A crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The initial grade is 2.5% and the final grade is -4% The length of the curve is 950 ft. Determine the following, 1. Stationing of the high point, PVC, and PVT. 2. Elevation at station 212+00, PVC, high point, and PVT.

A sag vertical curve joins a -6% grade and +5% grades. If the PVI of the grades is at Station 355+50 and at an elevation of 156 ft., determine the station and elevation of the PVC, PVT, and the low point for a design speed of 60 mph. Sketch the curve and label the PVI, PVC, PVT and the low point with their stations and elevations. Note: You should check the stopping sight distance criterion and riding comfort design criteria, using the one that controls. 2.

A grade of -3.0% is followed by a grade of +2.1% which intersects at station 10+250 and elevation of 110 m. If the maximum change in grade per 20 m station is 0.20%, determine the following A. Length of parabolic curve that shall connect these two gradelines. B. Elevation of PC. C. Elevation of a point on the curve @ Sta.10+250.

Q6. To help improve the safety of at-grade intersection of two roads, the intersection is being redesigned so that the E-W road will pass underneath the N-S road. Currently the vertical alignment of the E-W road consists of a crest vertical curve joining a 4% upgrade to a 3% downgrade. The existing vertical curve is 138 m long, the PVC of this curve is at station 14+47, and the elevation of the PVC is 477 m. The centerline of the N-S road is at station 15+45. Your job is to find the shortest vertical curve that provides 6.0 m of clearance between the new E-W road and the N-S road.

I need the answer as soon as possible

A -1% grade meets a +3% grade at sta. 12+00 and elevation 520 ft. by a vertical curve of length 200 ft. Calculate the following: i. K and r ii. Station of PVC and PVT iii. Elevation of point at a distance, L/4, from PVC and PVT iv. station of turning point v. elevation of turning point vi. elevation of mid-point of the curve

Note : If you don't know the solution please leave it but don't give me wrong solution. A vertical curve joining entering grade of -4% with an exiting grade of - 7% begins at station 2+607 and is being designed with K value of 72. What is the station of the highest point on the curve . Code the station as the total distance from the origin, i.e., if the station is 1+100 code it as 1100.

Please correct answer

ASAP PLS

A 5.3% grade intersects a -1.9% grade at STA 5+180 at an elevation of 186m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the curve below PVI.