A 1400-ft-long sag vertical curve (equal tangent) has a PVC at station 115 + 00 and elevation 750 ft. The initial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT.

Step by step solutionProblem 1. An existing equal-tangent sag vertical curve is designed for 60 mph. The initial grade is -3% and the elevation of the PVT is 750 ft. The PVC of the curve is at station 134+00 and the PVI is at 137+00. An overpass is being constructed directly above the PVI. The overpass design assumes the driver’s eye height is 5 ft. Determine: a. the stopping sight distance b. the curve lengthc. the clearance heightd. the mid-curve offset e. the elevation of the PVIf. the elevation of the bottom of the overpass structureg. Is there a linear relationship between curve length and K-value in this problem? Note: No need to show calculations for case (g).

Determine the minimum lenght of a crest vertical curve if the grades are +4% and -2%. Design speed is 112km/h. State assumptions used in solving this problem.

An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2