Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are in series? Which are in parallel? As a check on your assumptions, be sure that the elements in series have the same current and that the elements in parallel have the same voltage. Restrict your decisions to single elements not combinations of elements. Fig 7.64

Question

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Answer 1

Textbook Question

Chapter 7, Problem 1P

Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are in series? Which are in parallel? As a check on your assumptions, be sure that the elements in series have the same current and that the elements in parallel have the same voltage. Restrict your decisions to single elements not combinations of elements.

Chapter 7, Problem 1P, Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are

Fig 7.64

Expert Solution

To determine

(a)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 1

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 2

Since same current is flowing through $R1,R2 and E$ .

So, $R1,R2 and E$ are in series.

Also, since same voltage is flowing through $R3,R4 and R5$ .

So, $R3,R4 and R5$ are in parallel.

Conclusion:

Hence, $R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Expert Solution

To determine

(b)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R3,R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 3

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 4

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

And since same voltage is flowing through $R3,R4 and R2$ .

So, $R3,R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R3,R4 and R2$ elements are in parallel.

Expert Solution

To determine

(c)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 5

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 6

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

Since same voltage is across $R4 and R2$ .

So, $R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R4 and R2$ elements are in parallel.

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04:39

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Answer 2

Textbook Question

Chapter 7, Problem 1P

Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are in series? Which are in parallel? As a check on your assumptions, be sure that the elements in series have the same current and that the elements in parallel have the same voltage. Restrict your decisions to single elements not combinations of elements.

Chapter 7, Problem 1P, Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are

Fig 7.64

Expert Solution

To determine

(a)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 1

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 2

Since same current is flowing through $R1,R2 and E$ .

So, $R1,R2 and E$ are in series.

Also, since same voltage is flowing through $R3,R4 and R5$ .

So, $R3,R4 and R5$ are in parallel.

Conclusion:

Hence, $R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Expert Solution

To determine

(b)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R3,R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 3

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 4

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

And since same voltage is flowing through $R3,R4 and R2$ .

So, $R3,R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R3,R4 and R2$ elements are in parallel.

Expert Solution

To determine

(c)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 5

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 6

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

Since same voltage is across $R4 and R2$ .

So, $R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R4 and R2$ elements are in parallel.

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04:39

Answer 3

Textbook Question

Chapter 7, Problem 1P

Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are in series? Which are in parallel? As a check on your assumptions, be sure that the elements in series have the same current and that the elements in parallel have the same voltage. Restrict your decisions to single elements not combinations of elements.

Chapter 7, Problem 1P, Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are

Fig 7.64

Expert Solution

To determine

(a)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 1

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 2

Since same current is flowing through $R1,R2 and E$ .

So, $R1,R2 and E$ are in series.

Also, since same voltage is flowing through $R3,R4 and R5$ .

So, $R3,R4 and R5$ are in parallel.

Conclusion:

Hence, $R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Expert Solution

To determine

(b)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R3,R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 3

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 4

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

And since same voltage is flowing through $R3,R4 and R2$ .

So, $R3,R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R3,R4 and R2$ elements are in parallel.

Expert Solution

To determine

(c)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 5

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 6

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

Since same voltage is across $R4 and R2$ .

So, $R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R4 and R2$ elements are in parallel.

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04:39

Answer 4

Textbook Question

Chapter 7, Problem 1P

Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are in series? Which are in parallel? As a check on your assumptions, be sure that the elements in series have the same current and that the elements in parallel have the same voltage. Restrict your decisions to single elements not combinations of elements.

Chapter 7, Problem 1P, Which elements (individual elements, not combinations of elements) of the networks in Fig. 7.64. are

Fig 7.64

Expert Solution

To determine

(a)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 1

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 2

Since same current is flowing through $R1,R2 and E$ .

So, $R1,R2 and E$ are in series.

Also, since same voltage is flowing through $R3,R4 and R5$ .

So, $R3,R4 and R5$ are in parallel.

Conclusion:

Hence, $R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Expert Solution

To determine

(b)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R3,R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 3

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 4

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

And since same voltage is flowing through $R3,R4 and R2$ .

