Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 8.15, Problem 8KCP
What is an alloy? What is the difference between the melt temperature of a pure metal and an alloy of this metal?
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Chapter 8 Solutions
Foundations of Materials Science and Engineering
Ch. 8.15 - Define (a) a phase in a material and (b) a phase...Ch. 8.15 - In the pure water pressure-temperature equilibrium...Ch. 8.15 - How many triple points are there in the pure iron...Ch. 8.15 - Write the equation for the Gibbs phase rule and...Ch. 8.15 - Refer to the pressuretemperature equilibrium phase...Ch. 8.15 - (a) What is a cooling curve? (b) What type of...Ch. 8.15 - Prob. 7KCPCh. 8.15 - What is an alloy? What is the difference between...Ch. 8.15 - Prob. 9KCPCh. 8.15 - What is the significance of the liquidus curve?...
Ch. 8.15 - Prob. 11KCPCh. 8.15 - Prob. 12KCPCh. 8.15 - Prob. 13KCPCh. 8.15 - Describe the mechanism that produces the...Ch. 8.15 - Can coring and surrounding occur in a...Ch. 8.15 - What is a monotectic invariant reaction? How is...Ch. 8.15 - Write equations for the following invariant...Ch. 8.15 - How are eutectic and eutectoid reactions similar?...Ch. 8.15 - Distinguish between (a) a terminal phase and (b)...Ch. 8.15 - Distinguish between (a) an intermediate phase and...Ch. 8.15 - What is the difference between a congruently...Ch. 8.15 - Consider an alloy containing 70 wt% Ni and 30 wt%...Ch. 8.15 - Consider the binary eutectic coppersilver phase...Ch. 8.15 - If 500 g of a 40 wt% Ag60 wt% Cu alloy is slowly...Ch. 8.15 - A lead-tin (PbSn) alloy consists of 60 wt%...Ch. 8.15 - A PbSn alloy (Fig. 8.12) contains 40 wt% and 60...Ch. 8.15 - An alloy of 30 wt% Pb70 wt% Sn is slowly cooled...Ch. 8.15 - Consider the binary peritectic iridiumosmium phase...Ch. 8.15 - Consider the binary peritectic iridiumosmium phase...Ch. 8.15 - Consider the binary peritectic iridiumosmium phase...Ch. 8.15 - In the copperlead (CuPb) system (Fig. 8.24) for an...Ch. 8.15 - For an alloy of Cu70 wt% Pb (Fig. 8.24), determine...Ch. 8.15 - What is the average composition (weight percent)...Ch. 8.15 - Consider an Fe4.2 wt% Ni alloy (Fig. 8.17) that is...Ch. 8.15 - Consider an Fe5.0 wt% Ni alloy (Fig. 8.17) that is...Ch. 8.15 - Determine the weight percent and composition in...Ch. 8.15 - Determine the composition in weight percent of the...Ch. 8.15 - Draw, schematically, the liquidus and the solidus...Ch. 8.15 - Consider the CuZn phase diagram of Figure 8.26. a....Ch. 8.15 - Consider the nickelvanadium phase diagram of...Ch. 8.15 - Consider the titaniumaluminum phase diagram of...Ch. 8.15 - What is the composition of point y in Figure...Ch. 8.15 - In Figure 8.12, determine the degree of freedom,...Ch. 8.15 - The cooling curve of an unknown metal shows a...Ch. 8.15 - In the PbSn phase diagram (Fig. 8.12), answer the...Ch. 8.15 - Based on the CuAg phase diagram in Figure P8.23,...Ch. 8.15 - Based on the PdAg phase diagram in Figure EP 8.3,...Ch. 8.15 - Prob. 49SEPCh. 8.15 - Derive the lever rule for the amount in weight...Ch. 8.15 - Based on the AlNi phase diagram given in Figure...Ch. 8.15 - Prob. 52SEPCh. 8.15 - Based on the Al2O3SiO2 phase diagram in Figure...Ch. 8.15 - (a) Design a CuNi alloy that will be completely...Ch. 8.15 - Prob. 55SEPCh. 8.15 - Given that Pb and Sn have similar tensile...Ch. 8.15 - Consider the sugarwater phase diagram shown in...Ch. 8.15 - In Figure P8.57, if 60 g of water and 140 g of...Ch. 8.15 - In Figure P8.57, if 30 g of water and 170 g of...Ch. 8.15 - At 80C, if the wt% of sugar is 80%, (a) what...Ch. 8.15 - (a) Based on the phase diagram in Figure P8.61,...Ch. 8.15 - Referring to Figure P8.61. explain what happens as...Ch. 8.15 - Referring to Figure P8.61, (a) explain what...Ch. 8.15 - Using Figure P8.40, explain what the phase diagram...Ch. 8.15 - Using Figure P8.40. explain why, according to the...Ch. 8.15 - (a) In the TiAl phase diagram. Figure P8.42, what...Ch. 8.15 - Draw an approximate hypothetical phase diagram for...Ch. 8.15 - Draw the hypothetical phase diagram for a binary...
