Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 21P
To determine
The design speed of the curve.
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An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?
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A vertical curve joining entering grade of -4% with an exiting grade of - 7% begins at station 2+607 and is being designed with K value of 72. What is the station of the highest point on the curve . Code the station as the total distance from the origin, i.e., if the station is 1+100 code it as 1100.
A +3.00% grade intersects a -2.40% at station 46+70.00 and elevation 853.48 ft. A 400.00 ft curve will be used to connect the two grades. Compute Station and elevation for the curve's endpoints.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- 1. A vertical parabolic summit curve was designed in order to have a clear sight distance of 120m. The grade lines intersect a Station 9 + 000 at elevation 160.50m. The curve was so designed such that when the height of the driver's eye to 1.50m above the pavement would just see an object whose height is 0.10m above the pavement. Determine the max. speed that a car could travel along this curve. The grade lines has an upward grade of 5% and a downward grade of -3%.arrow_forward2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade lines intersect at Sta 9+000 at elev 160.50. The curve was design such that when the height of the drivers eye is 1.50 m above the payment it would just see an object whose height is 0.10 m above the pavement. Determine the max speed that a car could travel grade of 5% and a downgrade of -3%.arrow_forwardAn equal-tangent sag vertical curve is designed for 45 mi/h. The low point is 237 ft from the PVC at station 112 + 37 and the final offset at the PVT is 19.355 ft. If the PVC is at station 110 + 00, what is the elevation difference between the PVT and a point on the curve at station 111 + 00?arrow_forward
- 1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']arrow_forwardA compound curve that starts at stationing 4+321 consists of 2 simple curves. The 1st curve has a radius of 300 m and an angle of intersection of 45°. The 2nd curve has a radius of 500 m and an angle of intersection of 35°. The common tangent is parallel to the long chord of the compound curve. Compute the stationing of V, V1, V2, PCC and full stations, and the length of the long chord.arrow_forwardA +4% grade line intersects a -2 % grade line at station 6+800, where the elevation is 642.40 m. as shown in the figure. Determine the elevations of 100-m stations for this 1,000-m unequal tangent curve. Determine the station and curve elevation of PC, PT, D, E and CVC where in CVC is compound vertical curve.arrow_forward
- A simple curve having a degree of curve equal to 3.8-degree has central angle of 55.5-degree. It is required to replace the simple curve to another circular curve by connecting a transition curve at each and by maintaining the radius of the old curve and the center of the new central curve is moved away by 6.8m from the intersection point. If the stationing at Pl is at 4 + 657.89, determine the stationing of the start of central curve.arrow_forwardGiven an equal tangent vertical curve, in feet, with the following known information: STA A (Beginning of Curve) = 17+00 Elevation A = 95.00 feet G1 = +4.00% and G2 = -2.00% The vertical curve must begin at the fixed VPC (station A) and pass through station 21+00 at the elevation of 99.00 feet, the new calculated design length of the vertical curve, in feet, is:arrow_forwardA 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1% b) determine the highest and the lowest points on this vertical curve by using the K-value.arrow_forward
- 5. A 600 ft equal tangent vertical curve has the PVC at station 170+00 and elevation 1000 ft. The initial grade is -3.5% and the final grade is +0.5%. Determine the stationing and elevation of the PVI, the PVT, and the lowest point on the curve.arrow_forwardA 3.5% grade passing at station 49+45.00 at an elevation of 174.83 ft meets a -5.5% grade passing at station 49+55.00 at an elevation of 174.73 ft. Determine the station and elevation of the point of intersection of the two grades as well as the length of the curve, L, if the highest point on the curve must lie at station 48+61.11arrow_forward12. Find the minimum length of curve for the following scenarios. Entry Grade Exit Grade Design Speed Reaction Time A 3% 8% 45 mi/hr 2.5 s В -4% 2% 65 mi/hr 2.5 s 0 % -3% 70 mi/hr 2.5 sarrow_forward
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