Concept explainers
(a)
To calculate:Effective potential difference.
(a)
Answer to Problem 5PP
Effective potential differenceis
Explanation of Solution
Given:
Maximum potential difference,
Formula used:
The formula to calculate effective voltage is,
Where,
Calculation:
Effective potential difference can be calculated by the formula,
Conclusion:
Effective potential differenceis
(b)
To calculate:Effective current through the lamp.
(b)
Answer to Problem 5PP
Effective current of the lamp is
Explanation of Solution
Given:
Maximum current,
Formula used:
Effective current is calculated by the formula
Where,
Calculation:
The formula for effective current used is,
Substituting the values in above formula,
Conclusion:
Effective current of the lamp is
(c)
To calculate:Resistance of the lamp.
(c)
Answer to Problem 5PP
Resistance of the lamp is
Explanation of Solution
Given:
For a lamp,
Effective voltage,
Effective current,
Formula used:
Resistance is calculated by
Where,
Calculation:
Resistance of the lamp can be calculated by the formula,
Conclusion:
Resistance of the lamp is
Chapter 25 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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