Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 5.7, Problem 29AAP
To determine
The diffusivity
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Chapter 5 Solutions
Foundations of Materials Science and Engineering
Ch. 5.7 - Prob. 1KCPCh. 5.7 - Write an equation for the number of vacancies...Ch. 5.7 - Prob. 3KCPCh. 5.7 - Prob. 4KCPCh. 5.7 - Describe the substitutional and interstitial...Ch. 5.7 - Prob. 6KCPCh. 5.7 - What factors affect the diffusion rate in solid...Ch. 5.7 - Write the equation for Ficks second law of...Ch. 5.7 - Prob. 9KCPCh. 5.7 - Prob. 10KCP
Ch. 5.7 - (a) Calculate the equilibrium concentration of...Ch. 5.7 - Prob. 12AAPCh. 5.7 - Determine the diffusion flux of zinc atoms in a...Ch. 5.7 - The diffusion flux of copper solute atoms in...Ch. 5.7 - Prob. 15AAPCh. 5.7 - Prob. 16AAPCh. 5.7 - Prob. 17AAPCh. 5.7 - A gear made of 1020 steel (0.20 wt% C) is to be...Ch. 5.7 - Prob. 19AAPCh. 5.7 - The surface of a steel gear made of 1020 steel...Ch. 5.7 - Prob. 21AAPCh. 5.7 - If boron is diffused into a thick slice of silicon...Ch. 5.7 - Prob. 23AAPCh. 5.7 - Prob. 24AAPCh. 5.7 - Prob. 25AAPCh. 5.7 - Prob. 26AAPCh. 5.7 - Prob. 27AAPCh. 5.7 - Prob. 28AAPCh. 5.7 - Prob. 29AAPCh. 5.7 - Prob. 30AAPCh. 5.7 - The diffusivity of copper atoms in the aluminum...Ch. 5.7 - Prob. 32AAPCh. 5.7 - Prob. 33SEPCh. 5.7 - Prob. 34SEPCh. 5.7 - Prob. 37SEPCh. 5.7 - Prob. 38SEPCh. 5.7 - The activation energy of nickel atoms in FCC iron...Ch. 5.7 - Prob. 40SEPCh. 5.7 - The self-diffusion of iron atoms in BCC iron is...Ch. 5.7 - Would you expect the diffusion rate of copper...Ch. 5.7 - Would you expect the diffusion rate of copper...Ch. 5.7 - Prob. 44SEPCh. 5.7 - Prob. 45SEPCh. 5.7 - Prob. 46SEPCh. 5.7 - Prob. 47SEPCh. 5.7 - Prob. 48SEPCh. 5.7 - Prob. 49SEPCh. 5.7 - Prob. 50SEP
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- The activation energy for the diffusion of copper in silver is 193,000 J/mol. Calculate the diffusion coefficient at 1200 K (927C), given that D at 1000 K (727C) is 1.0 x10^-14 m2 /s.arrow_forwardCarbon is allowed to diffuse through a steel plate 11 mm thick. The concentrations of carbon at the two faces are 0.85 and 0.42 kg C/m³ in Fe, which are maintained constant. If the preexponential and activation energy are 6.2 x 107 m2/s and 80,000 J/mol, respectively, compute the temperature (in K) at which the diffusion flux is 6.5 x 10-10 kg/m2-s. Karrow_forwardThe diffusion coefficient for carbon in BCC iron at 400C and 900C is given as 3.80x10-13 and 1.70x-10m2/s respectively. Determine the temperature (in degrees C) at which a specimen of BCC iron has to be carburized for 150 minutes to produce the same diffusion result as at 900C for one hour.arrow_forward
- What temperature is required to obtain 0.4%C at a distance of 0.3 mm beneath the surface of a 0.22% C steel in 2h, when 1.1% C is present at the surface? Assume that the iron is FCC. (Please see figure 5.12 below for diffusion coefficient data. Please use your notes for a table of erf() function values Diffusion coefficient D (cm²/s) ܐ ܐ ܐ ܐ 10- 10-5 10- 10-10 10-11 10-12 10-13 10-14 10-15 Temperature (°C) 2000 1500 1200 1000 900 800 700 600 Cin graphite Mg in MgO Ca in Cao Hin FCC iron C in FCC iron Fe in FCC iron Fe in BCC iron H in BCC iron C in BCC iron Fe in FeO 500 5 6 7 8 9 10 11 12 13 104 T(K) Figure 5-12 The diffusion coefficient D as a function of reciprocal temperature for some metals and ceramics. In this Arrhenius plot, D represents the rate of the diffusion process. A steep slope denotes a high activation energy.arrow_forwardAnswer in a brief and concise essay. 1. Why does diffusion in solids important?arrow_forwardMechanical Engineering At approximately what temperature (in Kelvin) would a specimen of an alloy have to be carburized for 1.3 h to produce the same diffusion result as at 760°C for 14 h? Assume that values for Do and Qdare 3.6 x 10-6 m²/s and 163 kJ/mol, respectively.arrow_forward
