Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 3, Problem 20P
Summary Introduction
To determine: The
Introduction: Females possessing one X-linked recessive mutation are considered carriers. They will generally not manifest clinical symptoms of the disorder. However, differences in X chromosome inactivation can lead to varying degrees of clinical expression in carrier females since some cells will express one X allele, and some will express the other.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
In mice, dwarfism is caused by an X-linked recessive allele, and pink coat is caused by an autosomal dominantallele (coats are normally brownish). If a dwarf femalefrom a pure line is crossed with a pink male from a pureline, what will be the phenotypic ratios in the F1 and F2 ineach sex? (Invent and define your own gene symbols.)
: In Drosophila, yellow body is due to an X-linked gene that is recessive to the gene forgray body.(a) A homozygous gray female is crossed with a yellow male. The F1 are intercrossed toproduce F2. Give the genotypes and phenotypes, along with the expected proportions, of theF1 and F2 progeny.(b) A yellow female is crossed with a gray male. The F1 are intercrossed to produce the F2.Give the genotypes and phenotypes, along with the expected proportions, of the F1 and F2progeny.(c) A yellow female is crossed with a gray male. The F1 females are backcrossed with graymales. Give the genotypes and phenotypes, along with the expected proportions, of the F2progeny.(d) If the F2 flies in part b mate randomly, what are the expected phenotypic proportions offlies in the F3??
IN DROSOPHILA, AN X-LINKED
RECESSIVE MUTATION, Xm CAUSES
MINIATURE WINGS. LIST
THE F₂ PHENOTYPIC RATIOS IF:
A MINIATURE-WINGED FEMALE IS
CROSSED WITH A NORMAL MALE AND
A MINIATURE-WINGED MALE IS
●
●
CROSSED WITH A NORMAL FEMALE.
WHAT WOULD THE PHENOTYPIC RATIO
FROM (A) BE IF THE MINIATURE-
WINGED GENE WERE AUTOSOMAL?
ASSUME IN ALL CASES THAT THE P1
INDIVIDUALS ARE TRUE-BREEDING.
Chapter 3 Solutions
Introduction to Genetic Analysis
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13P
Ch. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 31.1PCh. 3 - Prob. 31.2PCh. 3 - Prob. 31.3PCh. 3 - Prob. 31.4PCh. 3 - Prob. 31.5PCh. 3 - Prob. 31.6PCh. 3 - Prob. 31.7PCh. 3 - Prob. 31.8PCh. 3 - Prob. 31.9PCh. 3 - Prob. 31.10PCh. 3 - Prob. 31.11PCh. 3 - Prob. 31.12PCh. 3 - Prob. 31.13PCh. 3 - Prob. 31.14PCh. 3 - Prob. 31.15PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 57P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Human sex chromosomes are XX for females and XY for males. a. With respect to an X-linked gene, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele? c. If a female is heterozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele?arrow_forwardHemophilia is caused by an X-linked recessive mutation in humans. If a man whose paternal uncle (father's brother) was a hemophiliac marries a woman whose brother is also a hemophiliac, what is the probability that their first child will have hemophilia? (Assume that no other cases of hemophilia exist in the pedigree.) 1/3 0 1/8 0 1/4 1/2arrow_forwardIn beetles, an X-linked gene determines body size, with normal size (M)completely dominant to miniature body size (m). Body color is determined by an autosomal gene with two alleles, where B is incompletely dominant to b such that BB beetles are black, Bb beetles are brown and bb beetles are yellow. Male beetles are heterogametic (XY). The following cross is performed: brown, miniature sized body female X brown, normal sized body male Based on this information, which of the following statements is FALSE? Select 3 correct answer(s) Question 3 options: A) 1/8 of the female progeny will have yellow miniature bodies. B) All of the male progeny will have miniature bodies. C) 1/4 of the total progeny will be black. D) 1/4 of the male progeny will have yellow miniature bodies. E) All of the female progeny will have miniature bodies.…arrow_forward
