Chapter 3, Problem 3D.4E

Interpretation Introduction

Interpretation:

Molecular mass of compound that takes 2.7 longer than ${\text{XeF}}_2$ has to be determined.

Concept Introduction:

Effusion is explained as movement of the gas molecule through small hole. Diffusion can be explained as when one gas molecule mix with another gas molecule by random motion.

Graham’s law of effusion gives relation of rate of effusion with molar mass. Rate of effusion and square root of molar mass are inversely related. The mathematical expression is as follows:

  $\frac{\text{Effusion rate of A}}{\text{Effusion rate of B}}=\sqrt{\frac{M_{\text{B}}}{M_{\text{A}}}}$

Here,

$M_{\text{B}}$ is molar mass of gas $\text{B}$.

$M_{\text{A}}$ is molar mass of gas $\text{A}$.