Concept explainers
(a)
Interpretation:
The
Concept Introduction:
When H2O is lost from a material it is called dehydration. When an alcohol is treated with a strong acid such as H2SO4, a water molecule is lost by breaking two adjacent bonds C-OH and C-H and forming a new double bond, producing an alkene. This is an elimination reaction.
In this reaction more than one type of alkene may produce. But one of them is the major product.
According to Zaitsev rule, the major product alkene formed by elimination, is that which possess more alkyl groups bonded to it
(b)
Interpretation:
The alkene formed when the given alcohol is treated with H2SO4 should be determined. The major product should be predicted using Zaitsev rule.
Concept Introduction:
When H2O is lost from a material it is called dehydration. When an alcohol is treated with a strong acid such as H2SO4, a water molecule is lost by breaking two adjacent bonds C-OH and C-H and forming a new double bond, producing an alkene. This is an elimination reaction.
In this reaction more than one type of alkene may produce. But one of them is the major product.
According to Zaitsev rule, the major product alkene formed by elimination, is that which possess more alkyl groups bonded to it
(c)
Interpretation:
The alkene formed when the given alcohol is treated with H2SO4 should be determined. The major product should be predicted using Zaitsev rule.
Concept Introduction:
When H2O is lost from a material it is called dehydration. When an alcohol is treated with a strong acid such as H2SO4, a water molecule is lost by breaking two adjacent bonds C-OH and C-H and forming a new double bond, producing an alkene. This is an elimination reaction.
In this reaction more than one type of alkene may produce. But one of them is the major product.
According to Zaitsev rule, the major product alkene formed by elimination, is that which possess more alkyl groups bonded to it
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Chapter 14 Solutions
General, Organic, and Biological Chemistry - 4th edition
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- Draw and name ethers and heterocyclic ethers, including epoxides. Predict theirrelative boiling points, solubilities, and solvent properties.arrow_forwardAlkenes can be converted to alcohols by reaction with mercuric acetate to form a ß-hydroxyalkylmercury(II) acetate compound, a reaction called oxymercuration. Subsequent reduction with NaBH reduces the C-Hg bond to a C-H bond, forming the alkyl alcohol, a reaction called demercuration. Draw the structure of the Hg-containing compound and the final alcohol product formed in the reaction sequence. CH3 Hg(OOCCH3)2 NaBH4 HO™ Oxymercuration product Demercuration Product H₂O, THF Draw the alcohol product of demercuration. Draw the neutral product of oxymercuration. Omit byproducts. OH Hg Incorrectarrow_forwardWhat is the structure of the IUPAC name? Draw the structure and give how many carbons are on the parent chain. 2-(4-methylcyclohex-3-enyl)propane-2-thiolarrow_forward
- Explain Structure and Bonding of Alcohols, ethers, and epoxides ?arrow_forward1. 1-Octen-3-ol is a potent mosquito attractant commonly used in mosquito traps. A number of reactions, including hydrogenation, will transform 1-Octen-3-ol into a less effective molecule. What is a complete reaction equations for the hydrogenation of this alkenolarrow_forwardAn alcohol does not react with aziridine unless an acid is present. Why is the acid necessary?arrow_forward
Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning