Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Question
Chapter 21, Problem 25EQ
Summary Introduction
To analyze:
The results of western blot of a gene on mutation in varying conditions like:
1. Normal gene from a plant.
2. Gene without promoter.
3. Heterozygous mutation in which one gene is normal and other is short due to introduction of a stop codon at 112 position.
4. Homozygous mutation in which stop codon is inserted at 112 base pair (bp).
5. Homozygous mutation in which phenylalanine is changed to leucine.
Introduction:
In western blotting, the fragments of polypeptides that are produced within the cell are detected by using the antibodies as probes. The proteins from cell are purified and are loaded in the electrophoresis. These proteins then are observed by autoradiography or fluorescence.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Knowing that the genetic code is almost universal, a scientist uses molecular biological methods to insert the human β-globin gene (Shown in Figure 17.11) into bacterial cells, hoping the cells will express it and synthesize functional β-globin protein. Instead, the protein produced is nonfunctional and is found to contain many fewer amino acids than does β-globin made by a eukaryotic cell. Explain why.
Researchers have identified a gene (FR) responsible for watermelon resistance to infection by Dacus curcurbitae (a close relative of Drosophila melanogaster). They isolate RNA from resistant (FR+) and sensitive (fr-) watermelons and use a probe that will recognize both FR+ and fr- transcripts. They also isolate protein from resistant and sensitive watermelons and perform a Western blot using an antibody that can recognize the fr- and FR+ protein. Describe the results illustrated below and give a plausible molecular explanation for these observations.
In cells, certain hormones, such as epinephrine, have the ability to raise the concentration of cAMP. The CREB protein can be found in a cell extract that has been pretreated with epinephrine or not, depending on your preference.Using an electrophoretic mobility shift experiment, you test the CREB protein's capacity to attach to a DNA fragment containing a cAMP response element (CRE). Specify what you hope to achieve.
Chapter 21 Solutions
Genetics: Analysis and Principles
Ch. 21.1 - 1. Which of the following may be used as a vector...Ch. 21.1 - The restriction enzymes used in gene-cloning...Ch. 21.1 - 3. Which is the proper order of the following...Ch. 21.1 - 4. The function of reverse transcriptase is...Ch. 21.1 - A collection of recombinant vectors that carry...Ch. 21.2 - Prob. 1COMQCh. 21.2 - Prob. 2COMQCh. 21.2 - 3. During real-time PCR, the synthesis of PCR...Ch. 21.3 - When a dideoxyribonucleotide is incorporated into...Ch. 21.4 - 1. The purpose of site-directed mutagenesis and...
Ch. 21.5 - Which of the following methods use(s) a labeled...Ch. 21.5 - 2. Which of the following methods is used to...Ch. 21.5 - During Western blotting, the primary antibody...Ch. 21.6 - 1. In an EMSA, the binding of a protein to...Ch. 21.6 - The basis for DNase I footprinting is that the...Ch. 21 - Discuss three important advances that have...Ch. 21 - Prob. 2CONQCh. 21 - Write a double-stranded DNA sequence that is 20...Ch. 21 - What is cDNA? In eukaryotes, how does cDNA differ...Ch. 21 - 5. Draw the structural feature of a...Ch. 21 - Prob. 1EQCh. 21 - Prob. 2EQCh. 21 - Describe the important features of cloning...Ch. 21 - 4. How does gene cloning produce many copies of a...Ch. 21 - Prob. 5EQCh. 21 - Prob. 6EQCh. 21 - Prob. 7EQCh. 21 - Prob. 8EQCh. 21 - Prob. 9EQCh. 21 - Starting with a sample of RNA that contains the...Ch. 21 - 11. What type of probe is used for real-time PCR?...Ch. 21 - 12. What phase of PCR (exponential, linear, or...Ch. 21 - 13. DNA sequencing can help us to identify...Ch. 21 - A sample of DNA was subjected to automated DNA...Ch. 21 - Prob. 15EQCh. 21 - Prob. 16EQCh. 21 - Prob. 17EQCh. 21 - Prob. 18EQCh. 21 - Prob. 19EQCh. 21 - What is the purpose of a Northern blotting...Ch. 21 - Prob. 21EQCh. 21 - Prob. 22EQCh. 21 - 23. In the Western blot shown here, proteins were...Ch. 21 - If you wanted to know if a protein was made during...Ch. 21 - Prob. 25EQCh. 21 - Prob. 26EQCh. 21 - Prob. 27EQCh. 21 - 28. Describe the rationale behind the...Ch. 21 - Certain hormones, such as epinephrine, can...Ch. 21 - An electrophoretic mobility shift assay can be...Ch. 21 - Prob. 31EQCh. 21 - Prob. 32EQCh. 21 - Prob. 33EQCh. 21 - Prob. 1QSDC