- You have a Drosophila line that is homozygous for autosomal recessive alleles a, b, and c, linked in that order. You cross females of this line with males homozygous for the corresponding wild-type alleles. You then cross the F1 heterozygous males with their heterozygous sisters. You obtain the following F2 phenotypes (where letters denote recessive phenotypes and pluses denote wild-type phenotypes): 1364 + + +, 365 a b c, 87 a b +, 84 + + c, 47 a + +, 44 + b c, 5 a + c, and 4 + b +.a. What is the recombinant frequency between a and b? Between b and c? (Remember, there is no crossing over in Drosophila males.)b. What is the coefficient of coincidence?arrow_forwardIn Drosophila, the fruit fly, white eyes are determined by a recessive X-linked gene and the wild-type or normal brick-red eyes are due to its dominant allele. Use symbols of the following types: XrY = a white-eyed male; XRXR = a homozygous normal red female Show the genotypes and list the phenotypes of the F1 offspring Now, cross the F1 offspring. Show the genotypes and list the phenotypes of the F2 offspring.arrow_forwardA recessive allele causes Drosophila to have white eyes instead of wild-type eyes. This eye colourgene is known to be X-linked. In a cross between homozygous wild-type females and white-eyedmales, all F1 progeny have wild-type eyes. What ratio of wild-type to white-eyed progeny can be expected in each sex if F1 females arecrossed to males of the same genotype as their father?a. Males – 1 : 0; females – 1 : 0b. Males – 1 : 1; females – 1 : 0c. Males – 0 : 1; females – 1 : 1d. Males – 1 : 1; females – 1 : 1arrow_forward
- Color blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?arrow_forwardIn the fruit fly, Drosophila melanogaster, eye color is affected by an X-linked gene with two alleles, w for white eyes and w+ for the wild-type red eyes. White eyes is a recessive trait. Females from a true-breeding strain with wild type eyes are crossed with males that have white eyes. a. What will be the phenotypes in the F1 generation? b. What will be the phenotypes in the F2 generation and in what portions are they expected?arrow_forwardIn goats, development of the beard is due to a recessive gene. The following cross involving true-breeding goats was made and car- ried to the F2 generation: P;: bearded female x beardless male F1: all bearded males and beardless females ´1/8 beardless males | 3/8 bearded males 3/8 beardless females 1/8 bearded females F; × F, Offer an explanation for the inheritance and expression of this trait, diagramming the cross. Propose one or more crosses to test your hypothesis.arrow_forward
- In the common daisy, genes A and B control flower color. Both genes have a dominant allele (A or B) and a recessive allele (a or b). At least one copy of each dominant allele is required for flowers to be colorful instead of white. (Explain and Justify your answers) 21.1) Predict the genotypes and phenotypes of the F1 progeny of a cross between two white-flowered plants, one homozygous AA and the other homozygous BB. A) AA bb, white B) aa BB, white C) Aa Bb, colorful D) Aa Bb, white E) aa bb, colorful 21.2) Predict the phenotypic ratio of the F2 progeny of a cross between two white-flowered plants, one homozygous AA and the other homozygous BB. A) 3 colorful : 1 white B) 9 colorful : 7 white C) 9 white : 7 colorful D) 15 white : 1 colorful E) 15 colorful : 1 white 21.3) The inheritance pattern of daisy flower color provides an example of what type of gene interaction? A) additivity…arrow_forwardRed-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___arrow_forwardA mutant sex-linked trait called “notched” (N) is deadly in Drosophila when homozygous in females. Males who have a single N allele will also die. The heterozygous condition (Nn) causes small notches on the wing. The normal condition in both male and females is represented by the allele n. a) Indicate the phenotypes of the F1 generation from the following cross: XNXn x XnY b) Explain why dead females are never found in the F1 generation no matter which parents are crossed. c) Explain why the mating of female XNXn and a male XNy is unlikely.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Animal Communication | Ecology & Environment | Biology | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=LsMbn3b1Bis;License: Standard Youtube License