Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 12.2, Problem 1COMQ
With regard to a promoter, a transcriptional start site is
a. located at the
sequence and is recognized by
factor.
b. located at the
sequence and is where the first base is used as a template for transcription.
c. located at the
site and is recognized by σ factor.
d. located at the
e. site and is where the first base is used as a template for transcription.
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Students have asked these similar questions
A high rate of transcription initiation from promoters in bacteria can be achieved by which of the following?
a. the presence of perfect consensus sequences at the -35 and -10 positions of the promoter.
b. the binding of an activator protein close to the promoter.
c. the presence of an UP element immediately upstream of the promoter.
d. a and c, but not b
e. a, b, and c
Your investors are concerned that the GasP protein might not be sufficiently produced under normal laboratory conditions. They suggest controlling the transcription of the gasP gene using a chemical that will “trigger” its transcription.
a. What type of promoter could be used?
b. What chemical will you use to control transcription?
c. How does this method of control work?
Regarding transcriptional promoter sites, which of the following statements are true? Select one or more than one:
a)They are located in the gene (DNA) whose information will be transcribed
b)They are found at the 3 'end of the gene that will be transcribed
c)Some of them are called 'TATA box'
d)They are found in the DNA, 'upstream' of the gene to be transcribed.
e)They are proteins of the cytoplasm
Chapter 12 Solutions
Genetics: Analysis and Principles
Ch. 12.1 - 1. Which of the following base sequences is used...Ch. 12.1 - Prob. 2COMQCh. 12.2 - With regard to a promoter, a transcriptional start...Ch. 12.2 - Prob. 2COMQCh. 12.2 - 3. Sigma factor is needed during which stage(s) of...Ch. 12.2 - A uracil-rich sequence occurs at the end of the...Ch. 12.3 - Which RNA polymerase in eukaryotes is responsible...Ch. 12.3 - Prob. 2COMQCh. 12.3 - Prob. 3COMQCh. 12.3 - Prob. 4COMQ
Ch. 12.4 - Which of the following are examples of RNA...Ch. 12.4 - A ribozyme is a. a complex between RNA and a...Ch. 12.4 - Prob. 3COMQCh. 12.4 - Prob. 4COMQCh. 12.5 - 1. Which of the following is not a key difference...Ch. 12 - Prob. 1CONQCh. 12 - Prob. 2CONQCh. 12 - Prob. 3CONQCh. 12 - Prob. 4CONQCh. 12 - 5. Mutations in bacterial promoters may increase...Ch. 12 - Prob. 6CONQCh. 12 - 7. In Chapter 9, we considered the dimensions of...Ch. 12 - 8. A mutation within a gene sequence changes the...Ch. 12 - Prob. 9CONQCh. 12 - At the molecular level, describe how factor...Ch. 12 - Prob. 11CONQCh. 12 - What is the complementarity rule that governs the...Ch. 12 - 13. Describe the movement of the open complex...Ch. 12 - 14. Describe what happens to the chemical bonding...Ch. 12 - Prob. 15CONQCh. 12 - Prob. 16CONQCh. 12 - Prob. 17CONQCh. 12 - Mutations that occur at the end of a gene may...Ch. 12 - If the following RNA polymerases were missing from...Ch. 12 - 20. What sequence elements are found within the...Ch. 12 - 21. For each of the following transcription...Ch. 12 - 22. Describe the allosteric and torpedo models for...Ch. 12 - Which eukaryotic transcription factor(s) shown in...Ch. 12 - 24. The initiation phase of eukaryotic...Ch. 12 - A eukaryotic protein-encoding gene contains two...Ch. 12 - 26. Describe the processing events that occur...Ch. 12 - Prob. 27CONQCh. 12 - Prob. 28CONQCh. 12 - Prob. 29CONQCh. 12 - Prob. 30CONQCh. 12 - 31. In eukaryotes, what types of modifications...Ch. 12 - Prob. 32CONQCh. 12 - Prob. 33CONQCh. 12 - 34. Figure 12.21 shows the products of alternative...Ch. 12 - 35. The processing of ribosomal RNA in eukaryotes...Ch. 12 - Prob. 36CONQCh. 12 - Prob. 37CONQCh. 12 - After the intron (which is in a lariat...Ch. 12 - Prob. 1EQCh. 12 - 2. Chapter 21 describes a technique known as...Ch. 12 - Prob. 3EQCh. 12 - As described in Chapter 21 and in experimental...Ch. 12 - Prob. 5EQCh. 12 - Prob. 6EQCh. 12 - 1. Based on your knowledge of introns and pre-mRNA...Ch. 12 - Discuss the types of RNA transcripts and the...