Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 12, Problem 22CONQ
Describe the allosteric and torpedo models for transcriptional termination of RNA polymerase II. Which model is more similar to p-dependent termination in bacteria and which model is more similar to
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Chapter 12 Solutions
Genetics: Analysis and Principles
Ch. 12.1 - 1. Which of the following base sequences is used...Ch. 12.1 - Prob. 2COMQCh. 12.2 - With regard to a promoter, a transcriptional start...Ch. 12.2 - Prob. 2COMQCh. 12.2 - 3. Sigma factor is needed during which stage(s) of...Ch. 12.2 - A uracil-rich sequence occurs at the end of the...Ch. 12.3 - Which RNA polymerase in eukaryotes is responsible...Ch. 12.3 - Prob. 2COMQCh. 12.3 - Prob. 3COMQCh. 12.3 - Prob. 4COMQ
Ch. 12.4 - Which of the following are examples of RNA...Ch. 12.4 - A ribozyme is a. a complex between RNA and a...Ch. 12.4 - Prob. 3COMQCh. 12.4 - Prob. 4COMQCh. 12.5 - 1. Which of the following is not a key difference...Ch. 12 - Prob. 1CONQCh. 12 - Prob. 2CONQCh. 12 - Prob. 3CONQCh. 12 - Prob. 4CONQCh. 12 - 5. Mutations in bacterial promoters may increase...Ch. 12 - Prob. 6CONQCh. 12 - 7. In Chapter 9, we considered the dimensions of...Ch. 12 - 8. A mutation within a gene sequence changes the...Ch. 12 - Prob. 9CONQCh. 12 - At the molecular level, describe how factor...Ch. 12 - Prob. 11CONQCh. 12 - What is the complementarity rule that governs the...Ch. 12 - 13. Describe the movement of the open complex...Ch. 12 - 14. Describe what happens to the chemical bonding...Ch. 12 - Prob. 15CONQCh. 12 - Prob. 16CONQCh. 12 - Prob. 17CONQCh. 12 - Mutations that occur at the end of a gene may...Ch. 12 - If the following RNA polymerases were missing from...Ch. 12 - 20. What sequence elements are found within the...Ch. 12 - 21. For each of the following transcription...Ch. 12 - 22. Describe the allosteric and torpedo models for...Ch. 12 - Which eukaryotic transcription factor(s) shown in...Ch. 12 - 24. The initiation phase of eukaryotic...Ch. 12 - A eukaryotic protein-encoding gene contains two...Ch. 12 - 26. Describe the processing events that occur...Ch. 12 - Prob. 27CONQCh. 12 - Prob. 28CONQCh. 12 - Prob. 29CONQCh. 12 - Prob. 30CONQCh. 12 - 31. In eukaryotes, what types of modifications...Ch. 12 - Prob. 32CONQCh. 12 - Prob. 33CONQCh. 12 - 34. Figure 12.21 shows the products of alternative...Ch. 12 - 35. The processing of ribosomal RNA in eukaryotes...Ch. 12 - Prob. 36CONQCh. 12 - Prob. 37CONQCh. 12 - After the intron (which is in a lariat...Ch. 12 - Prob. 1EQCh. 12 - 2. Chapter 21 describes a technique known as...Ch. 12 - Prob. 3EQCh. 12 - As described in Chapter 21 and in experimental...Ch. 12 - Prob. 5EQCh. 12 - Prob. 6EQCh. 12 - 1. Based on your knowledge of introns and pre-mRNA...Ch. 12 - Discuss the types of RNA transcripts and the...
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- Consider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination. Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds.arrow_forwardWhich serine in the CTD of RNA polymerase II is phosphorylated to recruit enzymes to add the 5’ guanosine cap? How is this phosphorylation different than the CTD phosphorylation in promoter clearance?arrow_forwardConsider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices 1.Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds. 2.Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. 3.Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. 4.Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination.arrow_forward
- Explain why inserting 5 bp of DNA at the –50 position of a eukaryotic gene decreases the rate of RNA polymerase II transcription initiation to a greater extent than inserting 10 bp at the same site.arrow_forwardAlthough initiation requires the sigma factor or sigma subunit be associated with the core RNA polymerase, in order to switch to the elongation phase of transcription, RNA polymerase must release the sigma factor and associate with elongation factors instead. What do these elongation factors do - why are they necessary for the elongation phase of transcription?arrow_forwardThe following logo plot represents the preferred cis-regulatory sequences (i.e. transcription factor binding site) of bHLH transcription factor FOSL1. C 1 2 3 4 5 6 7 8 9 10 11 position Would you expect this sequence to be recognized by a monomer, a homodimer, or a heterodimer of the protein? Explain your answer. (short phrases are sufficient; please write your answer into the template below) A- В I A -l expect FOSL1 to bind as a: (monomer, homodimer, heterodimer; please choose) B - short explanation: information content (bit) !!arrow_forward
- Describe the three models for RNAP active-center translocation during transcription initiation?arrow_forwardOnce an RNA polymerase has initiated transcription, it will release the sigma factor or sigma subunit and bind other proteins known as elongation factors before it begins moving down the DNA template doing strand elongation. Briefly explain why this is necessary - why can't RNA polymerase + sigma factor do all of transcription? Be specific.arrow_forwardOutline an experimental approach to determining the average chain growth rate for transcription in vivo. Chain growth rate is the number of nucleotides polymerized per minute per RNA chain.arrow_forward
- The CTD of the largest subunit of RNA polymerase II can be phosphorylated at multiple serine residues. What are the conditions that lead to the phosphorylated versus nonphosphorylated RNA polymerase II CTD?arrow_forward2b) Once an RNA polymerase has initiated transcription, it will release the sigma factor or sigma subunit and bind other proteins known as elongation factors before it begins moving down the DNA template doing strand elongation. Briefly explain why this is necessary - why can't RNA polymerase + sigma factor do all of transcription?arrow_forwardNegative supercoiling of DNA favors the transcription of genes because it facilitates unwinding. However, not all promoter sites are stimulated by negative supercoiling. The promoter site for topoisomerase II itself is a noteworthy exception. Negative supercoiling decreases the rate of transcription of this gene. Propose a possible mechanism for this effect and suggest a reason why it may occur.arrow_forward
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