So, $R3,R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R3,R4 and R2$ elements are in parallel.

Expert Solution

To determine

(c)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 5

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 6

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

Since same voltage is across $R4 and R2$ .

So, $R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R4 and R2$ elements are in parallel.

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04:39

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

To determine

(a)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 1

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 2

Since same current is flowing through $R1,R2 and E$ .

So, $R1,R2 and E$ are in series.

Also, since same voltage is flowing through $R3,R4 and R5$ .

So, $R3,R4 and R5$ are in parallel.

Conclusion:

Hence, $R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Expert Solution

To determine

(b)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R3,R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 3

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 4

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

And since same voltage is flowing through $R3,R4 and R2$ .

So, $R3,R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R3,R4 and R2$ elements are in parallel.

Expert Solution

To determine

(c)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 5

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 6

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

Since same voltage is across $R4 and R2$ .

So, $R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R4 and R2$ elements are in parallel.

Answer 8

Expert Solution

To determine

(a)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 1

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 2

Since same current is flowing through $R1,R2 and E$ .

So, $R1,R2 and E$ are in series.

Also, since same voltage is flowing through $R3,R4 and R5$ .

So, $R3,R4 and R5$ are in parallel.

Conclusion:

Hence, $R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

(a)

The elements of the network that are in series and in parallel.

Answer 13

Answer to Problem 1P

$R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Answer 14

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 1

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 2

Since same current is flowing through $R1,R2 and E$ .

So, $R1,R2 and E$ are in series.

Also, since same voltage is flowing through $R3,R4 and R5$ .

So, $R3,R4 and R5$ are in parallel.

Conclusion:

Hence, $R1,R2 and E$ elements are in series and $R3,R4 and R5$ elements are in parallel.

Answer 15

Expert Solution

To determine

(b)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R3,R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 3

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 4

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

And since same voltage is flowing through $R3,R4 and R2$ .

So, $R3,R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R3,R4 and R2$ elements are in parallel.

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

(b)

The elements of the network that are in series and in parallel.

Answer 20

Answer to Problem 1P

$R1 and E$ Elements are in series and $R3,R4 and R2$ elements are in parallel.

Answer 21

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 3

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 4

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

And since same voltage is flowing through $R3,R4 and R2$ .

So, $R3,R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R3,R4 and R2$ elements are in parallel.

Answer 22

Expert Solution

To determine

(c)

The elements of the network that are in series and in parallel.

Answer to Problem 1P

$R1 and E$ Elements are in series and $R4 and R2$ elements are in parallel.

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 5

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 6

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

Since same voltage is across $R4 and R2$ .

So, $R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R4 and R2$ elements are in parallel.

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

To determine

(c)

The elements of the network that are in series and in parallel.

Answer 27

Answer to Problem 1P

$R1 and E$ Elements are in series and $R4 and R2$ elements are in parallel.

Answer 28

Explanation of Solution

Given:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 5

Concept Used:

Elements in the series have the same current.

Elements in the parallels have the same voltage.

Calculation:

A network is given as below.

Introductory Circuit Analysis (13th Edition), Chapter 7, Problem 1P , additional homework tip 6

Since same current is flowing through $R1 and E$ .

So, $R1 and E$ are in series.

Since same voltage is across $R4 and R2$ .

So, $R4 and R2$ are in parallel.

Conclusion:

Hence, $R1 and E$ elements are in series and $R4 and R2$ elements are in parallel.

Answer 29

Ch. 7 - Which elements (individual elements, not...Ch. 7 - Repeat Problem 1 for the networks of Fig. 7.65....Ch. 7 - Determine RT for the networks in Fig. 7.66. Fig....Ch. 7 - Determine RT for the networks in Fig. 7.67. Fig....Ch. 7 - Find the total resistance for the configuration of...Ch. 7 - The total resistance RT for the network of Fig....Ch. 7 - For the network in Fig. 7.70. a. Does...Ch. 7 - For the network in Fig. 7.71: a. Determine RT. b....Ch. 7 - For the network of Fig. 7.72: a. find the currents...Ch. 7 - For the network of Fig. 7.73: Find the voltages V3...

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