- Compare the diffusion coefficients (in cm²/s) of nitrogen in BCC and FCC iron at the allotropic transformation temperature of 912°C. Decc -153606 X Your response differs from the correct answer by more than 10%. Double check your calculations, cm²/s -1976-7 Dicc x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. cm2/sarrow_forwardRank the magnitudes of the diffusion coefficients from greatest to least for the following systems: N in Fe at 700°C Cr in Fe at 700°C N in Fe at 900°C Cr in Fe at 900°C Now justify this ranking. (Note: Both Fe and Cr have the BCC crystal structure, and the atomic radii for Fe, Cr, and N are 0.124, 0.125, and 0.065 nm, respectively. You may also want to refer to Section 5.4.)arrow_forwardQuestion 1Helium gas is contained in a cylinder by a gas-tight piston which can beassumed to move without friction. The gas occupies a volume of 1 x 10^-3m^3 temperature of 300K and a pressure of 1 x 10^5 Pa.(a) Calculate :i.the number of helium atoms in the container,ii.the total KE of the helium atoms(b) Energy is now supplied to the gas in such a way that the gas expands andthe temperature remains constant at 300K. State, and explain what changes, if any, will have occurred in the following quantities :i. The internal energy of the gasii. The root-mean-square speed of the helium atomsiii. The density of the gas.(Given : Boltzmann's constant = 1.38 x 10^23 JK^-1)arrow_forward
- 6. (20%) Pure zinc is to be diffused into the copper by dipping copper into molten zinc at 450°C. Calculate how long would take to obtain 10wt% zinc at a depth of 0.5 mm beneath the copper surface. Is this commercially feasible? What practical problems might arise if we raise the temperature to 1000°C ? Use Table below for error function values as needed. At 450°C, the diffusion coefficient D = 6.3 10-17 m²/s.arrow_forwardThe diffusion coefficients for species A in metal B are given at two temperatures: D (m²/s) 8.54 x 10-17 8.39× 10-16 i (b) Determine the value of Do. (a) Determine the value of the activation energy Qd (in J/mol). i J/mol i T (°C) (c) What is the magnitude of D at 1190°C? 1020 1290 m²/s (Use scientific notation.) m²/s (Use scientific notation.)arrow_forwardProblem 1 A sheet of BCC iron 1 mm thick was exposed to a carburizing gas atmosphere on one side and a decarburizing atmosphere on the other side at 725°C. After having reached steady state, the iron was quickly cooled to room temperature. The carbon concentrations at the two surfaces of the sheet were determined to be 0.012 and 0.0075 wt%. Compute the diffusion coefficient if the diffusion flux is 1.4 x 108 kg/m2-s. Hint: Use Equation 4.9(Text Book) to convert the concentrations from weight percent to kilograms of carbon per cubic meter of iron.arrow_forward
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Introduction to Diffusion in Solids; Author: Engineering and Design Solutions;https://www.youtube.com/watch?v=K_1QmKJvNjc;License: Standard youtube license