Microbiology: An Evolving Science (Fourth Edition)
Microbiology: An Evolving Science (Fourth Edition)
4th Edition
ISBN: 9780393615098
Author: John W. Foster, Joan L. Slonczewski
Publisher: W. W. Norton & Company
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Chapter 11.1, Problem 3TQ
Summary Introduction

To review:

The lysis of E. coli cells lacking maltose porin by lambda phage.

Introduction:

The lambda phage infects Escherichia coli cells. It attaches to the host cell surface by binding to the maltose porin. This porin is responsible for the transport of maltose sugar into the bacterial cells. The maltose in the gut is provided by Bacteroides bacterial species that break down plant polysaccharides.

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Why is phage conversion considered beneficial to host cells?
Why is a webbed plate capable of producing a higher lysate titer (pfu/mL) than a cleared plate? a.) A webbed plate has plaques that have gone through more rounds of replication because the number of host cells did not limit phage replication, creating exponentially more phage particles b.) A webbed plate has no more host available for replication, meaning the plate is full of exponentially higher amounts of phage c.) A cleared plate has less bacteria than a webbed plate, so there are more plaques present d.) A cleared plate contains more phage than a webbed plate because it started with a more concentrated phage sample
In Hershey-Chase experiment, bacteriophages protein coats were tagged with radioactive isotope S-32. These phages were used to infect E. coli cells and the cells were further centrifuged to form pellets. Why was the radioactivity level of S-32 found greater outside the cells compared to the E. coli cell pellets? Explain briefly. If the experiment is repeated in the same manner but this time the phage protein coats are labelled with isotope X and the phage DNA with isotope Y, which isotope’s radioactivity will be found in greater amounts in the E. coli cell pellets after centrifugation? Explain briefly.
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