Microbiology: An Evolving Science (Fourth Edition)
4th Edition
ISBN: 9780393615098
Author: John W. Foster, Joan L. Slonczewski
Publisher: W. W. Norton & Company
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Chapter 6, Problem 5RQ
Summary Introduction
To review:
The differences between lytic, lysogenic, and slow release replication cycle along with their strengths and limitations.
Introduction:
A bacteriophage is a virus particle that uses bacterial cell as its host. It uses specific receptors for attachment to the host cell surface. It then inserts its genome into the host whichis replicated and packaged into progeny virion. Examples of bacteriophages include T4 and M13.
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Chapter 6 Solutions
Microbiology: An Evolving Science (Fourth Edition)
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- Double-stranded RNA viruses, use the following polymerase for genome synthesis: A) viral RNA-dependent RNA polymerase. B) host cell DNA-dependent RNA polymerase. C) viral DNA-dependent DNA polymerase. D) host cell RNA-dependent RNA polymerase.arrow_forwardBriefly describe the structure of bacteriophage.arrow_forwardWhich statement is true regarding a bacteriophage in the lysogenic cycle? 111 A) O The bacteriophage can exit the lysogenic state depending on the condition of host cell B) O While in this cycle, it would cause no harm to the host cell. O OAs the host cell divides, the bacteriophage genome will be present in all of the host cell's progeny. |D) OIt would become a prophage. E) O All are true statements.arrow_forward
- Explain, with the aid of a hand drawn diagram, the life cycle of bacteriophage T4.arrow_forwardWhich statement regarding transitions and transversions is TRUE? a) An adenine to guanine change is a transversion b) Transversions are more commonly found in nature that are transitions c) A cytosine to guanine change is a transition d) Transversions cause a distortion in the DNA double helixarrow_forwardA cell is produced with a mutation that causes it produce a completely defective TFIIH. What does this likely mean for the fate of the cell? A) The cell's copied DNA may contain more errors. B) the cell cannot make RNA C) Producing RNAs will be slower because the polymerase will fall off the DNA more often. D) The cell cannot replicate its DNAarrow_forward
- Assume you isolate a single stranded (+) RNA virus. When you examine the proteins in the virus, you find that it does NOT contain replicase enzymes within its capsid. Which of the following is true? This virus must have a gene that encodes replicase. This virus will not be able to enter a host cell. Its genome cannot be translated (the process of translation) by the host cell ribosomes. A DNA copy of the viral genome has to be made before viral genes are expressed. This virus must lack surface antigens.arrow_forwardA large portion of the human genome is transposons. Collectively, they are most likely: A) an equal mix of DNA and retrotransposons B) mostly DNA transposons because they are found in DNA C) mostly retrotransposons because they copy themselves each time they move D) mostly DNA transposons because they can cut themselves outarrow_forwardWhat is the function of reverse transcriptase in retroviruses? a) It converts viral RNA into double-stranded DNA Ob) It uses viral RNA as a template for making complementary RNA strands Oc) It translates viral RNA into proteins d) It uses viral DNA as a template for RNA synthesisarrow_forward
- Describe the stages in the multiplication cycle of bacteriophages.arrow_forwardWhich of the following statements is not applicable to conjugation? A) OF factors are transferrable plasmids passed from one cell to another during conjugation. B) O During conjugation, rolling circle replication transfers an F factor from an F+ cell to an F- cell. ) O An F factor acquired during conjugation will automatically be integrated into the recipient's chromosome. D) O Conjugation requires physical contact between cells via the formation of a sex pilus. E) O An Hfr strain is capable of transferring a portion of the chromosome during conjugation.arrow_forwardIn Hershey-Chase experiment, bacteriophages protein coats were tagged with radioactive isotope S-32. These phages were used to infect E. coli cells and the cells were further centrifuged to form pellets. Why was the radioactivity level of S-32 found greater outside the cells compared to the E. coli cell pellets? Explain briefly. If the experiment is repeated in the same manner but this time the phage protein coats are labelled with isotope X and the phage DNA with isotope Y, which isotope’s radioactivity will be found in greater amounts in the E. coli cell pellets after centrifugation? Explain briefly.arrow_forward
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