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(a)
To calculate:
EMF of secondary circuit.
(a)
Answer to Problem 74A
EMF of secondary circuit is 3.6×103 V.
Explanation of Solution
Given:
Vp=120 V
Ns=15000
Np=500
Formula used:
VpVs=NpNs
where,
Vs = effective potential difference of secondary coil
Np = No of turns of primary coil
Vp = effective potential difference of primary coil
Ns = No of turns of secondary coil
Calculation:
EMF of secondary circuit can be calculated by the formula,
VpVs=NpNs
Rearranging the above formula,
Vs=Vp×NsNp
Substitutitng the values in above formula,
=(120)(15000)500
3.6×103 V
Conclusion:
Hence EMF of secondary circuit is 3.6×103 V.
(b)
To calculate:
Current in the primary circuit.
(b)
Answer to Problem 74A
Current in the primary circuit is 9.0×10 A.
Explanation of Solution
Given:
Vs=3600 V
Is=3.0 A
Vp=120 V
Formula used:
VpIp=VsIs
where,
Vs = effective potential difference of secondary coil
Is = current of primary coil
Vp = effective potential difference of primary coil
Ip = current of secondary coil
Calculation:
Current in the primary circuit can be calculated by the formula,
VpIp=VsIs
Rearranging the above formula,
Ip=VsIsVp
Substituting the values in above formula,
=(3600)(3.0)120
= 9.0×10 A
Conclusion:
Hencecurrent in the primary circuit is 9.0×10 A.
(c)
To calculate:
Power drawn by the primary circuit and secondary circuit.
(c)
Answer to Problem 74A
Power drawn by the primary circuit and secondary circuit is 1.1×104 W.
Explanation of Solution
Given:
Vs=3600 V
Is=3.0 A
Vp=120 V
Ip=9.0×10 A
Formula used:
VpIp=VsIs
where,
Vs = effective potential difference of secondary coil
Is = current of primary coil
Vp = effective potential difference of primary coil
Ip = current of secondary coil
Calculation:
Power drawn by the primary circuit can be calculated by the formula,
= VpIp
Substituting the values in above formula,
=(120)(9.0×10)
= =1.1×104 W
Power drawn by the secondary circuit can be calculated by the formula,
= VsIs
Substituting the values in above formula,
=(3600)(3.0)
=1.1×104 W
Conclusion:
Hencepower drawn by the primary circuit and secondary circuit is 1.1×104 W.
Chapter 25 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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