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- In Northern blot analysis, mRNA samples from tissues are bound to a labeled DNA probe that is complementary to the mRNA, and run on a gel to be visualized. The protein tropomyosin is known to be present in both brain and liver. When brain and liver tissue were assayed for the presence of tropomyosin mature mRNA, bands of two different sizes were seen. Tropomyosin gene diagram (3000 bp total): Shown in attatched image If the band on the Northern blot for mRNA isolated from liver tissue is 2580 bp, whereas from brain tissue the band is 2250 bp, what is most likely? a)The two mRNAs are made from different tropomyosin DNA sequences. b)Exon 2 is alternatively spliced out of the brain mRNA. c)Introns 1 and 2 are spliced out of the brain transcript but not the liver transcript. d)Exons 1 and 3 are spliced out of the brain transcript but not the liver transcript. e)Exon 2 is alternatively spliced out of the liver mRNA.arrow_forwardWhat's the correct answer and can you explain in detail? I'm confused on how gel mobility works.arrow_forwardKnowing that the genetic code is almost universal, a scientist uses molecular biological methods to insert the human β-globin gene (Shown in Figure 17.11) into bacterial cells, hoping the cells will express it and synthesize functional β-globin protein. Instead, the protein produced is nonfunctional and is found to contain many fewer amino acids than does β-globin made by a eukaryotic cell. Explain why.arrow_forward
- You would like to add a nuclear localization sequence (NLS) of Lys-Lys-Lys-Arg-Lys to a protein that is usually found in the cytoplasm of a yeast cell. To accomplish this, you introduce the nucleotide sequence encoding the NLS into the gene that encodes the cytoplasmic protein of interest. a. What is the size of the nucleotide insert that will encode the NLS? Briefly explain. 5' 3' b. Below is a diagram of the gene encoding the cytoplasmic protein of interest in the yeast genome. If your goal is to put the NLS at the carboxyl (C) terminus of the protein, at which location (A-E) should the NLS be inserted? Briefly explain. A TATAA ATATT promoter +1 B ATG TAC D TAA ATT stop codon E 3' 5'arrow_forwardA molecular geneticist hopes to find a Gene in human liver cell that codes for an important blood-clotting protein,he knows that the nucleotide sequence of a small part of the Gene is GTGGACTGACA.briefly explain how to obtain genearrow_forwardBesides the examples listed in Table 24.3, list five types ofshort sequences that a geneticist might want to locate withina DNA sequence.arrow_forward
- Shown below is a schematic diagram illustrating a very short gene with 5000 bp region of an unknown Schizosaccharomyces pombe genome. (Note: Transcription starts at Transcription Start Site (TSS).) TSS 5. 3' 3 +1 (i) Name the specific regions that can be recognized by Transcription Factor IID (TF ID) and indicate the locations in the diagram above. (ii) List the mechanistic steps that can trigger the initiation of transcription by Transcription Factor IIH (TF IIH).arrow_forwardKnowing that the genetic code is almost universal, a scientist uses molecular biological methods to insert the human - globin gene (shown in the figure below (Links to an external site.)) into bacterial cells, hoping the cells will express it and synthesize functional - globin protein. Instead, the protein produced is nonfunctional and is found to contain many fewer amino acids than does -globin made by a eukaryotic cell. Explain why and give thoughts as to how to overcome this.arrow_forwardBelow is a sequence of 540 bases from a genome. What information would you use to find the beginnings and ends of open reading frames? How many open reading frames can you find in this sequence? Which open reading frame is likely to represent a protein- coding sequence, and why? Which are probably not functioning protein-coding sequences, and why? Note: for simplicitys sake, analyze only this one strand of the DNA double helix, reading from left to right, so you will only be analyzing three of the six reading frames shown in Figure 19.4.arrow_forward
- Analyzing Cloned Sequences A base change (A to T) is the mutational event that created the mutant sickle cell anemia allele of beta globin. This mutation destroys an MstII restriction site normally present in the beta globin gene. This difference between the normal allele and the mutant allele can be detected with Southern blotting. Using a labeled beta globin gene as a probe, what differences would you expect to see for a Southern blot of the normal beta globin gene and the mutant sickle cell gene?arrow_forwardFor a specific type of mutation at a given location in a particular gene, identify whether it will affect the size of the mRNA, the protein, or both. How would the mutant appear on a gel in comparison to the originalarrow_forwardThe E. coli genome contains approximately 4639 kb. (a) How many copies of the 6-bp recognition sequence for the trp repressor would be expected to occur in the E. coli chromosome? (b) Explain why it is advantageous for the trp repressor to be a dimer that recognizes two adjacent 6-bp sequences.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage LearningBiology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Biology: The Dynamic Science (MindTap Course List)
Biology
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Cengage Learning
Parasites: Protozoa (classification, structure, life cycle); Author: ATP;https://www.youtube.com/watch?v=V4iSB0_7opM;License: Standard youtube license