Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Chapter 3, Problem 56P
To determine
The station of the
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Students have asked these similar questions
A horizontal curve is being designed for a new four-lane roadway with 11-ft lanes. The PT
is located at station 1050+20, the design speed is 45 mph and maximum superelevation of
4%. If the central angle of the curve is 30 degrees, what is the radius of the curve and
location of the PC and PI?
Design a vertical curve (i.e., Determine length of the curve as well as station and elevation of the
vertical curve's PVC and PVT) with the given PVI (station and elevation given the figure below)
to go through a future intersection location at the point at which the vertical curve is flat. Report
the vertical curve's design speed to the nearest 5 miles per hour.
PVC
Future Intersection
Station = 100+00
G1 = -2.6%
PVT
PVI
G2 = 1.0%
Station = 99+00
Elevation = 228 ft
%3|
The angle between a 5-m full station of a certain curve is 10°. The curve has 7 intermediate stations between P.C. (10 + 300m) and P.T. After laying out the curve, it was found out that the P.T. falls in a property lot and it should be moved in a way that the P.T. will be free from crossing the lot. Compute all the necessary elements of the old curve and new relocated curve.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- An equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.arrow_forward4. Horizontal Curve: P.C. 12+00.00 P.I T 4= 30° P.T. This highway has a 60 mph speed limit requiring a minimum radius for any curve to be 1500'. If the curve is to begin at Station 12+00.00 and is to have a radius of 1610.10', how long will the curve be? At what station will the PI and PT go? How long will E be? (Answers should all be in hundredths.)arrow_forward2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade lines intersect at Sta 9+000 at elev 160.50. The curve was design such that when the height of the drivers eye is 1.50 m above the payment it would just see an object whose height is 0.10 m above the pavement. Determine the max speed that a car could travel grade of 5% and a downgrade of -3%.arrow_forward
- A section of a two-lane, two-way highway (2 @ 3.5 m) is to be designed with a circular curve. Sta. Pl at 200 + 100.000 Design speed = 60 kph Intersection angle = 40 degrees Rate of change of acceleration: 0.5 m/sec2arrow_forwardA horizontal curve is being designed for a new two-lane highway (3.6-m lanes). The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of 0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT.arrow_forwardA horizontal curve on a four-lane (two lane in each direction) highway (11-ft lanes) has PC at station 124+30 and PT at station 130 + 15. The central angle is 40 degrees, the superelevation is 0.12, and 23.5 ft is cleared (for sight distance) from the inside edge of the innermost lane. Determine a maximum safe speed (assuming current design standards) to the nearest 5 mi/h.arrow_forward
- The design speed for a two-lane highway (lane width=12 ft.) is 60 mph. The localjurisdiction governs 8% superelevation. The central angel of the curve is 40 degrees. The PI station is at 452+50.What is the curve radius to the travel path (R)? What is the curve radius (R)? What is the curve length (L)? What isthe station of PC? What is the station of PT? What is the SSD? How many feet must be cleared from the lane'sshoulder edge to provide adequate stopping sight distance?arrow_forwardA simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the length (ft) of roadway to the first full station on the curve? The first full station occurs at 4+00arrow_forwardA compound curve is joined by two simple curves adjacent to each other, the first one having a radius of 200m and a central angle of 42˚ while that of the second curve has a radius of 200m and central angle of 30˚. Compute the total length of curve from PC to PT of the compound curve.arrow_forward
- A simple curve having a degree of curve equal to 40030’ has a central angle of 50050’. It is required to replace the simple curve with another circular curve y connecting a transition curve (spiral) at each ends by maintaining the radius of the old curve and the center of the new central curve is moved away by 5 m. from the intersection point. Determine the central angle of the circular curve Compute the tangent distance Ts of the spiral curve What is the maximum velocity that a car could pass thru curve without skidding?arrow_forwardA simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the intermediate chord length (ft) (i.e. the straight line distance between two sequential full stations)? Response Feedback: 8 C =2Rsin- D 2arrow_forwardAn equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20arrow_forward
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