Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Chapter 3, Problem 6P
To determine
The elevation difference between the
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A vertical symmetrical sag curve has a descending grade of - 4.2% and an ascending grade of +3%
intersecting at station 10 +020, whose elevation is 100 m. The two grade lines are connected by a 260
m vertical parabolic sag curve. (a) At what distance from the P.C. is the lowest point of the curve
located in m? (b) What is the vertical offset of the parabolic curve to the point of intersection of the
tangent grades in m. (c) If a 1 m. diameter culvert is placed at the lowest point of the curve with the top
of the culvert buried 0.60 m. below the subgrade, what will be the elevation of the invert of the culvert?
4. An equal tangent (sag) vertical curve connects an initial grade of -3% and a final
grade of +1% and is designed for 60 mph. The PVI is at station 250+50 and
elevation 732 ft. What is the station and elevation of the lowest point on the curve?
A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1%
b) determine the highest and the lowest points on this vertical curve by using the K-value.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- 1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']arrow_forwardAn equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?arrow_forwardA crest vertical curve connects a +4.44 % grade and a -6.87 % grade. The PVI is located at station 43 + 50.00 at an elevation of 1,240.00 feet. The design speed is 30 mph. Determine the following: The length of the vertical curve using the AASHTO method (“K” factors) (1/8 pts.) The station of the PVC/BVC (1/8 pts.) The station of the PVT/EVC (1/8 pts.) The station of the high point (1/8 pts.) The elevation of the PVC/BVC (1/8 pts.) The elevation of the PVT/EVC (1/8 pts.) The elevation of the high point (1/8 pts.) The elevation of station 44+ 23.23 (1/8 pts.)arrow_forward
- A 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forwardA vertical parabolic curve is to be used under a grade-separation structure. The curve is 250 m long and the minus grade of 3.8 percent intersects the plus grade of 5.4 percent at station of 0+120.424. Calculate the low point of the curve if the intersection at station 0+120.424 is at elevation 230.085 m.arrow_forwardA Vertical parabolic curve of length 180m has the following specifications. The point of interaction of grade lines is at station 4 + 316 and its elevation is 38m. The backwards tangent has a grade of -2.2% and the grade of the forward tangent is +3%. Under this conditions determine the following: (a) Station and elevation of PC & PT (b) Station of the lowest point of the curve (c) Elevation of the lowest point of the curvearrow_forward
- 2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00 with its elevation of 1,005 ft. Please determine following. a. PVC station b. PVC elevation C. PVT station d. PVT elevation e. The station where the highest elevation is located f. The highest elevation on the road g. The stations where the road elevation is 995 feet. Crest Vertical Curve PVI = 110+00 sta Design Speed: 70 mph Yev= 1,005' PVI Highest elevation PVI 2.5% -2.0% PVC PVT Elevation = 995 ft L=1,115 ftarrow_forwardA crest vertical curve connects a ?4.44% grade and a ?6.87% grade. The PVI is at station 43 ? 50.00 at an elevation of 1240.00 ft. The design speed is 30 mi/h.arrow_forwardA horizontal curve on Texas Highway 83 (Tx83) comprises of a two-lane rural highway with a lane width of 12 ft. and superelevation of 8%. The posted speed limit is 50 mph. along a 0.5-mile section of highway, both a horizontal and vertical curve exists. The vertical curve has an initial grade of -2.00% and a final grade of +4.00%. The PVI is at station 156+40. A driver traveling eastbound strikes a stationary roadway object. The daytime crash results in a fatality and is being investigated for safe design speed. Evaluate and comment on the roadway design.arrow_forward
- 2. (Sag Vertical Curve) An existing highway-railway at-grade crossing is being redesigned as grade separated to improve traffic operations. The railway must remain at the same elevation. The highway is being reconstructed to travel under the railway. The underpass will be a sag curve that has an initial grade of -2% and a final grade of 2%. The PVI of the sag curve will be centered under the railway (a symmetrical alignment). The sag curve design speed is 45 mi/h. How many feet below the railway should the curve PVI be located?arrow_forwardQuestion 3 An equal-tangent vertical curve is to be constructed between grades of -2 percent and +1 percent. The PVI is at station 110 + 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve.arrow_forwardAn equal tangent vertical curve is to be constructed between grades of -2.0% and +1.0 %. The PVI is at station 11 +000.00 and at elevation 420 m. Due a street crossing the roadway, the elevation of the roadway at station 11 +071.00 must be at 421.5 m. Design the curve. (what is the curve length?)arrow_forward
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