Chapter 25, Problem 40A

To determine

To Calculate: The potential difference for a generator deliver for an external circuit.

Answer to Problem 40A

  $4.0\times {10}^2\text{V}$

Explanation of Solution

Given:

Maximum Potential Difference: $56\text{5}\text{V}$ .

Formula Used:

The effective potential difference is:

  $V_{eff}=\frac{V_{\max }}{\sqrt{2}}$

Where,

  $V_{eff}$ : Effective Potential Difference

  $V_{\max }$ : Maximum Potential Difference

Calculation:

To calculate the effective potential difference,

  $V_{eff}=\frac{V_{\max }}{\sqrt{2}}$

Now, substitute all the values in the given formula,

  $V_{eff}$ $=$ $\frac{565V}{\sqrt{2}}$

The value of $\sqrt{2}$ is $1.414$ .

  $V_{eff}$ $=$ $\frac{\text{565}\text{V}}{1.414}$

  $V_{eff}$ $=$ $4.0\times {10}^2\text{V}$

Conclusion:

Hence,the potential difference for a generator deliver for an external circuitis $4.0\times {10}^{\text{2}}\text{V}$ .