Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
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Chapter 3, Problem 12P
a.
Summary Introduction
To determine: The
Introduction: The phenotypic ratio apply to the relative number of offspring displaying a particular trait or combination of characters.
b.
Summary Introduction
To determine: The genotypic ratio that is produced from selfing.
Introduction: The genotypic ratio designates the number of times a genotype would occur in the offspring after a test cross.
c.
Summary Introduction
To determine: The phenotypic ratio that is produced from testcross.
Introduction: It can be identified by doing a test cross and finding the frequency of a trait or trait combinations that will be expressed based on the genotypes of the progeny.
d.
Summary Introduction
To determine: The genotypic ratio that is produced from test crossing.
Introduction: The genotypic ratio shows the number of times a trait of an organism will occur in the offspring when genes for specific traits are crossed.
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shows the results of a dihybrid cross involving seed shape and seed color. a. What proportion of the round and yellow F2 progeny from this cross is homozygous at both loci? b. What proportion of the round and yellow F2 progeny from this cross is homozygous at least at one locus?
A test cross between a plant of genotype PpSs and the tester white plant with wrinkled seed coat (ppss) gives the following numbers of progeny in four phenotypic types. 14:87:83:16 (purple flower + smooth seed coat: purple flower + wrinkled seed coat: white flower + smooth seed coat: white flower + wrinkled seed coat).
a. What is the expected ratio of progeny phenotypes assuming independent assortment of alleles?
b. Explain how ratios of progeny show that the two genes are linked.
c. How many map units separate the purple and smooth genes? Show your calculations.
d. What is the “parental” genotype of the heterozygous parent? (i.e. Which alleles of the P and S loci are present on each of the two chromosomes of the doubly heterozygous parent of this test cross?)
In peas, tall is dominant over dwarf. If a plant homozygous for tall is crossed with one homozygous for dwarf :
a. What will be the genotype(s) (use the initial of your last name) and phenotype (s) of the F1 plants?
b. If the F1 is grown the next season, predict the possible genotypes and phenotypes.
c. If you cross the F1 to the tall parent, what phenotype will result of the cross? What will be the ratio of the genotype?
d. If you cross the F1 to the short parent, what phenotype will result of the cross? What will be the ratio of the genotype?
Chapter 3 Solutions
Introduction to Genetic Analysis
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13P
Ch. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 31.1PCh. 3 - Prob. 31.2PCh. 3 - Prob. 31.3PCh. 3 - Prob. 31.4PCh. 3 - Prob. 31.5PCh. 3 - Prob. 31.6PCh. 3 - Prob. 31.7PCh. 3 - Prob. 31.8PCh. 3 - Prob. 31.9PCh. 3 - Prob. 31.10PCh. 3 - Prob. 31.11PCh. 3 - Prob. 31.12PCh. 3 - Prob. 31.13PCh. 3 - Prob. 31.14PCh. 3 - Prob. 31.15PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 57P
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- For the cross: PpAa x PpAa P = purple flowers (Dominant) p = white flowers A = axial flowers (Dominant) a = terminal flowers a. What are the possible gamete classes that can form from these parents? b. What are the expected offspring genotype classes and ratios/proportions/fractions which will result from the cross? c. What are the expected offspring phenotype classes and ratios/proportions/fractions which will result from the cross? 2. Predict ratios/proportions/fractions of genotypes and phenotypes of the following crosses. T = tall stem t = dwarf stem P = purple flowers p = white flowers G = green pods g = yellow pods A = axial flowers a = terminal flowers R = round peas r = wrinkled seeds A. ttPp x Ttpp B. GgRr x ggRr C. PpGg x ppggarrow_forwardshows the results of a cross between a tall pea plant and a short pea plant. a. What phenotypes and proportions will be produced if a tall F1 plant is backcrossed to the short parent? b. What phenotypes and proportions will be produced if a tall F1 plant is backcrossed to the tall parent?arrow_forwardGive typed explanation : In peas, tall (T) is dominant to short (t). A homozygous tall plant is crossed with a short plant. The F1 are self-fertilized to produce the F2. Both tall and short plants appear in the F2. If the tall F2 are self-fertilized, what types of offspring and proportions will be produced?arrow_forward
- Consider the cross RrmmTT x RRMmTt. Assume the three gene pairs are independently segregating. a. Derive the gametic ratio of the second parent using the branching method.b. Derive the genotypic ratio for the offspring from each cross using the branching method. Showcomplete solutions.c. What is the probability that an offspring from this cross will be heterozygous for all gene pairs?arrow_forwarda. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…arrow_forwardIn sweet peas, the synthesis of purple anthocyanin pigment in the petals is controlled by two genes, B and D. What petal color would you expect in a pure breeding plant unable to catalyze the first reaction? Indicate the genotype and phenotype. 2. What petal color would you expect in a pure breeding plant unable to catalyze the second reaction? Indicate the genotype and phenotype. 3. If plants 1 and 2 are crossed, what petal color would the F1 plants have? Indicate the genotype and phenotype. 4. What ratio of purple : blue : white plants would you expect in the F2? Indicate the genotypes, phenotypes, and the F2 phenotypic ratio.arrow_forward
- Tallness (T) in snapdragons is dominant to dwarfness (t), while red (R) flower color is dominant to white (r). The heterozygous condition results in pink (Rr) flower color. A dwarf, red snapdragon is crossed with a plant homozygous for tallness and white flowers. What are the genotype and phenotype of the F1 individuals? Group of answer choices A. TtRr–tall and red B. TtRr–tall and pink C. ttrr–dwarf and white D. TTRR–tall and red E. ttRr–dwarf and pinkarrow_forwardTwo pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64arrow_forwardREad and analyzed the following genetic problem. Show complete solution (Genotypes of P, Punnet Square and GR,PR). 1. In the garden peas, green pod color is dominant over yellow pods. Also, round seed shape is dominant over wrinkled seed. Cross fertilization was done between a pea that is homozygous dominant for pod color with heterozygous round shape and another pea that is heterozygous for both pod color and seed shape. Determine the genotypic and phenotypic ratio of teh offspring.arrow_forward
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