of globin protein is hemoglobin.
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Need help:, The rRNAs are isolated from the large subunit of a bacterial ribosome and separated by density
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Objective: Get a sense of how genomics, the study of the genome in its entirety,needs to think about how to go about its research.
Geonomic DNA is broken up into fragments. The 5’ and 3’ ends of each fragment(a “read”) are sequenced. The sequenced reads are assembled together intocontiguous sequences (“contigs”) based on sequence similarity.
The idea is to sequence enough random fragments so that every nucleotide in thegenome is represented on some read. The number of such fragments needed iscalled the coverage, c.
The coverage c can be calculated by the formula RL/G, where R is the number ofreads sequenced, L is the average length of a read and G is the total length of thegenome. The units of length are bases (b) or base pairs (bp).
Consider a genome whose length is 1000 bp. “Shotgun” sequencing techniquesare applied to the genome, resulting in 20 reads, with an average length of 50 bp.A very important point is that, even though 20 x 50 = 1000, there is no guaranteethat ALL…
Objective: Get a sense of how genomics, the study of the genome in its entirety,needs to think about how to go about its research.
Geonomic DNA is broken up into fragments. The 5’ and 3’ ends of each fragment(a “read”) are sequenced. The sequenced reads are assembled together intocontiguous sequences (“contigs”) based on sequence similarity.
The idea is to sequence enough random fragments so that every nucleotide in thegenome is represented on some read. The number of such fragments needed iscalled the coverage, c.
The coverage c can be calculated by the formula RL/G, where R is the number ofreads sequenced, L is the average length of a read and G is the total length of thegenome. The units of length are bases (b) or base pairs (bp).
Consider a genome whose length is 1000 bp. “Shotgun” sequencing techniquesare applied to the genome, resulting in 20 reads, with an average length of 50 bp.A very important point is that, even though 20 x 50 = 1000, there is no guaranteethat ALL…
Chapter 21 Solutions
Biology
Ch. 21.1 - Prob. 1CSCh. 21.1 - Prob. 1CCCh. 21.1 - Prob. 2CCCh. 21.1 - Prob. 3CCCh. 21.2 - Prob. 1CCCh. 21.2 - Prob. 2CCCh. 21.2 - Prob. 3CCCh. 21.3 - Prob. 1EQCh. 21.3 - Prob. 2EQCh. 21.3 - Prob. 3EQ
Ch. 21.4 - Prob. 1CCCh. 21.4 - Prob. 1CSCh. 21.5 - Prob. 1CSCh. 21.5 - Repetitive Sequences and Transposable Elements...Ch. 21 - Prob. 1TYCh. 21 - DNA ligase is needed in a cloning experiment a. to...Ch. 21 - Prob. 3TYCh. 21 - Why is Taq polymerase used in PCR rather than...Ch. 21 - Lets suppose you want to clone a gene that has...Ch. 21 - In the CRISPR-Cas technology for editing genes,...Ch. 21 - Prob. 7TYCh. 21 - The enzyme that helps short segments of DNA move...Ch. 21 - Prob. 9TYCh. 21 - Which of the following was not a goal of the Human...Ch. 21 - Prob. 1CQCh. 21 - Briefly describe whether or not each of the...Ch. 21 - Prob. 3CQCh. 21 - Identify and discuss three important advances that...Ch. 21 - Prob. 2COQ
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