Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
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Chapter 5, Problem 63P
Interpretation Introduction
Interpretation: The structure of cis-1,2-dimethylcyclohexane needs to be drawn and its stability needs to be explained.
Concept Introduction: A compound is stable when its methyl group present in its equatorial position.
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For the following pair of molecules,
(1) Draw out the chair conformation for each molecule, flip the ring if it is possible.
(2) Compare both molecules to circle out which one is more stable.
(3) Assign the absolute configuration (R/S) on all the chiral center(s), if it applicable.
(4) Name the molecule on the left side.
VS.
Construct a model in which a tetrahedral carbon atom has four different colored model atoms attached to it- red, green, orange and white representing 4 different atoms attached to the central atom.
a) Does the atom have a plane of symmetry? why or why not?
b) Now replace the green atom in your model with a second orange atom. Now two of the groups attached to the carbon atom are identical. Does the model now have a plane of symmetry? Describe it.
c)A carbon atom has four different groups attached to the stereogenic center. Draw structural formulas for the following compound and mark stereogenic centers with as asterisk: 1-bromobutane, 2-bromobutane, 1,2-dibromobutane, 1,4-dibromobutane, 2,3-dibromobutane.
F) Circle the letter corresponding to the relationship of each pair of structures:
Identical (I), Conformers (C), Enantiomers (E) (enantiomers can have different
conformations). FIRST... determine the absolute configuration of chiral centers.
H
|
F
OH
C
H
OH
E
Chapter 5 Solutions
Organic Chemistry: Structure and Function
Ch. 5.1 - Prob. 5.3ECh. 5.1 - Prob. 5.4ECh. 5.1 - Prob. 5.5ECh. 5.2 - Prob. 5.6ECh. 5.2 - Prob. 5.8TIYCh. 5.3 - Prob. 5.9ECh. 5.3 - Prob. 5.11TIYCh. 5.3 - Prob. 5.12ECh. 5.4 - Prob. 5.13ECh. 5.4 - Prob. 5.14E
Ch. 5.4 - Prob. 5.16TIYCh. 5.4 - Prob. 5.17ECh. 5.5 - Prob. 5.18ECh. 5.5 - Prob. 5.19ECh. 5.5 - Prob. 5.20ECh. 5.6 - Prob. 5.21ECh. 5.6 - Prob. 5.22ECh. 5.6 - Prob. 5.23ECh. 5.7 - Prob. 5.24ECh. 5.7 - Prob. 5.26TIYCh. 5.7 - Prob. 5.27ECh. 5 - Prob. 5.1ECh. 5 - Prob. 5.2ECh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71P
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- For the the structure shown below, Part A) Draw the Newman projections and 3-D sawhorse structures corresponding to the lowest and highest energy conformations for rotation around the C2-C3 bond. Draw the Newman projections looking FROM THE C2 CARBON TO THE C3 CARBON (i.e. with the C2 carbon in the "front"). Part B) Determine the energy difference between the lowest and highest conformations, and be sure to clearly show each energy contribution that you are including in your calculation. 2,3-dimethylpentane ECLIPSING Interactions AB Energy kcal/mol H/H 1.0 H / Me 1.4 H/Et 1.5 H/i-Pr 1.6 H/t-Bu 3.0 Me / Me 2.6 Me / Et 2.7 Me/i-Pr 3.0 GAUCHE A. Interactions Me / Me Me / Et Me / i-Pr Me / t-Bu Et / Et Et / -Pr Et/t-Bu i-Pr/i-Pr B Energy kcal/mol 0.9 0.95 1.1 2.7 1.1 1.6 3.0 2.0arrow_forwardF) Circle the letter corresponding to the relationship of each pair of structures: Identical (1), Conformers (C), Enantiomers (E) (enantiomers can have different conformations). FIRST... determine the absolute configuration of chiral centers. I OH с OH Earrow_forwardc) Draw the most stable chair conformation for each of the following cyclohexanes. Now, "flip" the ring and redraw the molecule in the higher energy form. i) chlorocyclohexane ii) cis-1-chloro-2-methylcyclohexane iii) trans-1-methyl-3-propylcyclohexanearrow_forward
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