Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Textbook Question
Chapter SRP, Problem 19P
Give structures for compounds A–D. Compound D gives a strong IR absorption band near
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As reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?
Treatment of benzoic acid (C6H5CO2H) with NaOH followed by 1-iodo-3methylbutane forms H. H has a molecular ion at 192 and IR absorptions at 3064, 3035, 2960−2872, and 1721 cm−1. Propose a structure for H.
There are several isomeric alcohols and ethers of molecular formula C5H12O. Two of these exhibit the following 1H-NMR spectra. Propose a structure for each of the isomers.
Isomer A: δ = 0.92 (t, 7.8 Hz, 3 H), 1.20 (s, 6H), 1.49 (q, 7.8 Hz, 2H), 1.85 (s, 1H) ppm
Isomer B: δ = 1.19 (s, 9 H), 3.21 (s, 3H) ppm
Chapter SRP Solutions
Organic Chemistry
Ch. SRP - 1. Arrange the compounds of each of the following...Ch. SRP - 2. Arrange the compounds of each of the following...Ch. SRP - Predict the final product from each of the...Ch. SRP - Prob. 4PCh. SRP - Write detailed mechanisms for each of the...Ch. SRP - Prob. 6PCh. SRP - Prob. 7PCh. SRP - Prob. 8PCh. SRP - Prob. 9PCh. SRP - Give stereochemical structures for compounds AD:
Ch. SRP - Prob. 11PCh. SRP - The remaining steps in the industrial synthesis of...Ch. SRP - Prob. 13PCh. SRP - Prob. 14PCh. SRP - Prob. 15PCh. SRP - Prob. 16PCh. SRP - 17. Show how you would modify the synthesis given...Ch. SRP - Prob. 18PCh. SRP - Give structures for compounds AD. Compound D gives...Ch. SRP - The tranquilizing drug meprobamate (Equanil or...Ch. SRP - Prob. 21PCh. SRP - 22. Outlined here is the synthesis of a central...Ch. SRP - 23. What are compounds A and B? Compound B has a...Ch. SRP - Prob. 24PCh. SRP - 25. The Dow process for synthesizing phenol, which...Ch. SRP - Prob. 26PCh. SRP - Prob. 27PCh. SRP - 28. Compound Y shows prominent IR absorption...Ch. SRP - Prob. 29PCh. SRP - Consider this reaction involving peracetic acid:...Ch. SRP - 31. A compound (N) with the molecular formula...Ch. SRP - 32. Compound X is insoluble in aqueous sodium...Ch. SRP - Write the structures of the three products...Ch. SRP - Compound C (C9H11NO) gives a positive Tollens test...Ch. SRP - A compound X (C10H14O) dissolves in aqueous sodium...Ch. SRP - Compound Z (C5H10O) decolorizes bromine. The IR...Ch. SRP - 37. Compound W was isolated from a marine annelid...Ch. SRP - 38. Phenols generally are not changed on treatment...
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- Treatment of ketone A with ethynyllithium (HC≡CLi) followed by D3O+ afforded a compound B of molecular formula C12H13DO3, which gave an IR absorption at approximately 1715 cm−1. What is the structure of B and how is it formed?arrow_forwardThe treatment of (CH3)2C=CHCH2Br with H2O forms B (molecular formulaC5H10O) as one of the products. Determine the structure of B from its 1H NMR and IR spectra.arrow_forwardTreatment of 2-methylpropanenitrile [(CH3)2CHCN] with CH3CH2CH2MgBr, followed by aqueous acid, affords compound V, which has molecular formula C7H14O. V has a strong absorption in its IR spectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91 (triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and 2.60 (septet, 1 H) ppm. What is the structure of V? We will learn about this reaction in Chapter 20.arrow_forward
- Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.arrow_forwardAs we will learn in Chapter 17, reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?arrow_forwardCompound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forward
- The treatment of (CH3)2C=CHCH2Br with H2O forms B (molecular formula C5H10O) as one of the products. Determine the structure of B from its 1H NMR and IR spectra.arrow_forwardCompounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)arrow_forwardThe treatment of (CH3)2C = CHCH2Br with H2O forms B (molecular formula C5H10O) as one of the products. Determine the structure of B from its H NMR and IR spectra.arrow_forward
- Treatment of compound C (molecular formula C9H12O) with PCC affords D (molecular formula C9H10O). Use the 1H NMR and IR spectra of D to determine the structures of both C and D.arrow_forwardCompound X (molecular formula C10H12O) was treated with NH2NH2,−OH to yield compound Y (molecular formula C10H14). Based on the 1H NMR spectra of X and Y given below, what are the structures of X and Y?arrow_forwardCompound A, C8H10O, has the IR and 1H NMR spectra shown. Propose a structure consistent with the observed spectra, and label each peak in the NMR spectrum. Note that the absorption at 5.5 î disappears when D2O is added.arrow_forward
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