Study Guide for Campbell Biology
Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 18, Problem 4TYK
Summary Introduction

Introduction: Mutations are sudden changes that occur in the nucleotide sequence of DNA. An operon is the “functional unit” of a gene. It has three units namely promoter, operator, and structural genes. The promoter initiates transcription by binding to RNA polymerase, while operator regulates gene expression.  An operon has a cluster of genes that are controlled by a single promoter. Lac operon in E. coli is required for proper synthesis and metabolism of the disaccharide lactose.

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A mutation in the operator region of the trp operon can prevent the trp repressor from binding to this operator. When these mutant cells are placed in a solution containing chicken broth, which of the following happens? a. Tryptophan would bind to the repressor. b. The Repressor would bind to the operator irrespective of the presence of amino acids in the environment.  c. The transcription of the trip operon would be inhibited. d. The transcription of the repressor protein is inhibited
For the trp operon, determine whether genes will be expressed (on) or silenced (off) given the following: a. Tryptophan levels are high. b. The trp repressor can no longer bind tryptophan.
The graph below shows a growth curve of E. coli growing in a defined medium containing equal concentration of glucose and lactose. On the y-axis optical density provides a measure of cell number, higher optical density indicates greater cell number. OD (optical density) Time Based on your knowledge regarding regulation of the lac operon, the best explanation of these results is that... A. The bacteria are utilizing both sugars simultaneously. B. At early time points, inhibition of the lac repressor allows for lactose metabolism. C. Cells constitutively express enzymes needed for sugar metabolism, allowing for continuous cell growth. D. Glucose activates CAP, allowing for cell growth at intermediate time points. E. At later time points, high cAMP allows for an increase in beta-galactosidase expression.
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QCE Biology: Introduction to Gene Expression; Author: Atomi;https://www.youtube.com/watch?v=a7hydUtCIJk;License: Standard YouTube License, CC-BY