Chapter 25, Problem 97A

To determine

To calculate:

The amount of charge in capacitor $\left(q\right)$ .

Answer to Problem 97A

The amount of charge on capacitor is $1.1\times {10}^{-3}$ C.

Explanation of Solution

Given:

Capacitance of Capacitor|: $22$ µ F

Voltage: $48$ V

Formula Used:

Formula to calculate the charge on capacitor is given by,

  $c=\frac{q}{\Delta V}$

Where,

  $c$ : Capacitance of Capacitor

  $q$ : Charge on capacitor

  $\Delta V$ : Voltage

Calculation:

Formula to calculate the charge on capacitor is given by,

  $c=\frac{q}{\Delta V}$

To find the charge on the capacitor rearrange the formula,

  $q=C\Delta V$

Substitute all the given values in the above formula,

  $q$$=$$\left(22\times {10}^{-6}\right)\times \left(48\right)$$=$$1.1\times {10}^{-3}$ C

  $q=1.1\times {10}^{-3}$ C

Conclusion:

Hence, the charge on the capacitor is $1.1\times {10}^{-3}$ C.