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- A 1.5-kg specimen of a 88 wt% Pb-12 wt% Sn alloy (Animated Figure 9.8) is heated to 220°C; at this temperature it is entirely an a- phase solid solution. The alloy is to be melted to the extent that 50% of the specimen is liquid, the remainder being the a phase. This may be accomplished either by heating the alloy or changing its composition while holding the temperature constant. (a) To what temperature must the specimen be heated? i °C (b) How much tin must be added to the 1.5-kg specimen at 220°C to achieve this state? i kgarrow_forwardA 80%Ag-20%Cu alloy is slowly heated from room temperature (25°C).Determine (1) At what temperature does the first liquid phase form and what is this liquid’s composition?(2) At what temperature does all solid melt and what is the last remaining solid’s composition?arrow_forwardDetermine the quenching and normalizing process temperatures of 2 different steels containing 0.6% C and 1.3% C (Ac3 and Acm will be considered linear)arrow_forward
- Why are the most precipitation-hardened alloys suitable only for low-temperature applications?arrow_forwardHow does the undercooling of a metallic material during heat treatment relate to it's mechanical properties?arrow_forwardWhat kinds of dispersion hardened alloys can retain their strength up to 1000 ° C?arrow_forward
- Referring to Figure 1, answer the following: What are the liquidus and solidus temperatures for an 80%Pb20%Tl alloy? What is the composition of the solid solution phase for the aforementioned alloy once we hit the liquidus temperature upon cooling? For the same alloy above, use the inverse lever rule to calculate the %solid and %liquid at 325Carrow_forwardThe TTT diagram for a 1076 eutectoid steel is given: What is the heat treatment process to form 50% Coarse Pearlite + 50% Martensite. 800 A 1400 Eutectoid temperature 700 A 1200 600 1000 500 800 400 A 600 300 M(start) 200 50% 400 M + A M(50%) M(90%) 100 200 10-1 1 10 102 103 104 105 Time (s) Temperature (°C) Temperature (°F)arrow_forwardWhat is a eutectic composition?arrow_forward
- What is the bernoulli effect?arrow_forwardRefer to the Time Temperature Transformation (TTT) diagram given in Appendix A: (i) Determine the resulting microstructure for 0.8% carbon steel if the steel is rapidly cooled from the y region to 280°C within 5 seconds. (i) If the resulting microstructure in Question 6b (i) above is reheat to 300°C within 1 minute and hold for 1 hour at remain temperature, then and then rapidly quenched to room temperature, determine its final microstructure. (ii) If the resulting microstructure in Question 6b (i) above is reheat to 300°C within 1 minute and hold for 16 minutes at remain temperature, then and then rapidly quenched to room temperature, determine its final microstructure. (iv) Arrange the mircostructures 6 (b) (i,i and i) from the lowest to the highest hardnes value. (v) Sketch the thermal history from Question 6b (i) to (ii) on a TTT diagram.arrow_forwardQuestion-3 If 500 g of a 40 wt % Ag - 60 wt % Cu alloy is slowly cooled from 1000°C to just below 780°C: (a) How many grams of liquid and proeutectic alpha are present at 850°C? (b) How many grams of liquid and proeutectic alpha are present at 780°C + AT ? (c) How many grams of alpha are present in the eutectic structure at 780°C - AT ? (d) How many grams of beta are present in the eutectic structure at 780°C - AT ? Atomic percent silver °C °F 10 20 30 40 50 60 70 80 90 1100 1084.5 1900 1000 961.93 1700 900 L+a 1600 L+B 800 780 1400 7.9 719 91.2 700 1200 600 a+B 1000 500 850 400 Cu 10 30 40 50 60 70 80 90 Ag Weight percent silver 20arrow_forward
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