Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 4.8, Problem 49SEP
To determine
The chemical formula for an intermetallics compound of Cu and Al is
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What is the composition in weight percent of an alloy that contains 98 g tin and 65 g lead? What is the composition in atom percent?
1. When Au comes into contact with Ag, it creates a solid solution that is called a substitutional solid solution. Calculate the amount of Au atoms per cubic centimeter in an Ag–Au alloy with 10% Au and 90% Ag. Pure Au has a density of 19.32 g/cm3 and pure Ag has a density of 10.49 g/cm3.
2. What is the atomic radius of nickel (in A) if it follows an FCC crystal structure, given that Nickel has a density of 8.9 g/mL and an atomic weight of 58.7 g/mol.
3. If 25 grains per square inch are measured at 100x magnification, what is the ASTM grain size number of the metal specimen?
1 Al-Li Aerospace Alloys
When a small amount of Li is added into Al to create an Al-Li alloy, the two elements typically do not
mix homogeneously. Instead, most of the material is nearly-pure Al, while some small regions are Li-rich.¹
(These small regions are called precipitates and they are responsible for giving Al-Li alloys much better
properties for aerospace applications relative to pure Al. We'll learn more about the alloying process and
about precipitates later in the course.)
The Li-rich regions have the chemical formula Al3Li and belong to the cubic crystal system.² In the unit
cell, the Li atoms are located at 000, while the Al atoms are located at 110, 101, and 01121.
(a) Draw the unit cell of Al3Li.
(b) Which of the crystal structures from Callister Chapter 3 does this resemble? Why do we not call it
that structure?
(c) Given that the lattice parameter is 0.401 nm, what is the density of Al3Li?
Chapter 4 Solutions
Foundations of Materials Science and Engineering
Ch. 4.8 - Prob. 1KCPCh. 4.8 - Define the homogeneous nucleation process for the...Ch. 4.8 - In the solidification of a pure metal, what are...Ch. 4.8 - In the solidification of a metal, what is the...Ch. 4.8 - During solidification, how does the degree of...Ch. 4.8 - Distinguish between homogeneous and heterogeneous...Ch. 4.8 - Describe the grain structure of a metal ingot that...Ch. 4.8 - Distinguish between equiaxed and columnar grains...Ch. 4.8 - How can the grain size of a cast ingot be refined?...Ch. 4.8 - Prob. 10KCP
Ch. 4.8 - Prob. 11KCPCh. 4.8 - Prob. 12KCPCh. 4.8 - Distinguish between a substitutional solid...Ch. 4.8 - What are the conditions that are favorable for...Ch. 4.8 - Prob. 15KCPCh. 4.8 - Prob. 16KCPCh. 4.8 - Prob. 17KCPCh. 4.8 - Prob. 18KCPCh. 4.8 - Describe the structure of a grain boundary. Why...Ch. 4.8 - Describe and illustrate the following planar...Ch. 4.8 - Prob. 21KCPCh. 4.8 - Describe the optical metallography technique. What...Ch. 4.8 - Prob. 23KCPCh. 4.8 - Prob. 24KCPCh. 4.8 - Prob. 25KCPCh. 4.8 - Prob. 26KCPCh. 4.8 - Prob. 27KCPCh. 4.8 - Prob. 28KCPCh. 4.8 - Prob. 29KCPCh. 4.8 - Prob. 30KCPCh. 4.8 - Prob. 31KCPCh. 4.8 - Calculate the size (radius) of the critically...Ch. 4.8 - Prob. 33AAPCh. 4.8 - Prob. 34AAPCh. 4.8 - Calculate the number of atoms in a critically...Ch. 4.8 - Prob. 36AAPCh. 4.8 - Prob. 37AAPCh. 4.8 - Prob. 38AAPCh. 4.8 - Prob. 39AAPCh. 4.8 - Prob. 40AAPCh. 4.8 - Prob. 41AAPCh. 4.8 - Prob. 42AAPCh. 4.8 - Determine, by counting, the ASTM grain-size number...Ch. 4.8 - Prob. 44AAPCh. 4.8 - For the grain structure in Problem 4.43, estimate...Ch. 4.8 - Prob. 46AAPCh. 4.8 - Prob. 47SEPCh. 4.8 - Prob. 48SEPCh. 4.8 - Prob. 49SEPCh. 4.8 - Prob. 50SEPCh. 4.8 - In Chapter 3 (Example Problem 3.11), we calculated...Ch. 4.8 - Prob. 52SEPCh. 4.8 - Prob. 53SEPCh. 4.8 - Prob. 54SEPCh. 4.8 - Prob. 55SEPCh. 4.8 - Prob. 56SEPCh. 4.8 - Prob. 57SEPCh. 4.8 - Prob. 58SEPCh. 4.8 - Prob. 59SEPCh. 4.8 - Prob. 60SEPCh. 4.8 - Prob. 61SEPCh. 4.8 - Prob. 62SEPCh. 4.8 - Prob. 63SEPCh. 4.8 - Prob. 64SEPCh. 4.8 - Prob. 65SEPCh. 4.8 - Prob. 66SEP
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- Calculate the theoretical density of NiO, given that it has the rock salt crystal structure. You may want to use the table below. The atomic weights for Ni and O are 58.69 g/mol and 16.00 g/mol, respectively. Ionic Radius (nm) P = i Cation Fe²+ Ni²+ Mg2+ Mn2+ g/cm³ 0.077 0.069 0.072 0.067 Anion 0²- S²- Ionic Radius (nm) 0.140 0.184arrow_forwardCompute the composition, in atom percent, of an alloy that contains 45.2 kg copper, 46.3 kg zinc, and 0.95 kg lead?arrow_forwardA number of elements along with their crystal structures and atomic radii are listed in the following table. Which pairs might be expected to have complete solid solubility in each other? Crystal Atomic Crystal Structure Atomic Structure radius (nm) radius (nm) Silver Palladium FCC 0.144 Lead FCC 0.175 FCC 0.137 0.137 Tungsten Rhodium ВСС Copper Gold FCC 0.128 FCC 0.134 Platinum Tantalum FCC 0.144 FCC 0.138 Nickel FCC 0.125 ВСС 0.143 Aluminum Sodium FCC 0.143 Potassium ВСС 0.231 ВСС 0.185 Molybdenum ВСС 0.136arrow_forward
- Show that Ni and Cu are totally soluble in one another using Hume-Rothery rules. Atomic radii, electronegativities and crystal structures of Ni and Cu are given below. Ni Cu Crystal Structure FCC FCC Electronegativities 1.9 1.8 r (nm) 0.1246 0.1278arrow_forwardIron (Fe) undergoes an allotropic transformation at 912°C: upon heating from a BCC [ alpha phase) to a FCC (gamma phase). Accompanying thistransformation is a change in the atomic radius of Fe from R bcc= 0.12584 nm to R fcc= 0.12394 nm and, in addition, a change in density.Compute the percentage volume change per atom (Vfinal |-V initial |)/ (V; initial |) associated with this reaction . Indicate whetherthere is an expansion or zontraction taking place during the processarrow_forwardWhich of the following are true regarding crystalline and non-crystalline materials at the atomic scale? Select one or more: a. Crystalline materials show no long-range order b. There are an infinite number of crystal systems and lattices possible C. Density of packing is higher for crystalline materials d. Bond energy is lower for noncrystalline materials Materials which are not crystalline are referred to as amorphous Bond length is shorter for crystalline versus noncrystalline materials e.arrow_forward
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