Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 10.5, Problem 2COMQ
In Noll’s experiment to test the beads-on-a-string model, exposure of nuclei to a low concentration of DNase I resulted in
a. a single band of DNA with a size of approximately
b. several bands of DNA in multiples of
c. a single band of DNA with a size of
d. several bands of DNA in multiples of
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Students have asked these similar questions
The use of dideoxynucleotide triphosphates in the Sanger method
facilitates sequencing of polynucleotides. Why?
A. Fragments are generated with the terminal ends corresponding to the
complement of the DNA being sequenced.
B. Incorporation of the specific dideoxynucleotides terminates polymerization
of the newly synthesized DNA.
C. Dideoxynucleotides are randomly incorporated to the growing polypeptide
chain
D. Both A and B
E. All of these
The diagram illustrating the polymerase chain reaction (PCR) technique is provided below. How does the number of copies of the DNA region being amplified change at the end of each cycle of the polymerase chain reaction?
Group of answer choices
a. The number of copies triples (or triplicates).
b. The number of copies does not change.
c. The number of copies quadruples (or quadruplicates).
d. The number of copies doubles (or duplicates).
e. The number of copies halves.
Which of the following best describes the process of DNA seqencing.
a. DNA is seperated on a gel and the different bands are labled with flouroscent nucleotides and scanned with a laser.
b. A laser is used to flurorescently label the nucleotides present with in the DNA , the DNA is run on a gel and then the DNA is droken into fragments
c. Nucleotides are scanned with a laser and incrprorated into the DNA that has been seperated on a gel and then DNA is amplified with PCR.
d. fragments of DNA are produced in a reaction that lables them with any of four different fluroscent dyes and the fragmented then are run on a gel and scanned with laser
e. DNA is broken down into its constituents nucleotides and the nucleotides are then run on a gel and purified with a laser
Chapter 10 Solutions
Genetics: Analysis and Principles
Ch. 10.1 - 1. A bacterial chromosome typically contains
a. a...Ch. 10.2 - Mechanisms that make the bacterial chromosome more...Ch. 10.2 - 2. Negative supercoiling may enhance activities...Ch. 10.2 - 3. DNA gyrase
a. promotes negative supercoiling....Ch. 10.3 - 1. The chromosomes of eukaryotes typically contain...Ch. 10.4 - Which of the following is an example of a...Ch. 10.5 - What are the components of a single nucleosome? a....Ch. 10.5 - 2. In Noll’s experiment to test the...Ch. 10.5 - Prob. 3COMQCh. 10.5 - Prob. 4COMQ
Ch. 10.6 - Prob. 1COMQCh. 10.6 - 2. The role of cohesin is to
a. make chromosomes...Ch. 10 - Prob. 1CONQCh. 10 - Prob. 2CONQCh. 10 - 3. Describe the mechanisms by which bacterial DNA...Ch. 10 - Why is DNA supercoiling called supercoiling rather...Ch. 10 - Prob. 5CONQCh. 10 - Prob. 6CONQCh. 10 - Prob. 7CONQCh. 10 - Prob. 8CONQCh. 10 - Prob. 9CONQCh. 10 - 10. What is the function of a centromere? At what...Ch. 10 - Prob. 11CONQCh. 10 - 12. Describe the structures of a nucleosome and a...Ch. 10 - Beginning with the G1 phase of the cell cycle,...Ch. 10 - Draw a picture depicting the binding between the...Ch. 10 - 15. Compare heterochromatin and euchromatin. What...Ch. 10 - 16. Compare the structure and cell localization of...Ch. 10 - 17. What types of genetic activities occur during...Ch. 10 - Lets assume the linker region of DNA averages 54bp...Ch. 10 - 19. In Figure 10.12, what are we looking at in...Ch. 10 - 20. What are the roles of the core histone...Ch. 10 - A typical eukaryotic chromosome found in humans...Ch. 10 - Which of the following terms should not be used to...Ch. 10 - Discuss the differences between the compaction...Ch. 10 - 24. What is an SMC complex? Describe two...Ch. 10 - Two circular DNA molecules, which we can call...Ch. 10 - 2. Let’s suppose you have isolated DNA from a cell...Ch. 10 - 3. We seem to know more about the structure of...Ch. 10 - In Nolls experiment of Figure 10.11, explain where...Ch. 10 - When chromatin is treated with a salt solution of...Ch. 10 - 6. Let’s suppose you have isolated chromatin from...Ch. 10 - If you were given a sample of chromosomal DNA and...Ch. 10 - Consider how histone proteins bind to DNA and then...Ch. 10 - In Chapter 23, the technique of fluorescence in...Ch. 10 - Bacterial and eukaryotic chromosomes are very...Ch. 10 - The prevalence of highly repetitive sequences...Ch. 10 - Discuss and make a list of the similarities and...
