Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 20P
To determine
The elevation and stationing of the low pointPVI, and PVT.
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A 500-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1322 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT.
Solve this problem using parabolic equation and offset method.
A 850-ft equal-tangent creat vertical cuve has its PVC at station 102+00 and elevation 1000 ft. The initial grade is 3.5% and the final grade is -3%. Determine the station of the highest point of the curve
A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and
two-lane highway with a design speed of 45 mph. Assume AASHTO Standards.
1. Determine the minimum length for the curve that is designed to meet passing sight
distance using K-value method
2. Determine the Station and Elevation of the PVC
Duoblem 1
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- A 1400-ft-long sag vertical curve (equal tangent) has a PVC at station 115 + 00 and elevation 750 ft. The initial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT.arrow_forwardA 777m equal tangent crest vertical curve has PVC at Sta 16+430 and at elevation 115m. The initial grade is 7.9% and the final grade is -3.3%. Determine the elevation (m) of PVT.arrow_forwardA +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and Elevation 300.00 on a two-lane highway with a design speed of 45 mph. Assume AASHTO Standards. 1. Determine the minimum length for the curve that is designed to meet passing sight distance using K-value method 2. Determine the Station and Elevation of the PVCarrow_forward
- Compute: A 520 ft long equal-tangent crest vertical curve connects tangents that intersect at station 340+00 and elevation 1325 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the stationing and elevation of the PVC, PVT, and high point.arrow_forwardA 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forwardQ3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation (1291.2 m). the back grade of (-8%) meet the forward grade of (+7.8%) at (PVI) station (54+00) with elevation (1281.5 m). determine the length of the curve with the stations of (PVC) and (PVT)? PVT PVC gi-(-6%) PVI g2=(+5.8%)arrow_forward
- Highway engineering: A 520-ft–long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1325 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT.arrow_forwardAn equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. Design the curve.arrow_forwardA -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 200 m on one side of the vertex of the straight grade and 100 m on the other. The station of PC is 10 + 000 and its elevation is 228 m. Determine the stationing of the lowest point of the curve. A 10+211 B. 10+200 C. 10+106 D. 10+207arrow_forward
- A crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The initial grade is 2.5% and the final grade is -4%. The length of the curve is 950 ft. Determine the following, 1. Stationing of the high point, PVC, and PVT. 2. Elevation at station 212+00, PVC, high point, and PVT.arrow_forwardAn equal-tangent sag vertical curve is designed for 100 kph. The lowest point is at elevation 308.0 m. The initial grade is -2% and the final grade is +1%. What is the elevation of the PVC?arrow_forward2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00 with its elevation of 1,005 ft. Please determine following. a. PVC station b. PVC elevation C. PVT station d. PVT elevation e. The station where the highest elevation is located f. The highest elevation on the road g. The stations where the road elevation is 995 feet. Crest Vertical Curve PVI = 110+00 sta Design Speed: 70 mph Yev= 1,005' PVI Highest elevation PVI 2.5% -2.0% PVC PVT Elevation = 995 ft L=1,115 ftarrow_forward
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