Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 24P
To determine
The station and elevation of the lowest point on the curve.
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A vertical symmetrical sag curve has a descending grade of - 4.2% and an ascending grade of +3%
intersecting at station 10 +020, whose elevation is 100 m. The two grade lines are connected by a 260
m vertical parabolic sag curve. (a) At what distance from the P.C. is the lowest point of the curve
located in m? (b) What is the vertical offset of the parabolic curve to the point of intersection of the
tangent grades in m. (c) If a 1 m. diameter culvert is placed at the lowest point of the curve with the top
of the culvert buried 0.60 m. below the subgrade, what will be the elevation of the invert of the culvert?
4. An equal tangent (sag) vertical curve connects an initial grade of -3% and a final
grade of +1% and is designed for 60 mph. The PVI is at station 250+50 and
elevation 732 ft. What is the station and elevation of the lowest point on the curve?
1. If PVI at sta 5+650 has an elevation of 122.45 m what is the elevation of the grade tangent at station 5+684? Given grade is +3%.
2. If a 26-degree curve consists of a 14 degree simple curve, what is the angle of the transition curves?
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- 1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']arrow_forwardA 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1% b) determine the highest and the lowest points on this vertical curve by using the K-value.arrow_forwardA Vertical parabolic curve of length 180m has the following specifications. The point of interaction of grade lines is at station 4 + 316 and its elevation is 38m. The backwards tangent has a grade of -2.2% and the grade of the forward tangent is +3%. Under this conditions determine the following: (a) Station and elevation of PC & PT (b) Station of the lowest point of the curve (c) Elevation of the lowest point of the curvearrow_forward
- A vertical parabolic curve is to be used under a grade-separation structure. The curve is 250 m long and the minus grade of 3.8 percent intersects the plus grade of 5.4 percent at station of 0+120.424. Calculate the low point of the curve if the intersection at station 0+120.424 is at elevation 230.085 m.arrow_forwardA symmetrical parabolic summit curve connects two grades of +4.9% and -3.2%. It is to pass through a point "D" on the curve at station 25 + 180m . If the stationing of the grade intersection is 25 + 145m and the stationing of PVC is 24 + 979m determine the following: Length of the parabolic curve Stationing of the highest point. Difference in elevation between PVC and PVI Difference in elevation between PVC and point Darrow_forwardA vertical equal-tangent, 1000 ft long, connects an initial grade of -2.5% and a final grade of +2%. The PVC of the curve is located at station 95 + 00 and has an elevation of 850 ft. At which station is the PVI of the curve located? 80 + 00 83 + 75 O 90 + 00 O 95 + 00 O 100 + 00arrow_forward
- A crest vertical curve connects a ?4.44% grade and a ?6.87% grade. The PVI is at station 43 ? 50.00 at an elevation of 1240.00 ft. The design speed is 30 mi/h.arrow_forwardA +3.00% grade intersects a -2.40% at station 46+70.00 and elevation 853.48 ft. A 400.00 ft curve will be used to connect the two grades. Compute Station and elevation for the curve's endpoints.arrow_forwardA symmetrical sag curve has a descending grade of -4.2% and an ascending grade of +3.6% intersecting at Station 10+130, whose elevation is 121.55 m. The rate of change of grade is restricted to 0.60%. a. What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades? b. At what distance from PC is the lowest point of the curve located?arrow_forward
- A 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forwardA symmetrical sag curve has a descending grade of -4.2% and an ascending grade of +3% intersecting at station 10 + 200, whose elevation is 100 m. The rate of change of grade is restricted to 0.55385% per station. a. What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades? b. At what distance from PC is the lowest point of the curve located? c. If a 1-m diameter culvert is placed at the lowest point of the curve with the top of the culvert buried 0.60 m below the subgrade, what will be the elevation of the invert of the culvert?arrow_forwardA symmetrical parabolic summit curve is to connect two roads with grades of +4% and -2.5% that meet at station 18 + 420 at an elevation of 80.522 m. This curve is to pass through a point P at station 18 + 400 at an elevation of 79.267 m. Determine the elevation at the highest point on the curve.arrow_forward
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