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- Which of the following statements is FALSE regarding the molecular mechanism for DNA polymerases? A. The active site contains 2 divalent metal ions B. A single stranded DNA template is required C. The enzyme can only attach a new deoxynucleotide to the 5’ end of a growing chain D. The 3’OH on the deoyxyribose ring attacks a phosphate of a dNTP to produce a new phosophodiester bond E. None of the above (all are true statements)arrow_forwardWhat is the effect of incubating a mixture of RNA and DNA with 0.1 M NaOH? A. DNAishydrolyzedtonucleosidemonophosphates.B. No effect. RNA and DNA are resistant to base hydrolysis.C. RNA is hydrolyzed to nucleoside monophosphates. D. Both RNA and DNA are hydrolyzed to nucleoside monophosphates. Stem-loop structures in RNA resemble the ________ form of double-helical DNA. A. A B. BC. supercoiledcircular D. Zarrow_forwardWhat is the effect of incubating a mixture of RNA and DNA with 0.1 M NaOH? A. DNA is hydrolyzed to nucleoside monophosphates. B. No effect. RNA and DNA are resistant to base hydrolysis. C. RNA is hydrolyzed to nucleoside monophosphates. D. Both RNA and DNA are hydrolyzed to nucleoside monophosphates. Stem-loop structures in RNA resemble the ________ form of double-helical DNA. A. A B. B C. supercoiled circular D. Zarrow_forward
- If you repeat the okazaki experiment WITHOUT denaturing DNA, what would be the expected outcome? a. Increased length of RNA primers b. Slowing of fragment maturation O c. No short fragments observed d. All short fragments observed e. Decrease in fragment size over timearrow_forwardWhich of the following statements is TRUE concerning the synthesis of the leading and lagging strands of DNA in prokaryotic cells? a. O b. The leading strand is synthesized by one polymerase III continuously, and the lagging strand is synthesized by several molecules of DNA polymerase III. d. The leading and lagging strands are synthesized at the same time by the one DNA polymerase I. O c. The leading and lagging strands are synthesized at the same time by the one DNA polymerase III. The leading strand is synthesized by one polymerase III, and the lagging strand is synthesized by DNA polymerase I.arrow_forwardWhich of the following statements BEST DESCRIBES the main findings of the Meselson-Stahl experiment? A. DNA can be separated using centrifugation B. The semiconservative model of DNA replication is more accurate than the dispersive or conservative models of DNA replication C. Using 14N in experiments is an effective way of tracking nitrogen molecules D. Bacteria grown in the presence of a heavier nitrogen isotope (15N) will replicate at a slower rate than those that utilise a lighter nitrogen isotope (14N) E. Both strands of each new DNA double helix are brand new and synthesized from individual nucleotidesarrow_forward
- You have 2 solutions of DNA. Solution 1 contains single stranded viral DNA while Solution 2 has double stranded form of the same viral DNA. Both solutions contain 1 mg/ml of DNA. You then expose each of these solutions to UV light at 260 nm. Which of the following results would you expect to see after UV light exposure? a.Neither solution will absorb any UV light but the DNA in both solutions will be broken by the action of the UV light. b.Solution 1 will absorb less light than Solution 2 c.Solution 1 will absorb more light than solution 2. d.Nothing will occur. DNA can only absorb UV light if it is interchelated with ethidium bromide. e.Both solutions will absorb the same amount of light since their concentrations are the same.arrow_forwardWhich statement about Okazaki fragments is true? Select one: a. DNA polymerase doesn’t need a primer to build these fragments b. They act as a primer that initiates DNA replication. c. They correct errors made during earlier phases of DNA replication. d. They are necessary because DNA polymerase can only build DNA in the 5’ to 3’ direction, so for one of the strands at each fork, the DNA polymerase can only buildaway from the fork. e. They prevent the ends of chromosomes from shortening with every replication.arrow_forwardWhich of the following statements is not true? Explain why. A. A DNA strand can serve as a template strand on many occasions. B. Following semiconservative DNA replication, one strand is a newly made daughter strand and the other strand is a parental strand. C. A DNA double helix may contain two strands of DNA that were made at the same time. D. A DNA double helix obeys the AT/GC rule. E. A DNA double helix could contain one strand that is 10 generations older than its complementary strand.arrow_forward
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