Biochemistry: The Molecular Basis of Life
6th Edition
ISBN: 9780190209896
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 7, Problem 13RQ
Summary Introduction
To review:
The structural relationship exhibited by the term D-sugar, and the reason for classifying glucose and fructose as D-sugars.
Introduction:
Isomers are compoundsthathave thesame molecular formula but different spatial arrangements of atoms;the related phenomenon is known as isomerization. Monosaccharides(carbohydrates) show isomerism.
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Students have asked these similar questions
question 1 : draw an α,α(2, 2) linkage between the two monosaccharides(two fructose ). label the glycosidic linkage. Must be Haworth
question 2 : Draw glycosidic linkage between D-glucose linked to D-altrose with a β(1, 3) glycosidic linkage. label clearly the glycosidic linkage. must be Haworth.
Is sucrose a reducing or non-reducing sugar? Explain.
Is lactose a reducing non reducing sugar? Explain.
Question 18
Match the following structural composition with the corresponding polysaccharide
Linear homoglycan of glucose connected by a1-4 linkages
a. agarose
v Branched glycan formed by alternating units of D-galactose and L-galactose
b. amylose
v Linear sulfated chains of alternating B-D-galactopyranose and 3,6-anhydro- a-galactopyranosyl units
c. amylopectin
v Poly-B-Dmannopyranosyluronic acid and/or Poly-a-L-gulopyranosyluronic acid
d. Alginate
v Repeating Poly-D-galacturonic acid residues
e. agaropectin
deacetylated straight-chain amino-polysaccharide polymer linked in a B(1-4) type of linkage
f. Pectin
g. carrageenan
h. chitosan
Chapter 7 Solutions
Biochemistry: The Molecular Basis of Life
Ch. 7 - Prob. 1QCh. 7 - Prob. 2QCh. 7 - Prob. 3QCh. 7 - Prob. 4QCh. 7 - Prob. 5QCh. 7 - Prob. 6QCh. 7 - Prob. 7QCh. 7 - Prob. 1RQCh. 7 - Prob. 2RQCh. 7 - Prob. 3RQ
Ch. 7 - Prob. 4RQCh. 7 - Prob. 5RQCh. 7 - Prob. 6RQCh. 7 - Prob. 7RQCh. 7 - Prob. 8RQCh. 7 - Prob. 9RQCh. 7 - Prob. 10RQCh. 7 - Prob. 11RQCh. 7 - Prob. 12RQCh. 7 - Prob. 13RQCh. 7 - Prob. 14RQCh. 7 - Prob. 15RQCh. 7 - Prob. 16RQCh. 7 - Prob. 17RQCh. 7 - Prob. 18RQCh. 7 - Prob. 19RQCh. 7 - Prob. 20RQCh. 7 - Prob. 21RQCh. 7 - Prob. 22RQCh. 7 - Prob. 23RQCh. 7 - Prob. 24RQCh. 7 - Prob. 25RQCh. 7 - Prob. 26RQCh. 7 - Prob. 27RQCh. 7 - Prob. 28FBCh. 7 - Prob. 29FBCh. 7 - Prob. 30FBCh. 7 - Prob. 31FBCh. 7 - Prob. 32FBCh. 7 - Prob. 33FBCh. 7 - Prob. 34FBCh. 7 - Prob. 35FBCh. 7 - Prob. 36FBCh. 7 - Prob. 37FBCh. 7 - Prob. 38SACh. 7 - Prob. 39SACh. 7 - Prob. 40SACh. 7 - Prob. 41SACh. 7 - Prob. 42SACh. 7 - Prob. 43TQCh. 7 - Prob. 44TQCh. 7 - Prob. 45TQCh. 7 - Prob. 46TQCh. 7 - Prob. 47TQCh. 7 - Prob. 48TQCh. 7 - Prob. 49TQCh. 7 - Prob. 50TQCh. 7 - Prob. 51TQCh. 7 - Prob. 52TQCh. 7 - Prob. 53TQCh. 7 - Prob. 54TQCh. 7 - Prob. 55TQCh. 7 - Prob. 56TQCh. 7 - Prob. 57TQCh. 7 - Prob. 58TQCh. 7 - Prob. 59TQCh. 7 - Prob. 60TQCh. 7 - Prob. 61TQCh. 7 - Prob. 62TQCh. 7 - Prob. 63TQCh. 7 - Prob. 64TQCh. 7 - Prob. 65TQCh. 7 - Prob. 66TQCh. 7 - Prob. 67TQCh. 7 - Prob. 68TQCh. 7 - Prob. 69TQCh. 7 - Prob. 70TQ
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- Why are (+)glucose and (-)fructose both classified asD sugar.?arrow_forwardComplete the following table by providing the Fischer and Haworth Projections of the given sugars. (Please be careful with the alpha and beta, and the complete and abbreviated) (not a graded question) Sugar Fischer Projection Haworth Projection (Complete) alpha-anomer Haworth Projection (Abbreviated) beta-anomer L-Galactose L-Fructosearrow_forwardWhat structural relationship is indicated by the term D-sugar? Why are (+) glucose and (-) fructose both classified as D-sugars?arrow_forward
- If thymine nucleotides are degraded by the same enzymes as those catabolizing uridine nucleotides, give the structure of the thymine metabolite that corresponds to B-ureidopropionate.arrow_forwardThe hexokinases are a class of enzymes that catalyze the ATP-dependent phosphorylation of hexoses (sugars with six carbons). The hexokinases will bind only D-hexose sugars and not their L-counterparts. In general terms, describe the features of enzyme structure that make this specificity possible.arrow_forwardCellulose and glycogen are both polymers of glucose, but they have very different functions. Select all of the statements below that are true (this is a multi-select question). One important difference between cellulose and glycogen is that the cellulose has a(1→6) branches, which greatly increases the "connectiveness" within the structure. One important difference between cellulose and glycogen is that cellulose is a B(14) linked glucan, while glycogen is an a(1→4) linked glucan. The major cause of the functional difference is that glycogen is stored in the cytosol, whereas cellulose is a component of the cell walls. Cellulose is flexible due to the noncovalent interactions between the B(1-4) linked strands of glucose: the polymer can bend without breaking covalent bonds. Cellulose is more "stretchy" than glycogen, since its structure is held together only by the relatively weak hydrogen bonds.arrow_forward
- What is the pyranose/furanose ring structure of this sugar?arrow_forwardThe amount of branching (number of (α1→6) glycosidic bonds) in amylopectin can be determined by the following procedure. A sample of amylopectin is exhaustively methylated—treated with a methylating agent (methyl iodide) that replaces the hydrogen of every sugar hydroxyl witha methyl group, converting —OH to —OCH3 . All the glycosidic bonds in the treated sample are then hydrolyzed in aqueous acid, and the amount of 2,3-di-O-methylglucose so formed is determined.(a) Explain the basis of this procedure for determining the number of (α1→6) branch points in amylopectin. What happens to the unbranched glucose residues in amylopectin during the methylation and hydrolysis procedure?(b) A 258 mg sample of amylopectin treated as described above yielded 12.4 mg of 2,3-di-O-methylglucose. Determine what percentage of the glucose residues in the amylopectin contained an (α1→6) branch. (Assume that the average molecular weight of a glucose residue in amylopectin is 162 g/mol.)arrow_forwardWhen a purine or pyrimidine is linked through a b-Nglycosidic link to C-1 of a pentose, the molecule is calleda _________________________.arrow_forward
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