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Microelectronics: Circuit Analysis and Design
- 8. Determine the output voltage V, and the Zener diode current Iz for the circuit below. The Zener diode is IN5236B. }} a) E-21 V, R1=1 km2, and R2-2 km2 b) E-21 V, R1-2 k2, and R2-1 k E R₁ www R₂arrow_forwardPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to IL-DC =0:5A RL VL-DC =20V 220V omsb O 001 F O 0.02 F O 0.0167F O None of the above Activatearrow_forwardIn the circuit shown below. Let Vm-35 V and i-20 mA and VpQ -0.7 V: iD 3 kQ 0.8 kO Vmcos(@t)V For t Os, the current in the diode equals: Oa. 0 mA Ob. 4 mA Oc. 2 mA Od. 6 mA If t = T/4, then the current in the diode equals: Oa. 6.29 mA Ob. 5.03 mA Oc. 4,03 mA Od. 7.86 mA If t = T/2, then the current in the diode equals: Oa. 15.24 mA Ob. 13.24 mA Oc. 19.24 mA Od. 17.24 mAarrow_forward
- SOLVE STEP BY STEP IN DIGITAL FORMAT For each of the circuits shown below, draw its voltage transfer curve, using the constant-drop model (all diodes are silicon identical, V_Don = 0.7V). Consider a variation of the input voltage from -10V to +10V. Vi V₁ D₁ D₁ Z D₂ 1k Circuit 1 1k Circuit 2 V₂ + V₂ Vi Vi 1k 1k D₁ Circuit 3 D₁ 1k ww 1k Circuit 4 + V₂ + V₂arrow_forwardMake open and short circuit calculations of the diode in Figure 8.15. (Vs=45, Vb=44, R1=74, R2=147 , R3=148)arrow_forwardIn the circuit of the following figure, the input voltage Vs is 15 volts rms with a frequency of 60 Hz, R equals 150 Ohms and C equals 100,000 Pico Farads. The diodes are Germanium (Vd = 0.2 volts) and the Zener diode is 12 volts. a) The magnitude of the ripple voltage at Cb) The Magnitude of the Peak Inverse Voltage (PIV) for D1 and D2.arrow_forward
- Consider the circuit given below with R = 5k2 and Vcc = 12V. The input signal is (Vs= 25 sin wt milivolts) is a smal signal source. The capacitor C is assumed very large. The diode is a pn-junction diode with turn-on voltage of VD=0.7V. Vcc R= 5 k2 Vcc = 12 V Io Io = 0.5 mA D1 a) Draw the DC equivalent circuit and determine the DC component of the output voltage Vo (E Vs R Vo b) Draw the AC determine the AC small signal colaponent of the output. small signal equivalent circuit and c) Determine the total voltage (DC+AC) at the output vo. What is the percentage of the ripple voltage seen at the output@40arrow_forward2. Figure A.1 shows I-V characteristics of two diodes, namely A and B. Diode A has higher dynamic resistance than diode B. UTM &UT ID 4 5UTM 3TM UTM UTM &UTM 5 UTM & UTM UTM 3 UTM 03 TM 6 UT 0.68 (a) UTM VD Figure A.1 State one possible reason why the diodes have different knee voltage values. UTM OM & UTM 3 UTM & TM (b) Based on Figure A.1, identify the knee voltage of UTM" TM 5 UTde BE UTMarrow_forwardFigure Q7 For the network shown in Figure Q8, determine the range of RL that will maintain the Zener diode in the ON state. 8. R=250 N IL +o IR Iz Vz = 10 V Vi = 20V IZM = 30mA R. VL Figure Q8arrow_forward
- I need some help with this problem. I need to create a power supply from 110v 60hz to regulated an output between 6 and 9 v. the image is the desire circuit to acomplish the possible solution. The resistor after the bridge rectifier will work as a surge protector or current limiter for the zener diode. the other is the Load resistor. I need some sort of calculations to prove the specific values for the components to operate according to the specs that I already explain. I know the capacitor will smooth the ripple voltage etc... but I need some guidance to get actual valuesarrow_forwardPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20Varrow_forwardQ4) Determine and sketch the output voltage across the load resistor (RL) for the circuit shown below. (assume Si diodes) V_DC 0.75 0.25 V_SIN Y SIN as RL -1 v SOR V_SQR 0.75 -0.75 V_TRI V TRI asarrow_forward
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