Interpretation: To describe the three given solids A, B, and C.
Concept Introduction: A salt is a chemical compound that consists of two ions where one is positively charged and the other is negatively charged.
Answer to Problem 88A
Salt A is potassium nitrate, salt B is barium sulfate and salt C is fructose.
Explanation of Solution
The three solids are given that can be fructose, barium sulfate, and potassium nitrate. These three products need to be identified by means of
It is given that salt A dissolves in water. When potassium nitrate reacts with water it dissociates into potassium and nitrate ions. These ions are therefore useful in conducting
Therefore, salt A is potassium nitrate.
It is given that salt B is insoluble in water. When barium sulfate reacts with water it forms a precipitate which means it cannot be dissolved in water.
Therefore, salt B is barium sulfate.
It is given that salt C dissolves in water but does not conduct electricity. Fructose is a sugar i.e., a carbohydrate. Sugar can be easily dissolved in water. The solution so formed cannot be used for conducting an electric current.
Therefore, salt C is fructose.
Thus, salt A is potassium nitrate, salt B is barium sulfate and salt C is fructose.
Chapter 15 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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