Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
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Chapter 11, Problem 31P
The pedigree shown in Fig. 11.22 was crucial to the identification of the Huntington disease gene HD, which is located on chromosome 4.
| a. | The data show that the DNA marker G8 is clearly linked to HD. For the large majority of the people in the pedigree with Huntington disease, which allele of G8 (A, B, C, or D) did they inherit, along with the dominant disease-causing allele of HD, on the copy of chromosome 4 from their affected parent? |
| b. | How many people in the pedigree can you categorize absolutely as the product of parental or recombinant gametes from their affected parent, without making any assumptions at all (including the assumption of linkage)? |
| c. | If you now make the assumption that G8 and HD are linked, how many of the people in this pedigree must be the product of a recombinant gamete from their affected parent? |
| d. | Based solely on the data from this pedigree, what would be the best estimate for the map distance between G8 and HD? |
| e. | Considering your answers to parts (b) through (d), calculate the maximum Lod score. The pedigree contains 47 people resulting from informative matings. (Note that 00 = 1.) What does this Lod score signify? |
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Susan’s grandfather was deaf, and passed down a hereditary form of deafness within Susan’s family as shown in Figure Q19–12.A. Is this mutation most likely to be dominant or recessive?B. Is it carried on an autosome or a sex chromosome? Why?C. A complete SNP analysis has been done for all of the 11 grandchildren (4 affected, and 7 unaffected). In comparing these 11 SNP results, how long a haplotype block would you expect to find around the critical gene? How might you detect it?
The DNA of every individual in the pedigree shown
below has been sequenced at the causative locus.
All the non-shaded individuals are wild type apart
from III.1. III.1 has been proven to have the
causative mutation for this autosomal dominant
condition, but they exhibit no symptoms. Based on
this small pedigree, what is the level of penetrance
for the condition? Please give your answer as a
WHOLE percentage, give the number only, no
percentage symbol.
Answer: The level of penetrance for the
condition shown in the pedigree below is Blank 1
percent.
1:1
1:2
Il:1
I1:2
I1:3
Il:4
I1:5
I1:6
II:1 I:2 III:3
III:4
III:3 III:6 III:7
III:8
III:9
III:10 III:11 III12 II:13 III:14
IV:1 | IV:2 IV:3 IV:4 IV:5 IV:6 IV:7 IV:8 IV:9 IV:10 IV:11 IV:12 IV:13 IV:14 IV:15 IV:16 IV:17
IV:18 IV:19
V:1 V:2 V:3 V:4 V:5
V:6
V:7
V:8 V:9
V:10
V:11 V:12
You are studying four linked genes located on chromosome 2 in the fruit fly Drosophila
melanogaster: adp (which contributes to obesity), b (which contributes to body color), pr (which
contributes to metabolism), and vg (which contributes to wing formation). A series of crosses
between pair-wise combinations of these mutations yielded the following recombination frequencies
between the indicated loci:
pr and adp 9%
adp and b 6%
pr and b 3%
vg and b 10%
vg and pr 7%
What is the genetic distance in map units (cM) between the adp and vg loci?
16
9
6
4
Chapter 11 Solutions
Genetics: From Genes to Genomes
Ch. 11 - Choose the phrase from the right column that best...Ch. 11 - Would you characterize the pattern of inheritance...Ch. 11 - Would you be more likely to find single nucleotide...Ch. 11 - A recent estimate of the rate of base...Ch. 11 - If you examine Fig. 11.5 closely, you will note...Ch. 11 - Approximately 50 million SNPs have thus far been...Ch. 11 - Mutations at simple sequence repeat SSR loci occur...Ch. 11 - Humans and gorillas last shared a common ancestor...Ch. 11 - In 2015, an international team of scientists...Ch. 11 - Using PCR, you want to amplify an approximately 1...
Ch. 11 - Prob. 11PCh. 11 - The previous problem raises several interesting...Ch. 11 - You want to make a recombinant DNA in which a PCR...Ch. 11 - You sequence a PCR product amplified from a...Ch. 11 - Prob. 15PCh. 11 - The trinucleotide repeat region of the Huntington...Ch. 11 - Sperm samples were taken from two men just...Ch. 11 - Prob. 18PCh. 11 - a. It is possible to perform DNA fingerprinting...Ch. 11 - On July 17, 1918, Tsar Nicholas II; his wife the...Ch. 11 - The figure that follows shows DNA fingerprint...Ch. 11 - Microarrays were used to determine the genotypes...Ch. 11 - A partial sequence of the wild-type HbA allele is...Ch. 11 - a. In Fig. 11.17b, PCR is performed to amplify...Ch. 11 - The following figure shows a partial microarray...Ch. 11 - Scientists were surprised to discover recently...Ch. 11 - The microarray shown in Problem 25 analyzes...Ch. 11 - The figure that follows shows the pedigree of a...Ch. 11 - One of the difficulties faced by human geneticists...Ch. 11 - Now consider a mating between consanguineous...Ch. 11 - The pedigree shown in Fig. 11.22 was crucial to...Ch. 11 - You have identified a SNP marker that in one large...Ch. 11 - The pedigrees indicated here were obtained with...Ch. 11 - Approximately 3 of the population carries a mutant...Ch. 11 - The drug ivacaftor has recently been developed to...Ch. 11 - In the high-throughput DNA sequencing protocol...Ch. 11 - A researcher sequences the whole exome of a...Ch. 11 - As explained in the text, the cause of many...Ch. 11 - Figure 11.26 portrayed the analysis of Miller...Ch. 11 - A research paper published in the summer of 2012...Ch. 11 - Table 11.2 and Fig. 11.27 together portray the...Ch. 11 - The human RefSeq of the entire first exon of a...Ch. 11 - Mutations in the HPRT1 gene in humans result in at...Ch. 11 - Prob. 44P
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