Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Chapter 5, Problem 1P

For each configuration in Fig. 5.88, find the individual (not combinations of) elements (voltage sources and/or resistors) that are in series.

Chapter 5, Problem 1P, For each configuration in Fig. 5.88, find the individual (not combinations of) elements (voltage

Expert Solution
Check Mark
To determine

(a)

The individual elements that are connected in series for the given configuration.

Answer to Problem 1P

The individual elements that are connected in series for the given configuration are E and R1.

Explanation of Solution

Given:

The circuit is given below.

  Introductory Circuit Analysis (13th Edition), Chapter 5, Problem 1P , additional homework tip  1

Calculation:

The given circuit is analyzed by the rules of series-parallel combination.

As per the series combination rule, E and R1 are connected in series, which is further connected in series to the combination of R2 and R3. Since only individual components are concerned, the answer would be E and R1 connected in series.

Conclusion:

  E and R1 are connected in series

Expert Solution
Check Mark
To determine

(b)

The individual elements that are connected in series for the given configuration.

Answer to Problem 1P

The individual elements that are connected in series for the given configuration are R1 and R2.

Explanation of Solution

Given:

The circuit is given below,

  Introductory Circuit Analysis (13th Edition), Chapter 5, Problem 1P , additional homework tip  2

Calculation:

The given circuit is analyzed by the rules of series-parallel combination.

As per the series combination rule, R1 and R2 are connected in series, which is further connected to R3 in parallel.

Conclusion:

  R1 and R2 are connected in series.

Expert Solution
Check Mark
To determine

(c)

The individual elements that are connected in series for the given configuration.

Answer to Problem 1P

The individual elements that are connected in series for the given configuration are E1, R1 and E2

Explanation of Solution

Given:

The circuit is given below,

  Introductory Circuit Analysis (13th Edition), Chapter 5, Problem 1P , additional homework tip  3

Calculation:

The given circuit is analyzed by the rules of series-parallel combination.

As per the series combination rule, E1, R1 and E2 are connected in series with the parallel combination of R2 and R3 .Since only individual components are concerned, the answer would be E1, R1 and E2 connected in series.

Conclusion:

  E1, R1 and E2 are connected in series.

Expert Solution
Check Mark
To determine

(d)

The individual elements that are connected in series for the given configuration.

Answer to Problem 1P

The individual elements that are connected in series for the given configuration are E and R1 connected in series. Also, R3, R4 and R5 are connected in series.

Explanation of Solution

Given:

The circuit is given below,

  Introductory Circuit Analysis (13th Edition), Chapter 5, Problem 1P , additional homework tip  4

Calculation:

The given circuit is analyzed by the rules of series-parallel combination.As per the series combination rule of resistances, E and R1 connected in series and R3, R4 and R5 connected in series. Both these combinations are connected in parallel with R2.

Conclusion:

Therefore, E and R1 as well as R3, R4 and R5 connected in series.

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Chapter 5 Solutions

Introductory Circuit Analysis (13th Edition)

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