Chapter 25, Problem 73A

To determine

To Complete:The problem using the concept of electromagnetic inductance.

Explanation of Solution

Introduction:

An electromotive force is produced across an electrical conductor in a changing magnetic field,it is called electromagneticinduction.It is the process of using magnetic fields to produce voltage.Electromagnetic induction is used to supply power for many electrical devices.It is mostly used in electrical generators.

  $EMF=BLv\left(\sin \theta \right)$

Where,

  $EMF$ : Electromotive force

  $B$ : Magnetic field

  $L$ : Length

  $v$ : Velocity

The value of $\sin \theta$ is 1 as the direction across the field is perpendicular.

Considering above equation, the problem would be given as,

A copper wire of length $1.2\text{5 m}$ moves perpendicular through the magnetic field of $0.06-\text{T}.$ Ifthe speed at which the wire moves is $5.0\text{ m/s}$ ,then what is the EMF induced between its ends?