Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Chapter 3, Problem 12P
To determine
The station of
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A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and
two-lane highway with a design speed of 45 mph. Assume AASHTO Standards.
1. Determine the minimum length for the curve that is designed to meet passing sight
distance using K-value method
2. Determine the Station and Elevation of the PVC
Duoblem 1
3.12 An equal-tangent crest vertical curve connects a
+3.2% and a -1.1% grade. The PVI is at station 98 +
20. Due to drainage considerations, the highest point of
the curve is at station 100+79.35. Determine the
station of the PVC and PVT, and the design speed of the
curve.
A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1%
b) determine the highest and the lowest points on this vertical curve by using the K-value.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- A +3.00% grade intersects a -2.40% at station 46+70.00 and elevation 853.48 ft. A 400.00 ft curve will be used to connect the two grades. Compute Station and elevation for the curve's endpoints.arrow_forwardA 500-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1322 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT. Solve this problem using parabolic equation and offset method.arrow_forwardA crest vertical curve joining a + 3 percent and – 4 percent grade is to be designed for 75 mph. If the tangent intersect at station (345 + 6000) at an elevation of 250 ft, determine the stations and elevations of the PVC and PVT.arrow_forward
- A plus 5.0 percent grade intersects a minus 3.0 percent grade at station 4 + 10 and at an elevation of 460.60 ft. Given that a PVC station 3+00 is utilized. Determine the length of curve, PVT station, EPVC and EPVT?arrow_forwardAn equal-tangent vertical curve is to be constructed between grades of -2.0% (initial) and +1.0% (final). The PVI is at station 110 + 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve.arrow_forwardA crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The initial grade is 2.5% and the final grade is -4%. The length of the curve is 950 ft. Determine the following, 1. Stationing of the high point, PVC, and PVT. 2. Elevation at station 212+00, PVC, high point, and PVT.arrow_forward
- A 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forwardA vertical crest curve has an approach grade +4% and a departure grade -3%. The Vertical Intersection Point level is 125m Australian Height Datum (AHD), with Chainage 3405m. It is proposed to use a curve 550m long. Calculate: Chainage and Level at TP1 Chainage and Level at TP2. Chainage and level at the apex point.arrow_forwardAn equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2 An overpass is being built over the PVI of an existing equal-tangent curve. The curve has a 70- mi/h design speed and G1 = -5%, G2= +3%. Determine the minimum necessary clearance height of the overpass and the resultant elevation of the bottom of the overpass over the PVI. (Ignore the cross-sectional width of the overpass.)arrow_forward
- An incoming grade of +1.800% meets an exiting grade of -2.500% at a PVI having station = 27+32.20 and an elevation of 231.87'. A 450.00' vertical curve will join the two tangents. Compute the following vertical alignment elements: 1) BVC station and elevation 2) Station and elevation of the high point 3) Station and elevation of all full stations and EVC on the curve Submit a spreadsheet solution with sufficient text labels so your work is easy to follow. Solutions that are too difficult to follow or are incomplete will not be graded.arrow_forwardAn equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2arrow_forwardA +0.7% grade meets a -0.4% grade at sta 2+700 and at elevation 30 m. The max allowable change in grade per station is 0.2%. Determine the length of the curve.arrow_forward
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