Statistics Through Applications
2nd Edition
ISBN: 9781429219747
Author: Daren S. Starnes, David Moore, Dan Yates
Publisher: Macmillan Higher Education
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Question
Chapter 2.2, Problem 2.29E
(a)
To determine
To Calculate: the
(a)
Expert Solution
Answer to Problem 2.29E
M=Q2=7
Explanation of Solution
Given:
3 0 12 10 8 4 2 7 10 11 6 7 0 35 12 3 10 2 7 9 15 5 14 15 6
Formula used:
Q2=2×(N+14)th postion
Calculation:
Order the numbers in ascending order
0 0 2 2 3 3 4 5 6 6 7 7 7 8 9 10 10 10 11 12 12 14 15 15 35
Q2=2×(N+14)th postion=2×(25+14)th postion=13th postionM=Q2=7
I
The median or 2nd
(b)
To determine
To Calculate: the quartiles and IQR and interpret meaning of IQR in this setting.
(b)
Expert Solution
Answer to Problem 2.29E
Q1=3.5Q3=11.5IQR=8
Explanation of Solution
Given:
0 0 2 2 3 3 4 5 6 6 7 7 7 8 9 10 10 10 11 12 12 14 15 15 35
Formula used:
Q1=1×(N+14)th postionQ3=3×(N+14)th postionIQR=Q3−Q1
Calculation:
Q1=1×(N+14)th postion=1×(25+14)th postion=6.5=6th position +0.5(7th−6th)=3+0.5(4−3)=3.5
Q3=3×(N+14)th postion=3×(25+14)th postion=19.5=19th position+0.5(20th−19th)=11+0.5(12−11)=11.5Q3=7
IQR=Q3−Q1=11.5−3.5=8
IQR stands for inter
(c)
To determine
To Explain: that is there outlier
(c)
Expert Solution
Answer to Problem 2.29E
43 and 45 are extremely high outliers.
Explanation of Solution
Given:
43 45 72 73 78 80 81 82 82.5 85 85.5 86 86 87.5 87.5
88 88 88 89 91 91 92 93 93.5 93.5 94.5 94.5 95 96 98
Formula used:
For greater than Q3+1.5(IQR) and
For lesser than Q1−1.5(IQR)
Calculation:
Q3+1.5(IQR)=11.5+1.5(8)=23.5Q1−1.5(IQR)=3.5−1.5(8)=−8.5
An outlier is an extremely high or extremely low value in the data set. It can be identify an outlier if it is greater than Q3+1.5(IQR) and lesser then Q1−1.5(IQR) and there is only one outlier which is extremely high outliers 35.
Chapter 2 Solutions
Statistics Through Applications
Ch. 2.1 - Prob. 2.1ECh. 2.1 - Prob. 2.2ECh. 2.1 - Prob. 2.3ECh. 2.1 - Prob. 2.4ECh. 2.1 - Prob. 2.5ECh. 2.1 - Prob. 2.6ECh. 2.1 - Prob. 2.7ECh. 2.1 - Prob. 2.8ECh. 2.1 - Prob. 2.9ECh. 2.1 - Prob. 2.10E
Ch. 2.1 - Prob. 2.11ECh. 2.1 - Prob. 2.12ECh. 2.1 - Prob. 2.13ECh. 2.1 - Prob. 2.14ECh. 2.1 - Prob. 2.15ECh. 2.1 - Prob. 2.16ECh. 2.1 - Prob. 2.17ECh. 2.1 - Prob. 2.19ECh. 2.1 - Prob. 2.20ECh. 2.1 - Prob. 2.21ECh. 2.1 - Prob. 2.23ECh. 2.1 - Prob. 2.24ECh. 2.1 - Prob. 2.25ECh. 2.1 - Prob. 2.26ECh. 2.2 - Prob. 2.27ECh. 2.2 - Prob. 2.28ECh. 2.2 - Prob. 2.29ECh. 2.2 - Prob. 2.30ECh. 2.2 - Prob. 2.31ECh. 2.2 - Prob. 2.32ECh. 2.2 - Prob. 2.33ECh. 2.2 - Prob. 2.34ECh. 2.2 - Prob. 2.35ECh. 2.2 - Prob. 2.36ECh. 2.2 - Prob. 2.37ECh. 2.2 - Prob. 2.38ECh. 2.2 - Prob. 2.39ECh. 2.2 - Prob. 2.40ECh. 2.2 - Prob. 2.41ECh. 2.2 - Prob. 2.42ECh. 2.2 - Prob. 2.43ECh. 2.2 - Prob. 2.44ECh. 2.2 - Prob. 2.45ECh. 2.2 - Prob. 2.46ECh. 2.2 - Prob. 2.47ECh. 2.2 - Prob. 2.48ECh. 2.2 - Prob. 2.49ECh. 2.2 - Prob. 2.50ECh. 2.2 - Prob. 2.51ECh. 2.2 - Prob. 2.52ECh. 2.3 - Prob. 2.53ECh. 2.3 - Prob. 2.54ECh. 2.3 - Prob. 2.55ECh. 2.3 - Prob. 2.56ECh. 2.3 - Prob. 2.57ECh. 2.3 - Prob. 2.58ECh. 2.3 - Prob. 2.59ECh. 2.3 - Prob. 2.60ECh. 2.3 - Prob. 2.61ECh. 2.3 - Prob. 2.62ECh. 2.3 - Prob. 2.63ECh. 2.3 - Prob. 2.64ECh. 2.3 - Prob. 2.65ECh. 2 - Prob. 2.67RECh. 2 - Prob. 2.68RECh. 2 - Prob. 2.69RECh. 2 - Prob. 2.70RECh. 2 - Prob. 2.71RECh. 2 - Prob. 2.72RECh. 2 - Prob. 2.73RECh. 2 - Prob. 2.74RECh. 2 - Prob. 2.75RECh. 2 - Prob. 2.76RE
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