Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 23P
To determine
The elevation difference between the PVT and a point on the curve at
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An equal-tangent sag vertical curve is designed for 45 mi/h. The low point is 237 ft from the PVC at station 112 + 37 and the final offset at the PVT is 19.355 ft. If the PVC is at station 110 + 00, what is the elevation difference between the PVT and a point on the curve at station 111 + 00?
An equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.
1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve
connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at
station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC
and the PVI?
[Answer: PVI station: 110+50.3; PVI elevation: 930.6']
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade lines intersect at Sta 9+000 at elev 160.50. The curve was design such that when the height of the drivers eye is 1.50 m above the payment it would just see an object whose height is 0.10 m above the pavement. Determine the max speed that a car could travel grade of 5% and a downgrade of -3%.arrow_forward1. If PVI at sta 5+650 has an elevation of 122.45 m what is the elevation of the grade tangent at station 5+684? Given grade is +3%. 2. If a 26-degree curve consists of a 14 degree simple curve, what is the angle of the transition curves?arrow_forwardAn equal tangent sag vertical curve is designed for 45 mi/h. The low point is at station 112+37 about 237 ft from the PVC and the length of the curve is 553 ft. If the PVC is at station 110+00, what is the elevation difference between the PVT and a point on the curve at station 111+00. Take the elevation of PVC as 100 ft.arrow_forward
- An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2arrow_forward1. A vertical parabolic summit curve was designed in order to have a clear sight distance of 120m. The grade lines intersect a Station 9 + 000 at elevation 160.50m. The curve was so designed such that when the height of the driver's eye to 1.50m above the pavement would just see an object whose height is 0.10m above the pavement. Determine the max. speed that a car could travel along this curve. The grade lines has an upward grade of 5% and a downward grade of -3%.arrow_forwardA symmetrical sag curve has a descending grade of -4.2% and an ascending grade of +3% intersecting at station 10 + 200, whose elevation is 100 m. The rate of change of grade is restricted to 0.55385% per station. a. What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades? b. At what distance from PC is the lowest point of the curve located? c. If a 1-m diameter culvert is placed at the lowest point of the curve with the top of the culvert buried 0.60 m below the subgrade, what will be the elevation of the invert of the culvert?arrow_forward
- A symmetrical parabolic summit curve connects two grades of +4.9% and -3.2%. It is to pass through a point "D" on the curve at station 25 + 180m . If the stationing of the grade intersection is 25 + 145m and the stationing of PVC is 24 + 979m determine the following: Length of the parabolic curve Stationing of the highest point. Difference in elevation between PVC and PVI Difference in elevation between PVC and point Darrow_forwardA 3.5% grade passing at station 49+45.00 at an elevation of 174.83 ft meets a -5.5% grade passing at station 49+55.00 at an elevation of 174.73 ft. Determine the station and elevation of the point of intersection of the two grades as well as the length of the curve, L, if the highest point on the curve must lie at station 48+61.11arrow_forwardA 750-ft equal-tangent crest vertical curve connects tangents that intersect at elevation 572 ft. The curve starts at station 15+25. The initial grade is +5% and the final grade is -3%. Determine the elevation of the middle point of the curve. O A. 589.235 O B. 564.500 O C. 575.875 D. 562.125arrow_forward
- An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75% (final). The PVI is at station 12+000.000 and at elevation 319 m. Due to a street crossing the roadway, the elevation of the roadway at station 12+071.00 must be at 324 m. Which of the following most nearly gives the elevation of the PVC in meters? * 335.0 O 330.4 339.0 330.0 348.1arrow_forwardA vertical equal-tangent, 1000 ft long, connects an initial grade of -2.5% and a final grade of +2%. The PVC of the curve is located at station 95 + 00 and has an elevation of 850 ft. At which station is the PVI of the curve located? 80 + 00 83 + 75 O 90 + 00 O 95 + 00 O 100 + 00arrow_forwardA crest vertical curves joining a +3% and -4% grade is to be designed for 90 km/h. If the tangents intersect at station 3+400,00 at an elevation of 76,00 m, determine the stations and elevations of the BVC (beginning of the vertical curve) and EVC (end of the vertical curve). Also calculate the elevations of intermediate points on the curve at the whole stations every 40m.arrow_forward
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