Statistics Through Applications
Statistics Through Applications
2nd Edition
ISBN: 9781429219747
Author: Daren S. Starnes, David Moore, Dan Yates
Publisher: Macmillan Higher Education
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Chapter 2.2, Problem 2.37E

(a)

To determine

To identify: the mean, median, standard deviation for the each graph.

(a)

Expert Solution
Check Mark

Answer to Problem 2.37E

Variable =2

Explanation of Solution

Given:

  Statistics Through Applications, Chapter 2.2, Problem 2.37E , additional homework tip  1

Mean = 6.6, Median = 6.8, Standard Deviation = 1.3, variable =.......

The mean and median are almost similar and standard deviation is very small from the other three standard deviations. It implies that the range of the data has to be smaller and data has to be almost similar therefore

Variable =2

(b)

To determine

To identify: the mean, median, standard deviation for the each graph.

(b)

Expert Solution
Check Mark

Answer to Problem 2.37E

Variable = 3

Explanation of Solution

Given:

  Statistics Through Applications, Chapter 2.2, Problem 2.37E , additional homework tip  2

Mean = 6.6, Median = 6.0, Standard Deviation = 8.65, variable =.......

The mean and median are almost similar which means that the data would be almost symmetric. Therefore

Variable = 3

(c)

To determine

To identify: the mean, median, standard deviation for the each graph.

(c)

Expert Solution
Check Mark

Answer to Problem 2.37E

Variable = 1

Explanation of Solution

Given:

  Statistics Through Applications, Chapter 2.2, Problem 2.37E , additional homework tip  3

Mean = 6.6, Median = 3.75, Standard Deviation = 7.4, variable =.......

The median is a very less than median; the data has to be left-skewed therefore.

Variable = 1

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Statistics Through Applications

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