Concepts of Genetics (12th Edition)
Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 20, Problem 4PDQ

The human insulin gene contains a number of sequences that are removed in the processing of the mRNA transcript. In spite of the fact that bacterial cells cannot excise these sequences from mRNA transcripts, explain how a gene like this can be cloned into a bacterial cell and produce insulin.

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The human insulin gene contains a number of sequences thatare removed in the processing of the mRNA transcript. Bacterialcells cannot excise these sequences from mRNA transcripts, yetthis gene can be cloned into a bacterial cell and produce insulin.Explain how this is possible.
Briefly discuss (referring to the images provided) why mutant 2 fails to produce functional protein. Note that none of the mRNA transcribed from this gene is of the expected size; some of the mRNA molecules produced are 223 nucleotides shorter than expected, whilst others are 47 nucleotides longer than expected.
Using the DNA nucleotide sequences for the wild-type and mutant genes in the following tables, determine the complementary mRNA sequence for the five portions of the Mc1r gene provided. (Note: You are only transcribing short portions of the DNA sequence for this protein. The actual gene contains 954 base pairs.) Using the mRNA sequence completed, determine the resulting amino acid sequence of the MC1R protein. (Note: You are translating only a portion of protein. The full protein is 317 amino acids long. The numbers above the columns in the tables indicate amino acid positions in the protein sequence.) You may use the genetic code chart provided

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Concepts of Genetics (12th Edition)

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Bacterial Genomics and Metagenomics; Author: Quadram Institute;https://www.youtube.com/watch?v=_6IdVTAFXoU;License: Standard youtube license