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- f you made a change in the promoter sequence in the DNA that inactivates the promoter, what would happen at the RNA level? A-Nothing, because the RNA would be made as usual B-Transcription factors would be unable to bind and the RNA polymerase would not be recruited to the DNA, so no RNA would be made. C-The mutation of the DNA would be carried through to the RNA sequence. D-The DNA helicase would not be able to recognize and bind the DNA, so the RNA would not be made. EXPLAIN WHY THE ANSWER YOU CHOOSE IS CORRECTarrow_forwardWhich of the following processes is required for the initiation of transcription in bacteria? Select one: a. binding of sigma to the promoter region b. formation of a peptide bond in the elongating polypeptide chain c. formation of a phosphodiester bond in the elongating RNA strand d. binding of DNA polymerase to the promoter regionarrow_forwardSpecific transcription factors in eukaryotes interact with enhancers, which may be a long distance from the promoter. These transcription factors then a. alter the structure of the DNA between enhancer and promoter. b. do not interact with the transcription apparatus. c. can interact with the transcription apparatus via DNA looping. d. can interact with the transcription apparatus by removing the intervening DNA.arrow_forward
- a) What is a gene promoter? b) What proteins bind to a promoter? c) What do those proteins do to control gene expression?arrow_forwardWhat is one function of TFIIH during transcription? a. Recruiting the TATA-box binding protein to the TATA-box. b. Terminating transcription via factor-dependent termination. c. Capping the 5' end of mRNA with 7-methylguanylate. d. Phosphorylating the CTD of RNA polymerase.arrow_forwarda) what is a promoter and give the element and their functions of E.coli promoter b) what are eukaryotic transcription factor and list the class 2 general transcription factors and state their functionsarrow_forward
- A scientist compares the promoter regions of two genes. Gene A’s core promoter plus proximal promoter elements encompasses 70bp. Gene B’s core promoter plus proximal promoter elements encompasses 250bp. Which of the scientist’s hypotheses is most likely to be correct? a. More transcripts will be made from Gene B. b. Transcription of Gene A involves fewer transcription factors. c. Enhancers control Gene B’s transcription. d. Transcription of Gene A is more controlled than transcription of Gene B.arrow_forwardWhich sequence is most likely to be found in a promoter? a) CGGTGTATATCGTAC b) GTACAGTCATCCCGT c) AAATCTACTACGATT d) GGGTTGGGTTGGGTTarrow_forwardA mutation that inactivates the repressor gene of the lac operon results in (a) the continuous transcription of the structural genes (b) no transcription of the structural genes (c) the binding of the repressor to the operator (d) no production of RNA polymerase (e) no difference in the rate of transcriptionarrow_forward
- Through alternative splicing, eukaryotes (a) reinforce gene inactivation (b) prevent transcription of heterochromatin (c) produce related but different proteins in different tissues (d) amplify genes to meet the requirement of high levels of a gene product (e) bind transcription factors to enhancers to activate transcriptionarrow_forwardThe promoter consensus sequence at the -10 BOX in the bio gene in E. coli was TAGACT; however, a transversion occurred which changed the G nucleotide to T, what outcome(s) are likely? a. transcription levels would decrease because the promoter would be weaker b. nothing would happen because the promoter would not change the mRNA sequence c. the mutation would block RNA polymerase from binding to the DNA d. transcription levels would increase because the promoter would be stronger e. the bio gene does not require a functional promoterarrow_forwardThe “domain-swapping” experiment that grafts the Gal4 DNA-binding domain to the LexA activation domain generates a chimeric protein that will: A) bind to the Gal4 site. B) bindto the LexA site. C) activate transcription of the LexA gene. D) activate transcription of alleukaryotic genes. E) All of the answer options are correct.arrow_forward
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