Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 29P
To determine
The elevation of the curve at station
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A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1%
b) determine the highest and the lowest points on this vertical curve by using the K-value.
1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve
connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at
station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC
and the PVI?
[Answer: PVI station: 110+50.3; PVI elevation: 930.6']
An equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- A vertical symmetrical sag curve has a descending grade of - 4.2% and an ascending grade of +3% intersecting at station 10 +020, whose elevation is 100 m. The two grade lines are connected by a 260 m vertical parabolic sag curve. (a) At what distance from the P.C. is the lowest point of the curve located in m? (b) What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades in m. (c) If a 1 m. diameter culvert is placed at the lowest point of the curve with the top of the culvert buried 0.60 m. below the subgrade, what will be the elevation of the invert of the culvert?arrow_forwardNote : If you don't know the solution please leave it but don't give me wrong solution. A vertical curve joining entering grade of -4% with an exiting grade of - 7% begins at station 2+607 and is being designed with K value of 72. What is the station of the highest point on the curve . Code the station as the total distance from the origin, i.e., if the station is 1+100 code it as 1100.arrow_forward4. An equal tangent (sag) vertical curve connects an initial grade of -3% and a final grade of +1% and is designed for 60 mph. The PVI is at station 250+50 and elevation 732 ft. What is the station and elevation of the lowest point on the curve?arrow_forward
- 1. A vertical parabolic summit curve was designed in order to have a clear sight distance of 120m. The grade lines intersect a Station 9 + 000 at elevation 160.50m. The curve was so designed such that when the height of the driver's eye to 1.50m above the pavement would just see an object whose height is 0.10m above the pavement. Determine the max. speed that a car could travel along this curve. The grade lines has an upward grade of 5% and a downward grade of -3%.arrow_forwardA vertical equal-tangent, 1000 ft long, connects an initial grade of -2.5% and a final grade of +2%. The PVC of the curve is located at station 95 + 00 and has an elevation of 850 ft. At which station is the PVI of the curve located? 80 + 00 83 + 75 O 90 + 00 O 95 + 00 O 100 + 00arrow_forwardA 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forward
- An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?arrow_forwardAn equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2arrow_forwardA -4% grade line meets another line of +3.2% grade at station 11+ 4O. If a 225-ft parabolic curve connects these grade lines, at what station is the lowest point along the curve located? Your answerarrow_forward
- A crest vertical curve connects a ?4.44% grade and a ?6.87% grade. The PVI is at station 43 ? 50.00 at an elevation of 1240.00 ft. The design speed is 30 mi/h.arrow_forwardA plus 2.8% grade elevation intersects a minus 5.1% grade at station 2 + 087.224 at an elevation of 194.280 m. Calculate the elevations at every 20-m station for a 150-m vertical curve.arrow_forwardA parabolic curve has a descending grade of -0.8% and an ascending grade of +0.4% that intersect at station 10 + 020 with an elevation of 240.600 m. If the maximum allowable rate of change of grade for this curve is 0.15% per 20 m stations, determine the following: A. The elevation at station 10 + 000 *Draw the figurearrow_forward
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