Glencoe Physics: Principles and Problems, Student Edition
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN: 9780078807213
Author: Paul W. Zitzewitz
Publisher: Glencoe/McGraw-Hill
bartleby

Concept explainers

Question
Book Icon
Chapter 25, Problem 92A

(a)

To determine

To write:

The expression for the efficiency of the transformer in percent using the power relationship.

(a)

Expert Solution
Check Mark

Answer to Problem 92A

The expression for the efficiency of power is Efficiency e=PsPp×100 .

Explanation of Solution

Given:

For a step down transformer:

Efficiency: 92.5%

Voltage of secondary Vs : 28.0 V

Voltage of primary Vp : 125 V

Current: 25.0 A

Formula used:

The formula to calculate the efficiency of power for transformer is given by,

  e=PsPp×100

Where,

  Ps : Secondary Power

  Pp : Primary Power

  e : Efficiency

Calculation:

To write the expression of the efficiency of transformer in percent, it is written as

  e=PsPp×100

Where,

  Ps : Secondary Power

  Pp : Primary Power

  e : Efficiency

Conclusion:

The expression for the efficiency of power is Efficiency e=PsPp×100 .

(b)

To determine

To calculate:

The current in the primary circuit.

(b)

Expert Solution
Check Mark

Answer to Problem 92A

The current in the primary circuit is 6.05A .

Explanation of Solution

Given:

For a step down transformer:

Efficiency: 92.5%

Voltage of secondary Vs : 28.0 V

Voltage of primary Vp : 125 V

Current: 25.0 A

Formula used:

For the secondary power

  Ps=VsIs

For the primary current,

  Ip=PpVp

Where,

  Vs : Voltage of secondary

  Ip : Primary Current

  Vp : Voltage of primary

  Ps : Secondary power

Calculation:

In the First step calculate the secondary power and primary power to find the primary current,

Secondary power is given by the formula,

  Ps=VsIs

Substitute all the given values in the above formula,

  =(28.0)×(25.0)

  Ps = 7.00×102 W

Secondary power is 7.00×102 W

Now calculate the primary power, which is given by the formula,

  Pp=(100)×Pse

Substitute all the given values in the above formula,

  =(100)×(7.00×102)92.5 = 757 W

  Pp=757 W

Primary power is 757 W

Now in the last step the primary current is found,

The formula for primary current is given by,

  Ip=PpVp

Substituting all the given values in the above formula

  Ip=(757125) W= 6.05 A

  Ip=6.05 A

Conclusion:

Hence the current in the primary circuit is 6.05 A.

(c)

To determine

To calculate:

Therate of thermal energy generated.

(c)

Expert Solution
Check Mark

Answer to Problem 92A

Thermal energy will be produced at the rate of 57 J/s. This is the difference between the input power (757 W) and the output power (700 W)

Explanation of Solution

thermal energy can be calculated by taking the difference between the Input power that is the primary power and the output power that is the secondary power.

From the above calculation,

Input power = 757 W

Output Power = 700 W

Thermal Energy= Input Power- Output Power

  = (757750) W

  = 57 W

Conclusion:

Hence the rate at which thermal energy is generated is 57 W.

Chapter 25 Solutions

Glencoe Physics: Principles and Problems, Student Edition

Ch. 25.1 - Prob. 11SSCCh. 25.1 - Prob. 12SSCCh. 25.1 - Prob. 13SSCCh. 25.1 - Prob. 14SSCCh. 25.1 - Prob. 15SSCCh. 25.2 - Prob. 16PPCh. 25.2 - Prob. 17PPCh. 25.2 - Prob. 18SSCCh. 25.2 - Prob. 19SSCCh. 25.2 - Prob. 20SSCCh. 25.2 - Prob. 21SSCCh. 25.2 - Prob. 22SSCCh. 25.2 - Prob. 23SSCCh. 25 - Prob. 24ACh. 25 - Prob. 25ACh. 25 - Prob. 26ACh. 25 - Prob. 27ACh. 25 - Prob. 28ACh. 25 - Prob. 29ACh. 25 - Prob. 30ACh. 25 - Prob. 31ACh. 25 - Prob. 32ACh. 25 - Prob. 33ACh. 25 - Prob. 34ACh. 25 - Prob. 35ACh. 25 - Prob. 36ACh. 25 - Prob. 37ACh. 25 - Prob. 38ACh. 25 - Prob. 39ACh. 25 - Prob. 40ACh. 25 - Prob. 41ACh. 25 - Prob. 42ACh. 25 - Prob. 43ACh. 25 - Prob. 44ACh. 25 - Prob. 45ACh. 25 - Prob. 46ACh. 25 - Prob. 47ACh. 25 - Prob. 48ACh. 25 - Prob. 49ACh. 25 - Prob. 50ACh. 25 - Prob. 51ACh. 25 - Prob. 52ACh. 25 - Prob. 53ACh. 25 - Prob. 54ACh. 25 - Prob. 55ACh. 25 - Prob. 56ACh. 25 - Prob. 57ACh. 25 - Prob. 58ACh. 25 - Prob. 59ACh. 25 - Prob. 60ACh. 25 - Prob. 61ACh. 25 - Prob. 62ACh. 25 - Prob. 63ACh. 25 - Prob. 64ACh. 25 - Prob. 65ACh. 25 - Prob. 66ACh. 25 - Prob. 67ACh. 25 - Prob. 68ACh. 25 - Prob. 69ACh. 25 - Prob. 70ACh. 25 - Prob. 71ACh. 25 - Prob. 72ACh. 25 - Prob. 73ACh. 25 - Prob. 74ACh. 25 - Prob. 75ACh. 25 - Prob. 76ACh. 25 - Prob. 77ACh. 25 - Prob. 78ACh. 25 - Prob. 79ACh. 25 - Prob. 80ACh. 25 - Prob. 81ACh. 25 - Prob. 82ACh. 25 - Prob. 83ACh. 25 - Prob. 84ACh. 25 - Prob. 85ACh. 25 - Prob. 86ACh. 25 - Prob. 87ACh. 25 - Prob. 88ACh. 25 - Prob. 89ACh. 25 - Prob. 90ACh. 25 - Prob. 91ACh. 25 - Prob. 92ACh. 25 - Prob. 93ACh. 25 - Prob. 94ACh. 25 - Prob. 95ACh. 25 - Prob. 96ACh. 25 - Prob. 97ACh. 25 - Prob. 98ACh. 25 - Prob. 99ACh. 25 - Prob. 100ACh. 25 - Prob. 1STPCh. 25 - Prob. 2STPCh. 25 - Prob. 3STPCh. 25 - Prob. 4STPCh. 25 - Prob. 5STPCh. 25 - Prob. 6STPCh. 25 - Prob. 7STP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON